/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Solve by substitution or elimina... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve by substitution or elimination. $$ \begin{aligned} &\frac{1}{2}=3 x-y \\ &2 x+3 y=\frac{5}{4} \end{aligned} $$

Short Answer

Expert verified
\(x = \frac{1}{4}\), \( y = \frac{1}{4}\)

Step by step solution

01

Simplify the First Equation

Rewrite the first equation to make it more manageable. Starting with \(\frac{1}{2} = 3x - y\), add \(y\) to both sides to get the expression for \(y\): \(y = 3x - \frac{1}{2}\).
02

Substitute in the Second Equation

Replace \(y\) in the second equation with its expression from Step 1. The second equation is \(2x + 3y = \frac{5}{4}\). Substituting \(y = 3x - \frac{1}{2}\) gives: \[ 2x + 3\big(3x - \frac{1}{2}\big) = \frac{5}{4} \] Simplify this equation.
03

Solve for \(x\)

Distribute and combine like terms in the equation from Step 2: \[ 2x + 9x - \frac{3}{2} = \frac{5}{4} \] which simplifies to \[ 11x - \frac{3}{2} = \frac{5}{4} \]. Add \(\frac{3}{2}\) to both sides to isolate terms with \(x\): \[ 11x = \frac{5}{4} + \frac{6}{4} \]. Combine the fractions: \[ 11x = \frac{11}{4} \]. Divide both sides by 11 to find \(x\): \[ x = \frac{1}{4} \].
04

Solve for \(y\)

Substitute \(x = \frac{1}{4}\) back into the expression for \(y\) derived in Step 1: \[ y = 3\big(\frac{1}{4}\big) - \frac{1}{2} \]. Evaluate the expression: \[ y = \frac{3}{4} - \frac{1}{2} \]. Convert \( \frac{1}{2} \) to \( \frac{2}{4} \) to combine like terms: \[ y = \frac{3}{4} - \frac{2}{4} = \frac{1}{4} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Equations
Linear equations are equations where each term is either a constant or the product of a constant and a single variable.
These equations form straight lines when graphed.
For example, in the given exercise, we have two linear equations:
\[ \frac{1}{2} = 3x - y \] and \[ 2x + 3y = \frac{5}{4} \].
Both equations represent straight lines on a graph.
Solving these equations usually involves finding the point where the lines intersect.
Solving Systems of Equations
A system of equations consists of multiple equations that share the same set of variables.
To solve these systems, we need to find values for the variables that satisfy all equations simultaneously.
In the provided exercise, the system comprises:
  • \[ \frac{1}{2} = 3x - y \]
  • \[ 2x + 3y = \frac{5}{4} \]

The solution to this system is a pair of values \((x, y)\) that make both equations true together.
Different methods can be used, like substitution or elimination, to find the solution.
Substitution and Elimination Methods
There are two main methods to solve systems of equations: substitution and elimination.
The substitution method involves solving one of the equations for one variable and then substituting this value into the other equation.
In the provided exercise, we used substitution by first solving the first equation for \(y\):
\[ y = 3x - \frac{1}{2} \]
Then, we substituted \(y\) into the second equation and solved for \(x\).
The elimination method involves adding or subtracting equations to eliminate a variable, making it easier to solve for the remaining variable.
Both methods can lead to the solution, but substitution is particularly effective when one equation is easily solved for one variable.
Understanding these methods equips you with the tools to handle most systems of linear equations successfully.

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Most popular questions from this chapter

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For exercises \(85-88\), the completed problem has one mistake. (a) Describe the mistake in words, or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: Write a system of equations that represents the relationship of the variables. Mixture A is 6\% juice. Mixture B is \(15 \%\) juice. Mixture B contains \(50 \%\) of the RDA of vitamin C. Find the amount of each mixture needed to make 80 gal of a new drink that is \(11 \%\) juice. Round to the nearest whole number. $$ \begin{aligned} &x=\text { amount of Mixture A } \\ &y=\text { amount of Mixture B } \\ &\text { Incorrect Answer: } x+y=80 \text { gal } \\ &\qquad 0.06 x+0.50 y=(0.11)(80 \mathrm{gal}) \end{aligned} $$

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