Chapter 10: Problem 195
In the following exercises, graph by using intercepts, the vertex, and the axis of symmetry. $$ y=3 x^{2}+18 x+20 $$
Short Answer
Expert verified
The vertex is \( (-3, -7) \), the y-intercept is 20, the x-intercepts are \( x = -3 \pm \frac{\sqrt{21}}{3} \), and the axis of symmetry is \( x = -3 \).
Step by step solution
01
Find the y-intercept
To find the y-intercept, set x to 0 and solve for y: \( y = 3(0)^2 + 18(0) + 20 = 20 \).
02
Find the x-intercepts
To find the x-intercepts, set y to 0 and solve for x: \( 0 = 3x^2 + 18x + 20 \).Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) with \( a = 3 \), \( b = 18 \), and \( c = 20 \). Calculate the discriminant: \( b^2 - 4ac = 18^2 - 4(3)(20) = 324 - 240 = 84 \).Now solve: \( x = \frac{-18 \pm \sqrt{84}}{6} = \frac{-18 \pm 2\sqrt{21}}{6} = -3 \pm \frac{\sqrt{21}}{3} \). So, the x-intercepts are \( x = -3 + \frac{\sqrt{21}}{3} \) and \( x = -3 - \frac{\sqrt{21}}{3} \).
03
Find the vertex
Use the vertex formula \( x = -\frac{b}{2a} \). With \( a = 3 \) and \( b = 18 \), \( x = -\frac{18}{2(3)} = -3 \).Plugging \( x = -3 \) back into the equation to get y: \( y = 3(-3)^2 + 18(-3) + 20 = 27 - 54 + 20 = -7 \).So, the vertex is \( (-3, -7) \).
04
Find the axis of symmetry
The axis of symmetry is the vertical line that passes through the vertex. Since the vertex is at \( x = -3 \), the axis of symmetry is \( x = -3 \).
05
Graph the parabola
Now, plot the y-intercept at (0, 20), the x-intercepts at points calculated in Step 2, and the vertex at (-3, -7). Draw the axis of symmetry at \( x = -3 \) and sketch the parabola opening upwards because the coefficient of \( x^2 \) (which is 3) is positive.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Y-Intercept
The first key concept in graphing quadratic equations is finding the y-intercept. This point is where the graph crosses the y-axis. To find the y-intercept, set the value of x to 0 in the quadratic equation and solve for y. For example, given the equation \( y = 3x^2 + 18x + 20 \), you'd set \( x = 0 \):
\( y = 3(0)^2 + 18(0) + 20 = 20 \).
So, the y-intercept is at \( (0, 20) \). This tells us that the graph passes through the point (0,20) on the y-axis.
\( y = 3(0)^2 + 18(0) + 20 = 20 \).
So, the y-intercept is at \( (0, 20) \). This tells us that the graph passes through the point (0,20) on the y-axis.
X-Intercepts
Next, let's explore the x-intercepts, which are the points where the graph crosses the x-axis. To find these, set y to 0 in the equation and solve for x. For the equation \( 0 = 3x^2 + 18x + 20 \), use the quadratic formula:
\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
Identify the coefficients: \( a = 3 \), \( b = 18 \), and \( c = 20 \). First, compute the discriminant:
\( b^2 - 4ac = 18^2 - 4(3)(20) = 324 - 240 = 84 \).
Now apply the quadratic formula:
\( x = \frac{-18 \pm \sqrt{84}}{6} = \frac{-18 \pm 2\sqrt{21}}{6} = -3 \pm \frac{\sqrt{21}}{3} \).
This gives the x-intercepts as \( x = -3 + \frac{\sqrt{21}}{3} \) and \( x = -3 - \frac{\sqrt{21}}{3} \). These are the points where the parabola intersects the x-axis.
\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
Identify the coefficients: \( a = 3 \), \( b = 18 \), and \( c = 20 \). First, compute the discriminant:
\( b^2 - 4ac = 18^2 - 4(3)(20) = 324 - 240 = 84 \).
Now apply the quadratic formula:
\( x = \frac{-18 \pm \sqrt{84}}{6} = \frac{-18 \pm 2\sqrt{21}}{6} = -3 \pm \frac{\sqrt{21}}{3} \).
This gives the x-intercepts as \( x = -3 + \frac{\sqrt{21}}{3} \) and \( x = -3 - \frac{\sqrt{21}}{3} \). These are the points where the parabola intersects the x-axis.
Vertex
The vertex is a crucial point as it represents the peak or the lowest point of the parabola depending on its direction. To find it, use the vertex formula:
\( x = -\frac{b}{2a} \).
Given \( a = 3 \) and \( b = 18 \), we solve:
\( x = -\frac{18}{2(3)} = -3 \).
Once we have the x-coordinate of the vertex, substitute it back into the equation to find the y-coordinate:
\( y = 3(-3)^2 + 18(-3) + 20 = 27 - 54 + 20 = -7 \).
So, the vertex of the parabola is at \( (-3, -7) \). This point is crucial for understanding the parabola's shape and direction.
\( x = -\frac{b}{2a} \).
Given \( a = 3 \) and \( b = 18 \), we solve:
\( x = -\frac{18}{2(3)} = -3 \).
Once we have the x-coordinate of the vertex, substitute it back into the equation to find the y-coordinate:
\( y = 3(-3)^2 + 18(-3) + 20 = 27 - 54 + 20 = -7 \).
So, the vertex of the parabola is at \( (-3, -7) \). This point is crucial for understanding the parabola's shape and direction.
Axis of Symmetry
The axis of symmetry is an important feature of the graph of a quadratic equation. It is a vertical line that divides the parabola into two mirror-image halves and passes through the vertex. The equation for the axis of symmetry can be directly obtained from the x-coordinate of the vertex. For our vertex at \( x = -3 \), the axis of symmetry is:
\( x = -3 \).
This line helps in drawing the graph accurately, ensuring both sides of the parabola are symmetrical.
\( x = -3 \).
This line helps in drawing the graph accurately, ensuring both sides of the parabola are symmetrical.
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations and finding the x-intercepts. The formula is:
\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
This formula can be used with any quadratic equation of the form \( ax^2 + bx + c = 0 \). For our equation, \( 3x^2 + 18x + 20 = 0 \), we used the quadratic formula to find the x-intercepts. Remember:
- Identify the coefficients (a, b, and c).
- Calculate the discriminant \( b^2 - 4ac \).
- Substitute into the formula for x.
The quadratic formula provides the exact points where the parabola intersects the x-axis, essential for graphing the quadratic equation accurately.
To summarize, using the y-intercept, x-intercepts, vertex, axis of symmetry and quadratic formula, you have all the tools needed to accurately graph a quadratic equation.
\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
This formula can be used with any quadratic equation of the form \( ax^2 + bx + c = 0 \). For our equation, \( 3x^2 + 18x + 20 = 0 \), we used the quadratic formula to find the x-intercepts. Remember:
- Identify the coefficients (a, b, and c).
- Calculate the discriminant \( b^2 - 4ac \).
- Substitute into the formula for x.
The quadratic formula provides the exact points where the parabola intersects the x-axis, essential for graphing the quadratic equation accurately.
To summarize, using the y-intercept, x-intercepts, vertex, axis of symmetry and quadratic formula, you have all the tools needed to accurately graph a quadratic equation.