Chapter 7: Problem 18
For exercises \(5-48\), simplify. $$ \frac{u^{2}}{u^{2}+6 u+8}-\frac{4}{u^{2}+6 u+8} $$
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Chapter 7: Problem 18
For exercises \(5-48\), simplify. $$ \frac{u^{2}}{u^{2}+6 u+8}-\frac{4}{u^{2}+6 u+8} $$
These are the key concepts you need to understand to accurately answer the question.
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Find the number of 80,500 children and adolescents who are obese. Round to the nearest hundred. Approximately one in six children and adolescents are obese. (Source: www.cdc.gov, Nov. 2011)
The relationship of the diameter of a circle, \(x\), and the circumference of the circle, \(y\), is a direct variation. The diameter of a circle is \(20 \mathrm{~cm}\), and the circumference is \(62.8 \mathrm{~cm}\). a. Find the constant of proportionality, \(k\). b. Write an equation that represents this relationship. c. Find the circumference of a circle with a diameter of \(40 \mathrm{~cm}\).
For exercises \(67-82\), use the five steps and a proportion. In \(2010,3.5\) per 100,000 full-time equivalent workers were killed on the job with a total of 547 workers killed on the job. Find the number of full-time equivalent workers used to create this ratio. Round to the nearest whole number. (Source: www.osha.gov)
In radiography, a grid reduces the effect of X-ray scattering. The relationship of the interspace distance on the grid, \(x\), and the grid ratio, \(y\), is an inverse variation. When the interspace distance on a grid is 300 micrometers, the grid ratio is 8 . Write an equation that represents this variation. Include the units.
For exercises 87-90, the completed problem has one mistake. (a) Describe the mistake in words, or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: Solve: \(\frac{11}{x}+\frac{13}{12}=1\) Incorrect Answer: Least common denominator is \(12 x\). $$ \begin{aligned} 12 x\left(\frac{11}{x}+\frac{13}{12}\right) &=1 \\ 12 x\left(\frac{11}{x}\right)+12 x\left(\frac{13}{12}\right) &=1 \\ 132+13 x &=1 \\ \frac{-132}{0+13 x} &=-131 \\ \frac{13 x}{13} &=\frac{-131}{13} \\ x &=-\frac{131}{13} \end{aligned} $$
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