Chapter 7: Problem 3
For exercises 1-8, find the slope of the line that passes through the given points. $$ \left(\frac{1}{9}, \frac{2}{15}\right)\left(\frac{5}{9}, \frac{11}{15}\right) $$
Short Answer
Expert verified
The slope is \( \frac{27}{20} \).
Step by step solution
01
Identify the given points
The given points are \( \left( \frac{1}{9}, \frac{2}{15} \right) \) and \( \left( \frac{5}{9}, \frac{11}{15} \right) \).
02
Recall the slope formula
The formula for the slope (m) of the line that passes through two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by \( m = \frac{y_2 - y_1}{x_2 - x_1} \).
03
Substitute the coordinates into the slope formula
Substitute the coordinates \( x_1 = \frac{1}{9}, y_1 = \frac{2}{15}, x_2 = \frac{5}{9}, \) and \( y_2 = \frac{11}{15} \) into the slope formula. \[ m = \frac{\frac{11}{15} - \frac{2}{15}}{\frac{5}{9} - \frac{1}{9}} \]
04
Simplify the numerator
Simplify the numerator \( \frac{11}{15} - \frac{2}{15} \): \[ \frac{11}{15} - \frac{2}{15} = \frac{11 - 2}{15} = \frac{9}{15} \]
05
Simplify the denominator
Simplify the denominator \( \frac{5}{9} - \frac{1}{9} \): \[ \frac{5}{9} - \frac{1}{9} = \frac{5 - 1}{9} = \frac{4}{9} \]
06
Divide the simplified numerator by the simplified denominator
Divide \( \frac{9}{15} \) by \( \frac{4}{9} \): \[ m = \frac{\frac{9}{15}}{\frac{4}{9}} = \frac{9}{15} \times \frac{9}{4} = \frac{81}{60} = \frac{27}{20} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
slope formula
The slope formula is vital for calculating how steep a line is in coordinate geometry. The formula for the slope, represented as 'm', is derived from the change in y-coordinates divided by the change in x-coordinates.
The slope formula is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
You can use it when you know two points on a line, where one point is \( (x_1, y_1) \) and the other is \( (x_2, y_2) \).
To apply the formula:
In our example, the points are \(\left( \frac{1}{9}, \frac{2}{15} \right)\) and \(\left( \frac{5}{9}, \frac{11}{15} \right)\).
Plug these values into the slope formula to get:
\[ m = \frac{\frac{11}{15} - \frac{2}{15}}{\frac{5}{9} - \frac{1}{9}}. \]
The slope formula is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
You can use it when you know two points on a line, where one point is \( (x_1, y_1) \) and the other is \( (x_2, y_2) \).
To apply the formula:
- First, identify your points ((x1, y1) & (x2, y2))
- Next, find the differences: (y2 - y1) and (x2 - x1)
- Finally, divide the difference in y-coordinates by the difference in x-coordinates
In our example, the points are \(\left( \frac{1}{9}, \frac{2}{15} \right)\) and \(\left( \frac{5}{9}, \frac{11}{15} \right)\).
Plug these values into the slope formula to get:
\[ m = \frac{\frac{11}{15} - \frac{2}{15}}{\frac{5}{9} - \frac{1}{9}}. \]
coordinate geometry
Coordinate geometry, also known as analytic geometry, merges algebra and geometry. It's about understanding geometric shapes using a coordinate system.
Here, the position is represented by coordinates on the x and y axes. The axes intersect at the origin (0, 0).
Any point in this system is represented by (x, y) coordinates. These are often called ordered pairs.
For example, \(\left( \frac{1}{9}, \frac{2}{15} \right)\) means 1/9 units along the x-axis and 2/15 units along the y-axis.
Key items in coordinate geometry are:
Here, the position is represented by coordinates on the x and y axes. The axes intersect at the origin (0, 0).
Any point in this system is represented by (x, y) coordinates. These are often called ordered pairs.
For example, \(\left( \frac{1}{9}, \frac{2}{15} \right)\) means 1/9 units along the x-axis and 2/15 units along the y-axis.
Key items in coordinate geometry are:
- Points (defined by coordinates)
- Lines (defined by points or equations)
- Slopes (show the steepness of a line)
fractions
Fractions represent parts of a whole and are crucial in many mathematical calculations. A fraction is given by \(\frac{a}{b}\) where 'a' is the numerator and 'b' is the denominator.
In our slope problem, we combined and simplified fractions multiple times.
Key operations include:
In our slope problem, we combined and simplified fractions multiple times.
Key operations include:
- Adding/Subtracting Fractions: Ensure you have a common denominator before adding or subtracting the numerators.
For example, \(\frac{11}{15} - \frac{2}{15} = \frac{11 - 2}{15} = \frac{9}{15}\). - Multiplying Fractions: Multiply the numerators and denominators separately.
For instance, \(\frac{9}{15} \times \frac{9}{4} = \frac{81}{60}\). - Simplifying Fractions: Find common factors to reduce the fraction.
Simplifying \(\frac{81}{60}\) gives you \(\frac{27}{20}\).