Divisibility by 2
Understanding divisibility by 2 is quite simple. Any number is divisible by 2 if its last digit is even. Even numbers are those which end in 0, 2, 4, 6, or 8.
For instance, numbers like 14, 26, and 38 are all divisible by 2 because their last digits (4, 6, and 8, respectively) are even.
To apply this, look at the last digit of your number. If it's one of those even figures, then the whole number can be divided by 2 without any remainder.
In our example, 550 has a last digit of 0, which is even. So, 550 is divisible by 2.
Divisibility by 3
Checking if a number is divisible by 3 involves a bit more work. You need to find the sum of all its digits and then check if this sum is divisible by 3.
Let's break down the steps with 550:
1. Add the digits together: 5 + 5 + 0 = 10.
2. Determine if this sum (10) is divisible by 3. Since 10 is not divisible by 3, the number 550 is not divisible by 3.
This rule helps because it reduces larger numbers to smaller, more manageable sums.
Divisibility by 5
To determine if a number is divisible by 5, simply look at its last digit. A number is divisible by 5 if its last digit is either 0 or 5.
For example, numbers like 25, 50, and 85 are all divisible by 5 because of their last digits.
For 550, the last digit is 0. Therefore, 550 can be divided by 5 without any remainder.
Divisibility by 6
A number is divisible by 6 if and only if it meets two conditions at the same time:
1. The number must be divisible by 2.
2. The number must be divisible by 3.
In our exercise, 550 is divisible by 2 (last digit is 0) but not by 3 (sum of digits is 10).
Since it does not satisfy both conditions, 550 is not divisible by 6.
Divisibility by 10
This is one of the easiest tests. A number is divisible by 10 if its last digit is 0.
For example, 20, 30, and 100 all end in 0, hence they are divisible by 10.
In our example, the last digit of 550 is 0, indicating that 550 is divisible by 10 without any remainder.
This rule simplifies checking large numbers quickly.
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