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91Ó°ÊÓ

Solve and graph the solution set. In addition, present the solution set in interval notation. $$ -4 \leq-13(3 x+12)<4 $$

Short Answer

Expert verified
The solution set is \((-\frac{160}{39}, -\frac{152}{39}]\), in interval notation: \((-4.10, -3.90]\).

Step by step solution

01

Break Down the Double Inequality

The given inequality is \[-4 \leq -13(3x+12) < 4\].This means you have two inequalities that you need to solve separately: 1. \(-4 \leq -13(3x+12)\)2. \(-13(3x+12) < 4\).
02

Solve the First Inequality

Solve \(-4 \leq -13(3x+12)\).First, distribute the \(-13\) into the parenthesis:\(-4 \leq -39x - 156\).Add 156 to both sides:\(152 \leq -39x\).Divide both sides by \(-39\), remembering to reverse the inequality:\(- \frac{152}{39} \geq x\).Approximate \(- \frac{152}{39} \approx -3.90\).
03

Solve the Second Inequality

Now solve \(-13(3x+12) < 4\).Distribute the \(-13\) into the parenthesis:\(-39x - 156 < 4\).Add 156 to both sides:\(-39x < 160\).Divide both sides by \(-39\), remembering to reverse the inequality:\(x > -\frac{160}{39}\).Approximate \(-\frac{160}{39} \approx -4.10\).
04

Combine the Inequality Solutions

Combine the results from Step 2 and Step 3: \(-\frac{160}{39} < x \leq -\frac{152}{39}\).This represents the solution set in inequality notation.
05

Express Solution in Interval Notation

The solution set can be expressed as an interval by using the values found:\((-\frac{160}{39}, -\frac{152}{39}]\).And approximately:\((-4.10, -3.90]\).
06

Graph the Solution

To graph, plot on a number line:- Draw an open circle at approximately \(-4.10\) to indicate that it is not included in the set.- Draw a closed circle at approximately \(-3.90\) to indicate that it is included in the set.- Shade the region between the two points to represent all the numbers that satisfy the inequality.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Solution Set
A **solution set** is a collection of all the values that satisfy a given inequality. In this exercise, the inequality is split into two separate parts to find the values of \(x\) that make it true:
  • For \(-4 \leq -13(3x+12)\), the solution is \(x \leq -\frac{152}{39}\).
  • For \(-13(3x+12) < 4\), the solution is \(x > -\frac{160}{39}\).
The solution set is where both conditions are met. This results in \(-\frac{160}{39} < x \leq -\frac{152}{39}\). It's important to note that the solution includes \(-\frac{152}{39}\) but excludes \(-\frac{160}{39}\). This captures all the values that \(x\) can take to satisfy both inequalities.
Interval Notation Described
When we use **interval notation**, we're presenting the solution set as a range of values. This notation helps articulate precisely where numbers fall in relation to each other, especially:
  • Brackets \([\ ]\) indicate a number is included in the set.
  • Parentheses \((\ )\) indicate a number is not included.
For this inequality, the interval notation is \((-\frac{160}{39}, -\frac{152}{39}]\). Here:
  • \((-\frac{160}{39}\) shows \(-\frac{160}{39}\) is excluded.
  • \([-\frac{152}{39}]\) means \(-\frac{152}{39}\) is included.
This conveys that \(x\) can be any number greater than \(-\frac{160}{39}\) and up to \(-\frac{152}{39}\).
Visualizing with the Number Line
A **number line** is a great tool to visually represent the solution set. It makes it clear and straightforward:
  • Identify \(-4.10\) (for \(-\frac{160}{39}\)) and place an open circle there.
  • Locate \(-3.90\) (for \(-\frac{152}{39}\)) and place a closed circle there.
The open circle at \(-4.10\) shows that it is not included, while the closed circle at \(-3.90\) shows that it is part of the solution set.
Shade the line between these two points to represent all the values that satisfy the inequality.
Graphing the Solution Set
**Graphing** is the process of plotting values that satisfy the inequality on a number line. Here's how to accomplish this:
  • Draw a straight horizontal line to act as the number line.
  • Mark \(-4.10\) with an open circle because it is not part of the solution set.
  • Mark \(-3.90\) with a closed circle as it is included in the solution set.
  • Shade the area between the open and closed circles.
Graphing effectively communicates where all the possible values of \(x\) reside, offering a clear and easy-to-interpret visual of the solution.

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