Chapter 2: Problem 72
Solve and graph the solution set. In addition, present the solution set in interval notation. $$ -5<2(x-1)-3(x+2)<5 $$
Short Answer
Expert verified
The solution set is \((-13, -3)\) and can be graphed with open circles on a number line.
Step by step solution
01
Expand and Simplify the Inequality
We start by expanding both sides of the compound inequality:\[-5 < 2(x-1) - 3(x+2) < 5\]Distribute the multiplication across the terms:\[-5 < (2x - 2) - (3x + 6) < 5\]Simplify by combining like terms:\[-5 < 2x - 2 - 3x - 6 < 5\]This leads to:\[-5 < -x - 8 < 5\].
02
Isolate the Variable
Now, isolate the variable \(x\) in the middle by first adding 8 to each part of the inequality:\[-5 + 8 < -x - 8 + 8 < 5 + 8\]This simplifies to:\[3 < -x < 13\].
03
Solve for Positive x
To solve for \(x\), multiply all parts of the inequality by \(-1\). Remember to reverse the inequality signs:\[-3 > x > -13\].This can be rewritten as:\[-13 < x < -3\].
04
Write the Solution in Interval Notation
The solution \(-13 < x < -3\) in interval notation is:\((-13, -3)\).
05
Graph the Solution on a Number Line
To graph \((-13, -3)\), draw a number line and indicate open circles at \(-13\) and \(-3\), with a line connecting them, indicating all numbers in between are part of the solution. No point at either \(-13\) or \(-3\), as these are not included in the solution set.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Compound Inequality
A compound inequality involves two separate inequalities joined by either "and" or "or". In our example, the compound inequality is \[-5 < 2(x-1) - 3(x+2) < 5\] This combines two inequalities in one statement. The solution must satisfy both individual inequalities simultaneously. In other words, a number is a solution only if it works for both inequalities at the same time. This is different from a simple inequality, which contains only one comparison to deal with.
- "And" implies overlap - the solutions are in the region where both inequalities are true.
- "Or" implies union - solutions are valid if they satisfy at least one of the inequalities.
Interval Notation
Interval notation is a concise way to express the solution to an inequality. In this case, after solving the inequality, we got: \[-13 < x < -3\] This is expressed as \((-13, -3)\) in interval notation. The round brackets indicate that -13 and -3 are not included in the solution (known as open intervals).
- Round brackets \(( )\) signify numbers that are not part of the solution.
- Square brackets \([ ]\) mean a number is included in the solution.
Number Line Graphing
Graphing solutions on a number line is a visual way to represent the range of numbers that satisfy an inequality. For \((-13, -3)\), we depict this interval with open circles at -13 and -3, signaling these points are not included in the solution. Draw a line connecting these points to show that all numbers between -13 and -3 are part of the solution set. This graphical representation helps visualize the extent and nature of solutions:
- Open circles indicate that endpoints are not included in the solution.
- A connected line shows all numbers within the interval are valid solutions.
Variable Isolation
Isolating the variable is a critical step in solving inequalities. The goal is to have the variable, in this case, \(x\), alone in the center of the inequality. We started with the expression: \[-5 < -x - 8 < 5\]. We can isolate \(x\) by executing actions like adding, subtracting, multiplying, or dividing across every part of the inequality. Crucially, remember to reverse the inequality symbol when multiplying or dividing by a negative number. Here’s how we did it:
- Add 8 to each segment, moving towards isolating \(-x\).
- Multiply through by -1, flipping inequality signs, to solve for positive \(x\).