Chapter 7: Problem 94
$$ \text { Solve: } 0.75=\frac{k}{60} $$
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Chapter 7: Problem 94
$$ \text { Solve: } 0.75=\frac{k}{60} $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \text { Solve: } 800=5 k $$
For exercises 87-90, the completed problem has one mistake. (a) Describe the mistake in words, or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: Solve: \(\frac{2}{x-2}+\frac{8}{x}=\frac{x}{x-2}\) Incorrect Answer: \(\frac{2}{x-2}+\frac{8}{x}=\frac{x}{x-2}\) \(x(x-2)\left(\frac{2}{x-2}+\frac{8}{x}\right)=x(x-2)\left(\frac{x}{x-2}\right)\) \(x(x-2)\left(\frac{2}{x-2}\right)+x(x-2)\left(\frac{8}{x}\right)=x^{2}\) \(2 x+(x-2) 8=x^{2}\) \(2 x+8 x-16=x^{2}\) \(10 x-16=x^{2}\) \(0=x^{2}-10 x+16\) \(0=(x-8)(x-2)\) \(x-8=0 \quad\) or \(\quad x-2=0\) \(x=8 \quad\) or \(\quad x=2\)
For exercises \(67-82\), use the five steps and a proportion. In 2010 , there were \(426.0\) cases of chlamydia per 100,000 Americans with a total of \(1,307,893\) cases of chlamydia. Find the population of Americans used to create this ratio. Round to the nearest hundred. (Source: www.cdc .gov, 2011)
For exercises 1-10, (a) solve. (b) check. $$ \frac{3}{5} x-\frac{1}{4}=\frac{9}{10} $$
The relationship of \(x\) and \(y\) is an inverse variation. When \(x=2, y=10\). a. Find the constant of proportionality, \(k\). b. Write an equation that represents this inverse variation. c. Find \(y\) when \(x=5\).
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