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Chapter 6: Problem 24

Use a pattern to factor. Check. Identify any prime polynomials. $$ m^{2}-4 $$

Short Answer

Expert verified
The polynomial \( m^2 - 4 \) factors to \( (m - 2)(m + 2) \). Both factors are prime.

Step by step solution

01

Recognize the Pattern

The expression given is a difference of squares. A difference of squares takes the form \[ a^2 - b^2 \] and can be factored into \[ (a - b)(a + b) \].
02

Identify Squares

Identify the terms that are squared in the given polynomial. Here, \( m^2 \) is \( a^2 \) and \( 4 = 2^2 \) is \( b^2 \).
03

Factor the Expression

Using the difference of squares formula, factor \[ m^2 - 4 \] into \[ (m - 2)(m + 2) \].
04

Check

Expand the factored form to check your work: \[ (m - 2)(m + 2) = m^2 + 2m - 2m - 4 = m^2 - 4 \]. The original expression is obtained, confirming the factorization.
05

Identify Prime Polynomials

Both \( m - 2 \) and \( m + 2 \) do not factor further and are thus considered prime polynomials.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference of Squares
The 'difference of squares' is a special polynomial factorization pattern. It's when you have a subtraction between two squared terms. This pattern can be identified by expressions of the form
  • a2 - b2
For example, in the given exercise, we see
  • $$m^2 - 4$$
which fits the pattern because
  • $$m^2$$
  • $$4 = 2^2$$
Knowing this allows us to factor the expression using the formula:
  • $$(a - b)(a + b)$$
Substitute 'a' with 'm' and 'b' with '2' to get:
  • $$(m - 2)(m + 2)$$
This factorization method is quite handy for specific types of polynomials. Always look for the difference of squares pattern when factoring.
Polynomial Factorization
Polynomial factorization is the process of rewriting a polynomial as a product of simpler polynomials. This can often make solving equations and simplifying expressions much easier.
Some common patterns and methods include:
  • Difference of squares
  • Perfect square trinomials
  • Grouping
  • General quadratic formula
In our problem, we used the difference of squares to factor
$$ m^2 - 4$$ into
  • $$(m - 2)(m + 2)$$
Being familiar with these patterns helps in quickly identifying how to break down complex expressions. Besides patterns, always try to look for common factors in all terms first. Factorizing can simplify polynomials and make it easier to identify solutions or properties.
Prime Polynomials
Once polynomials are factored, it鈥檚 crucial to identify if any of those factors can be broken down further. A polynomial that cannot be factored further over the integers is known as a 'prime polynomial'.
In our example, after factoring
  • $$m^2 - 4$$
  • into
  • $$ (m - 2)(m + 2)$$
    • .
We observe that neither
  • $$(m - 2)$$
  • nor
  • $$(m + 2)$$
can be factored further. Thus, both are prime polynomials. Recognizing prime polynomials helps in ensuring that the factorization process is complete. Prime polynomials play a similar role to prime numbers in arithmetic; they are the basic building blocks in polynomial factorization.
Elementary Algebra
Elementary algebra involves understanding and using basic algebraic operations and concepts. This includes:
  • Solving equations
  • Factoring expressions
  • Working with polynomials
One fundamental part of elementary algebra is factoring, which simplifies expressions and equations significantly. In our example problem, we factored
  • $$m^2 - 4$$ into
  • $$ (m - 2)(m + 2)$$
Understanding algebra includes recognizing patterns like the difference of squares and knowing when a polynomial cannot be factored further, as seen with the prime polynomials. Mastery of elementary algebraic concepts and techniques provides a strong foundation for more advanced mathematics.

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Most popular questions from this chapter

(a) solve. (b) check. $$ x^{2}+x=90 $$

For exercises 97-100, the completed problem has one mistake. (a) Describe the mistake in words, or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: Solve: \(x^{3}+7 x^{2}+10 x=0\) Incorrect Answer: \(x^{3}+7 x^{2}+10 x=0\) \(x\left(x^{2}+7 x+10\right)=0\) \((x+5)(x+2)=0\) \(x+5=0\) or \(x+2=0\) \(\frac{-5-5}{x=-5}\) or \(\frac{-2-2}{x=-2}\) Solutions: \(x=-5, x=-2\)

Factor completely. Identify any prime polynomials. $$ x^{17}-x^{7} y^{2} $$

For exercises 81-86, use a polynomial equation to find the length and width of the rectangle. A rectangle is \(3 \mathrm{in}\). longer than it is wide. Its area is 108 in. \(^{2}\).

Solve. $$ y(y-5)(y-9)=0 $$
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