/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Identify the constant in the exp... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 72

Identify the constant in the expression \(8 x-2\).

Short Answer

Expert verified
The constant in the expression \(8x - 2\) is \(-2\).

Step by step solution

01

Identify Terms in the Expression

The given expression is \(8x - 2\). It contains two terms: \(8x\) and \(-2\). Understanding the types of terms in the expression is the first step.
02

Determine Types of Terms

Next, identify the types of terms: \(8x\) is a variable term because it contains the variable \(x\), while \(-2\) is a constant term because it does not contain any variables.
03

Identify the Constant Term

Since \(-2\) is the term without any variables, it is identified as the constant in the expression.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Identifying Terms in Expressions
In algebra, an expression is a combination of different terms.
Terms are the individual parts of an expression, separated by plus or minus signs.
For example, in the expression \(8x - 2\), there are two terms: \(8x\) and \(-2\).
It is crucial to first identify these terms to understand and solve algebraic expressions correctly.
  • A term can be a number (constant), a variable, or a combination of both.
Let's move on to understanding the different types of terms.
Variable Terms
Variable terms are terms that include variables, such as letters representing unknown values.
In the expression \(8x - 2\), the term \(8x\) is a variable term because it includes the variable \(x\).
The coefficient of a variable term is the number multiplying the variable.
In \(8x\), the coefficient is 8.
  • Variables are usually represented by letters like \(x\), \(y\), or \(z\).
  • Coefficients give us more information about the term, such as how many times the variable is counted.
Variable terms change depending on the value of the variable.
Constant Terms
Constant terms are the terms in an expression that don鈥檛 change value since they do not contain any variables.
They are fixed numbers.
In the expression \(8x - 2\), the term \(-2\) is a constant term.
Constants are easy to identify because they are just numbers without any attached variables.
  • Constants provide a baseline value in the expression.
  • Unlike variable terms, constants remain the same regardless of any changes to the variables in the expression.
For the expression \(8x - 2\), the constant term is \(-2\).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) solve one of the equations for a variable and solve by substitution. (b) if there is one solution, check. $$ \begin{array}{r} x+y=8 \\ 2 x+y=8 \end{array} $$

The maximum combined length and girth of a package that is mailed at the priority rate with the U.S. Postal Service is \(108 \mathrm{in}\). The length is the measure of the longest side of the package, and the girth is the distance measured around the thickest part of the parcel. A box is 3 in. high, 15 in. long, and 8 in. wide. Find its girth.

For exercises \(3-22\), graph. Label the solution region.a $$ \begin{aligned} &x+y \leq 8 \\ &x \geq 2 \end{aligned} $$

For exercises \(85-88\), the completed problem has one mistake. (a) Describe the mistake in words, or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: Write a system of equations that represents the relationship of the variables. Each pound of Cereal A contains \(0.5 \mathrm{oz}\) of almonds and \(2 \mathrm{oz}\) of dried cranberries. Each pound of Cereal B contains 2 oz of almonds and 1 oz of dried cranberries. Find the amount of each cereal needed to make 400 lb of a new cereal that contains \(0.75 \mathrm{oz}\) of almonds per pound of cereal. (1 \(\mathrm{lb}=16 \mathrm{oz}\).) $$ \begin{aligned} &x=\text { amount of Cereal A } \\ &y=\text { amount of Cereal B } \end{aligned} $$ Incorrect Answer: \(x+y=400 \mathrm{lb}\) $$ \left(\frac{0.5 \mathrm{oz}}{1 \mathrm{lb}}\right) x+\left(\frac{2 \mathrm{oz}}{1 \mathrm{lb}}\right) y=0.75 \mathrm{oz} $$

Solve \(d=r t\) for \(r\).
See all solutions

Recommended explanations on Math Textbooks

Probability and Statistics

Read Explanation

Calculus

Read Explanation

Discrete Mathematics

Read Explanation

Pure Maths

Read Explanation

Mechanics Maths

Read Explanation

Applied Mathematics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.