Chapter 3: Problem 10
Find the \(x\) - and \(y\) -intercepts. $$ -x+y=0 $$
Short Answer
Expert verified
x-intercept: (0, 0); y-intercept: (0, 0).
Step by step solution
01
Identify equation type
The given equation is a linear equation in the standard form. An example of the standard form of a linear equation is \(ax + by = c\). In this equation, \(a = -1\), \(b = 1\), and \(c = 0\).
02
Find the x-intercept
To find the x-intercept, set \(y = 0\) in the equation and solve for \(x\). Substitute \(y = 0\) into the equation:\[-x + 0 = 0\]Simplify and solve for \(x\):\[-x = 0\]\[x = 0\]So, the x-intercept is \((0, 0)\).
03
Find the y-intercept
To find the y-intercept, set \(x = 0\) in the equation and solve for \(y\). Substitute \(x = 0\) into the equation:\[-0 + y = 0\]Simplify and solve for \(y\):\[y = 0\]So, the y-intercept is \((0, 0)\).
04
Conclusion
Both the x-intercept and y-intercept are at the origin, therefore the graph of the equation passes through the origin.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the x-intercept
The x-intercept of a line is the point where the line crosses the x-axis on a graph. At this point, the y-coordinate is always zero because the line has not yet moved up or down. To find the x-intercept in a given linear equation, you need to substitute zero for the y variable.
\[\text{Example:} -x+y=0\]
\[\text{Example:} -x+y=0\]
- Set \(y = 0\) in the equation.
- The equation becomes \(-x + 0 = 0\).
- Simplify to find \(x\).
- In this case, \(-x = 0\) leads to \(x = 0\).
Understanding the y-intercept
The y-intercept of a line is where it crosses the y-axis. For this to occur, the x-coordinate must always be zero, since it's not moving left or right at that point. To find the y-intercept, set x equal to zero in your linear equation.
\[\text{Example:} -x+y=0\]
\[\text{Example:} -x+y=0\]
- Set \(x = 0\) in the equation.
- The equation simplifies to \(-0 + y = 0\) or simply \(y = 0\).
Equation Solving Techniques
Solving equations involves finding the values for the variables that make the equation true. When dealing with linear equations like \(-x + y = 0\), it's all about finding values for x and y. What makes this equation special is the symmetry in its intercepts.
For seasoned equation solving:
For seasoned equation solving:
- Identify if it's a standard form linear equation: \(ax + by = c\).
- Notice the coefficients: here, \(a = -1\), \(b = 1\), \(c = 0\).
- Focus on isolating the variable, by getting it alone on one side of the equation.
- Set y and then x to zero, respectively, and solve for the other variable.
- Recognize that both intercepts are at the origin \((0, 0)\), once substituted and simplified.