Chapter 7: Problem 2
For exercises 1-66, simplify. $$ \frac{240}{540} $$
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Chapter 7: Problem 2
For exercises 1-66, simplify. $$ \frac{240}{540} $$
These are the key concepts you need to understand to accurately answer the question.
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For exercises 1-10, (a) solve. (b) check. $$ \frac{1}{6} w+\frac{23}{8}=-3 $$
For exercises 61-64, the completed problem has one mistake. (a) Describe the mistake in words or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: The relationship of the number of gallons of gas, \(x\), and the total cost of the gas, \(y\), is a direct variation. If 8 gallons of gas costs \(\$ 24\), find the constant of proportionality. Incorrect Answer: $$ \begin{aligned} &k=x y \\ &k=(8 \mathrm{gal})(\$ 24) \\ &k=\$ 192 \mathrm{gal} \end{aligned} $$
If both sides of the equation \(\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\) are multiplied by \(x(x-1)\), the simplified equation is \(1 x+2(x-1)=x^{2}\). Rewriting in standard form and factoring, the equation is \((x-2)(x-1)=0\) and its solutions are \(x=1\) or \(x=2\). Explain why the solution \(x=1\) is extraneous.
For exercises \(45-48\), the formula \(R=\frac{U F}{P}\) describes the glomular filtration rate by a kidney \(R\). Is the relationship of the given variables a direct variation or an inverse variation? $$ R \text { and } P \text { are constant; the relationship of } U \text { and } F \text {. } $$
When the radiation is constant, the relationship of the current in an X-ray tube, \(x\), and the exposure time, \(y\), is an inverse variation. When the current is 600 milliamp, the exposure time is \(0.2 \mathrm{~s}\). Write an equation that represents this variation. Include the units.
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