Chapter 4: Problem 264
Graph each line with the given point and slope. (1,-1)\(; m=\frac{2}{3}\)
Short Answer
Expert verified
Use point (1, -1) and slope \(\frac{2}{3}\) to plot points and draw the line \[y = \frac{2}{3}x - \frac{5}{3}\].
Step by step solution
01
- Identify the Point and Slope
The given point is \(1, -1\), and the slope (\(m\)) is \(\frac{2}{3}\).
02
- Understand the Slope-Intercept Form
The slope-intercept form of a line equation is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. We will start by using the point-slope form to find the full equation of the line.
03
- Use the Point-Slope Form
The point-slope form of a line is \(y - y_1 = m(x - x_1)\), where \(m\) is the slope and \(\left(x_1, y_1\right)\) is the given point. Substitute \(\left(1, -1\right)\) and \(m = \frac{2}{3}\): \(y + 1 = \frac{2}{3}(x - 1)\).
04
- Simplify the Equation
Distribute the slope \(\left(\frac{2}{3}\right)\) and simplify: \(y + 1 = \frac{2}{3}x - \frac{2}{3}\). Then, subtract 1 from both sides to isolate \(y\): \(y = \frac{2}{3}x - \frac{2}{3} - 1\). Combine \frac{-2}{3} - 1\ to get \(y = \frac{2}{3}x - \frac{5}{3}\).
05
- Plot the Point on the Graph
Plot the given point \(1, -1\) on the graph.
06
- Use the Slope to Find Another Point
From point \(1, -1\), use the slope \(\frac{2}{3}\): rise 2 units up and run 3 units to the right to find another point \(4, 1\).
07
- Draw the Line Through the Points
Draw a straight line through the points \(1, -1\) and \(4, 1\). This line represents the equation \(\frac{2}{3}x - \frac{5}{3}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form is a convenient way to express the equation of a line. It is written as: \[ y = mx + b \] Here, \(m\) represents the slope of the line, and \(b\) is the y-intercept (where the line crosses the y-axis). Understanding this form is crucial because it directly tells us how steep the line is and where it starts on the y-axis. For example, in the equation \[ y = \frac{2}{3}x - \frac{5}{3} \] \(m = \frac{2}{3}\) indicates the line rises 2 units for every 3 units it moves to the right. \(b = -\frac{5}{3}\) means that the line will cross the y-axis at \(-\frac{5}{3}\). This form simplifies graphing as it provides a direct method to plot the line once you identify the slope and y-intercept.
Point-Slope Form
Another method to find the equation of a line is using the point-slope form which is derived from the slope formula. The point-slope form of a line equation is: \[ y - y_1 = m(x - x_1)\] Here, \(\left(x_1, y_1\right)\) is a point on the line, and \(m\) is the slope. This form is particularly useful when you already have a specific point and slope. For instance, given the point \(1, -1\) and slope \(\frac{2}{3}\), you can write: \[ y - (-1) = \frac{2}{3}(x - 1)\] Simplifying gives: \[ y + 1 = \frac{2}{3}x - \frac{2}{3}\,\] then: \[ y = \frac{2}{3}x - \frac{2}{3} - 1 \] Combining the constants: \[ y = \frac{2}{3}x - \frac{5}{3}. \] This form helps transition into the slope-intercept form, making graphing straightforward.
Plotting Points
Plotting points accurately on a coordinate plane is vital for graphing equations. To plot a point, you need an ordered pair \((x, y)\). Start by locating the \(x\)-coordinate on the horizontal axis, then move vertically to the \(y\)-coordinate. For example, to plot \((1, -1)\), find \(1\) on the x-axis, then go down to \(-1\) on the y-axis. When graphing linear equations, you plot the first given point, then use the slope to find the next point. Using the slope \(\frac{2}{3}\) from point \(1, -1\), you move up 2 units (rise) and 3 units to the right (run). This leads to point \((4, 1)\). After plotting these points, draw a straight line through them to represent your equation. Repeat this process for clearer visual understanding. Remember, accurate plotting is essential for precise graphing.