/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 For exercises \(9-24\), evaluate... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For exercises \(9-24\), evaluate or simplify. $$ \frac{\frac{p^{2}-11 p+30}{p^{2}-2 p-24}}{\frac{p^{2}-4 p-5}{p^{2}+5 p+4}} $$

Short Answer

Expert verified
\[1\]

Step by step solution

01

Factor Each Polynomial

Begin by factoring the polynomials in both the numerator and the denominator of each fraction. For the numerator of the first fraction: \[p^2 - 11p + 30 = (p-5)(p-6)\] For the denominator of the first fraction: \[p^2 - 2p - 24 = (p-6)(p+4)\] For the numerator of the second fraction: \[p^2 - 4p - 5 = (p-5)(p+1)\] For the denominator of the second fraction: \[p^2 + 5p + 4 = (p+1)(p+4)\]
02

Set Up the Problem with Factored Forms

Rewrite the original expression using the factored forms of the polynomials:\[\frac{\frac{(p-5)(p-6)}{(p-6)(p+4)}}{\frac{(p-5)(p+1)}{(p+1)(p+4)}}\]
03

Simplify Each Fraction

Simplify the fractions individually. For the first fraction, cancel the common factor \(p-6\):\[\frac{(p-5)}{(p+4)}\] For the second fraction, cancel the common factor \(p+1\):\[\frac{(p-5)}{(p+4)}\]
04

Divide by the Second Fraction

To divide by a fraction, multiply by its reciprocal. Set the problem up as follows:\[\frac{(p-5)/(p+4)}{(p-5)/(p+4)} = (p-5)/(p+4) \times (p+4)/(p-5)\]
05

Cancel Common Factors and Simplify

Cancel the common factors of \(p-5\) and \(p+4\). After canceling, we are left with:\[ 1 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Polynomials
Factoring is an essential technique in simplifying rational expressions. To factor a polynomial, you need to find expressions that multiply to give the original polynomial. This often involves finding two binomials whose product equals the polynomial. For example, consider the polynomial \(p^2 - 11p + 30\). By examining the polynomial, we look for two numbers that multiply to 30 and add up to -11. These numbers are -5 and -6, so we can factor it as \((p-5)(p-6)\).
Similarly, for \(p^2 - 2p - 24\), we seek two numbers that multiply to -24 and add to -2. Here, we find -6 and 4, so the factorization is \((p-6)(p+4)\).
Polynomials like \(p^2 + 5p + 4\) can be factored into \((p+1)(p+4)\) by looking for numbers that multiply to 4 and add up to 5. Understanding how to factor polynomials helps break down complex expressions into simpler, more manageable parts.
Canceling Common Factors
After factoring polynomials, the next step in simplifying rational expressions is to cancel common factors. Common factors in the numerator and denominator can be canceled out because any number divided by itself is 1. For instance, in the fraction \((p-5)(p-6) / (p-6)(p+4)\), the \(p-6\) terms in the numerator and denominator can be canceled. This simplification makes the fraction easier to handle.
In our original exercise, after factoring, we have \((p-5)(p-6) / (p-6)(p+4)\) and \((p-5)(p+1) / (p+1)(p+4)\). Here, \(p-6\) in the first fraction and \(p+1\) in the second can be canceled. This step is crucial in reducing complexity and making further calculations more straightforward.
Multiplying Rational Expressions
Multiplying rational expressions involves flipping the second fraction (taking its reciprocal) and then multiplying. For our exercise, we transform the division of fractions into multiplication by flipping the second fraction. We start with: \left( \frac{(p-5)/(p+4)}{(p-5)/(p+4)} \right)\.
We convert this into multiplication: \left( \frac{(p-5)}{(p+4)} \times \frac{(p+4)}{(p-5)} \right)\.
During multiplication, we multiply numerators together and denominators together. In our exercise, after converting the division into multiplication, we have: \left( \frac{(p-5)}{(p+4)} \times \frac{(p+4)}{(p-5)} \right)\. Canceling the common factors in the resulting expression \(p-5\) and \(p+4\), we ultimately get: 1.
By understanding these steps - factoring, canceling, and multiplying, students can simplify complex rational expressions with confidence.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For exercises 79-82, (a) clear the fractions and solve. (b) check. $$ 1=\frac{7}{6} w+\frac{5}{12} $$

For a fixed length of household copper wire, the relationship of the cross- sectional area, \(x\), and the resistance, \(y\), is an inverse variation. When the cross-sectional area is \(3.14 \times 10^{-6} \mathrm{~m}^{2}\), the resistance is \(5.4 \times 10^{-3} \mathrm{ohm}\). a. Find the constant of proportionality, \(k\). Use scientific notation. Include the units of measurement. b. Write an equation that represents this relationship. c. Find the resistance when the cross-sectional area is \(2.05 \times 10^{-6} \mathrm{~m}^{2}\). Round the mantissa to the nearest tenth.

The relationship of \(x\) and \(y\) is a direct variation. When \(x=2, y=6\). a. Find the constant of proportionality, \(k\). b. Write an equation that represents this direct variation. c. Find \(y\) when \(x=4\). d. Use slope-intercept graphing to graph this equation. e. Use the graph to find \(y\) when \(x=5\).

For exercises \(41-44\), the formula \(R=\frac{V C}{T}\) describes the flow rate of fluid \(R\) through an intravenous drip. Is the relationship of the given variables a direct variation or an inverse variation? $$ V \text { and } C \text { are constant; the relationship of } R \text { and } T \text {. } $$

For exercises 61-64, the completed problem has one mistake. (a) Describe the mistake in words or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: In the formula \(A=\frac{10}{B}\), is the relationship between \(A\) and \(B\) a direct variation or an inverse variation? Incorrect Answer: Since as \(B\) increases, \(A\) also increases, this is a direct variation.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.