Chapter 7: Problem 12
For exercises \(9-24\), evaluate or simplify. $$ \frac{\frac{4 p}{9}}{\frac{2 p^{2}}{3}} $$
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Chapter 7: Problem 12
For exercises \(9-24\), evaluate or simplify. $$ \frac{\frac{4 p}{9}}{\frac{2 p^{2}}{3}} $$
These are the key concepts you need to understand to accurately answer the question.
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For exercises 87-90, the completed problem has one mistake. (a) Describe the mistake in words, or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: Solve: \(\frac{2}{x-2}+\frac{8}{x}=\frac{x}{x-2}\) Incorrect Answer: \(\frac{2}{x-2}+\frac{8}{x}=\frac{x}{x-2}\) \(x(x-2)\left(\frac{2}{x-2}+\frac{8}{x}\right)=x(x-2)\left(\frac{x}{x-2}\right)\) \(x(x-2)\left(\frac{2}{x-2}\right)+x(x-2)\left(\frac{8}{x}\right)=x^{2}\) \(2 x+(x-2) 8=x^{2}\) \(2 x+8 x-16=x^{2}\) \(10 x-16=x^{2}\) \(0=x^{2}-10 x+16\) \(0=(x-8)(x-2)\) \(x-8=0 \quad\) or \(\quad x-2=0\) \(x=8 \quad\) or \(\quad x=2\)
For exercises 11-30, (a) solve. (b) check. $$ \frac{13}{d}-\frac{5}{9}=\frac{1}{6} $$
For exercises 49-52, the formula \(C=\frac{P_{m} P_{i}}{T F}\) describes the cost of insurance, \(C\). Is the relationship of the given variables a direct variation or an inverse variation? $$ P_{m}, T \text {, and } F \text { are constant; the relationship of } C \text { and } P_{i} $$
For exercises 43-58, (a) solve. (b) check. $$ \frac{2}{x}=0 $$
For exercises \(67-82\), use the five steps and a proportion. In 2010 , there were \(426.0\) cases of chlamydia per 100,000 Americans with a total of \(1,307,893\) cases of chlamydia. Find the population of Americans used to create this ratio. Round to the nearest hundred. (Source: www.cdc .gov, 2011)
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