/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 Simplify. $$\sqrt{18 y^{6}}+\s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Simplify. $$\sqrt{18 y^{6}}+\sqrt{32 y^{6}}$$

Short Answer

Expert verified
7 y^3 \sqrt{2}

Step by step solution

01

Simplify Inside the Square Roots

First, break down the numbers inside the square roots to their prime factors. \( \ \sqrt{18 y^6} = \sqrt{2 \times 3^2 \times y^6} \ \sqrt{32 y^6} = \sqrt{2^5 \times y^6} \)
02

Simplify Using Properties of Radicals

Utilize properties of square roots to separate the components. \( \ \sqrt{18 y^6} = \sqrt{2} \times \sqrt{3^2} \times \sqrt{y^6} = 3 \times y^3 \times \sqrt{2} \ \sqrt{32 y^6} = \sqrt{2^5} \times \sqrt{y^6} = 4 \times y^3 \times \sqrt{2} \)
03

Combine Like Terms

Combine the simplified terms. \( \ 3 y^3 \sqrt{2} + 4 y^3 \sqrt{2} = (3 + 4) y^3 \sqrt{2} = 7 y^3 \sqrt{2} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Square Roots
A square root is a value that, when multiplied by itself, gives the original number. If you take the square root of 16, you get 4 because 4 * 4 = 16. The symbol for square root is \(\text{√}\). In our example, we deal with the square roots of expressions like \(\text{√18}y^6\) and \(\text{√32}y^6\). To make these simpler, we need to look at the numbers inside the square roots.
Prime Factorization
Prime factorization involves breaking down a number into its prime components, which are prime numbers that multiply together to equal the original number. For example, the prime factors of 18 are 2 and 3 because 2 * 3^2 = 18. Prime numbers are numbers greater than 1 that have no factors other than 1 and themselves. Doing this helps in simplifying square roots. Let's take \(\text{√18 y^6}\). We break 18 into prime factors: 2 and 3^2, so we get \(\text{√(2 \times 3^2 \times y^6)}\). We do the same for 32 and get \(\text{√(2^5 \times y^6)}\).
Properties of Radicals
Radicals, especially square roots, obey certain properties that make them easier to work with. One key property is that the square root of a product \((\text{√ab})\) is the product of the square roots \(\text{√a} \times \text{√b}\). For example, \(\text{√18 y^6}\) can be broken down to \(\text{√2} \times \text{√3^2} \times \text{√y^6}\). Further simplifying, we get \(3 y^3 \text{√2}\) because \(\text{√3^2} = 3\) and \(\text{√y^6} = y^3\). Similarly, \(\text{√32 y^6}\) turns into \(4 y^3 \text{√2}\), using \(\text{√2^5} = 4 \text{√2}\) and \(\text{√y^6} = y^3\).
Combining Like Terms
In algebra, you often combine like terms to simplify an expression. Like terms are terms whose variables and exponents are the same. For the terms \(3 y^3 \text{√2}\) and \(4 y^3 \text{√2}\), the variable part \(y^3 \text{√2}\) is the same in both. So you add the coefficients 3 and 4 to get 7. The final step in simplifying \(\text{√18 y^6} + \text{√32 y^6}\) is combining these like terms to get \(7 y^3 \text{√2}\). This makes our simplified form of the original expression.

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