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In the following exercises, find the LCD. $$ \frac{5}{x^{2}-2 x-8}, \frac{2 x}{x^{2}-x-12} $$

Short Answer

Expert verified
The LCD is \[ (x - 4)(x + 2)(x + 3) \].

Step by step solution

01

Factor the Denominators

First, factor each denominator to find their prime factors.For the first fraction, factor the quadratic expression: \[x^2 - 2x - 8 = (x - 4)(x + 2)\]For the second fraction, factor the quadratic expression: \[x^2 - x - 12 = (x - 4)(x + 3)\]
02

Identify Common and Unique Factors

List the unique factors from both denominators. The factors from the first fraction are \( (x - 4) \) and \( (x + 2) \). The factors from the second fraction are \( (x - 4) \) and \( (x + 3) \).
03

Combine Factors to Find the LCD

Combine the factors, taking each factor the greatest number of times it appears in any one factorization:\[ \text{LCD} = (x - 4)(x + 2)(x + 3) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Quadratics
Understanding how to factor quadratics is crucial in solving many algebra problems, including finding the LCD. A quadratic equation is generally in the form of \(ax^2 + bx + c\). To factor this, you need to find two numbers that multiply to \(ac\) and add up to \(b\).

For instance, consider the quadratic expression \(x^2 - 2x - 8\). Here, \(a = 1\), \(b = -2\), and \(c = -8\). You need two numbers that multiply to \(1 \times -8 = -8\) and add up to \(-2\). Those numbers are \(2\) and \(-4\).

So, you can rewrite the quadratic as:
\(x^2 - 4x + 2x - 8\).
Then group the terms:
\(x(x - 4) + 2(x - 4)\).

Finally, factor by grouping:
\((x - 4)(x + 2)\).

Similarly, for \(x^2 - x - 12\), you fact it as \((x - 4)(x + 3)\).
LCD in Algebra
The Least Common Denominator (LCD) is the smallest common multiple of the denominators in a set of fractions. This is crucial for adding, subtracting, or comparing fractions. To find the LCD, follow these steps:

  • Factor each denominator into its prime factors or simplest expressions.
  • Identify all unique factors, including those that appear in both denominators.
  • Combine these factors, taking the highest power of each factor that appears.

In our exercise, we had the fractions: \(\frac{5}{x^{2}-2x-8}\) and \(\frac{2x}{x^{2}-x-12}\).
Factoring the denominators, we get \((x-4)(x+2)\) and \((x-4)(x+3)\).
The unique factors are \(x-4\), \(x+2\), and \(x+3\).
So the LCD is:
\((x - 4)(x + 2)(x + 3)\).
Fractions
Fractions represent a part of a whole and are expressed as \(\frac{a}{b}\), where \(a\) is the numerator and \(b\) is the denominator. Working with fractions often involves finding a common denominator, especially when adding, subtracting, or comparing them.

In algebra, denominators can often be polynomials, requiring factoring to simplify or find the LCD. For example, \(\frac{5}{x^{2}-2x-8}\) and \(\frac{2x}{x^{2}-x-12}\) are algebraic fractions with polynomial denominators.

By factoring the denominators into \((x-4)(x+2)\) and \((x-4)(x+3)\), we can find a common denominator to simplify operations like addition and subtraction.

Having a common denominator allows us to combine the fractions and solve complex algebraic problems more efficiently. This approach makes working with fractions smoother and helps maintain consistency in the equations you are solving.

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