/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 A caterer is buying \(40 \mathrm... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A caterer is buying \(40 \mathrm{lb}\) of oranges and apples. She wants four times as many pounds of apples as oranges. Find the amount of oranges and the amount of apples that she should buy.

Short Answer

Expert verified
8 pounds of oranges and 32 pounds of apples.

Step by step solution

01

Define the variables

Let the number of pounds of oranges be denoted by \( x \) and the number of pounds of apples be denoted by \( y \).
02

Set up the equations

According to the problem statement, two equations can be formed: 1) The total weight equation: \( x + y = 40 \) 2) Apples to oranges ratio: \( y = 4x \)
03

Substitute the second equation into the first

Since \( y = 4x \), substitute \( 4x \) for \( y \) in the first equation to get: \( x + 4x = 40 \).
04

Solve for \( x \)

Combine like terms to get: \( 5x = 40 \). Then solve for \( x \) by dividing both sides by 5: \( x = 8 \).
05

Solve for \( y \)

Substitute \( x = 8 \) back into the second equation: \( y = 4 \times 8 = 32 \).
06

Check the solution

Verify the solution by checking both conditions: \( x + y = 8 + 32 = 40 \) and \( y = 4x \). Both conditions are satisfied.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

linear equations
Linear equations are fundamental in algebra and appear often in word problems. They typically have one or two variables and form straight lines when graphed. In the exercise, we encounter two linear equations: \(x + y = 40\) and \(y = 4x\). These equations help us describe the relationship between the pounds of oranges \(x\) and apples \(y\). The first equation represents the total weight, whereas the second expresses that the pounds of apples are four times that of pounds of oranges.
This step-by-step process shows how establishing equations from word problems can lead us to solutions.
substitution method
The substitution method is a powerful technique for solving systems of linear equations. It involves solving one equation for one variable and then substituting this expression into the other equation.
In our problem, we start by solving \(y = 4x\). We then substitute \(4x\) for \(y\) in the first equation:
\[ x + 4x = 40 \ 5x = 40 \ x = 8 \]
This solution of \(x\) is then substituted back into the second equation to find \(y\):
\[ y = 4 \times 8 = 32 \]
This shows how substitution simplifies solving systems of equations by reducing the problem to a single variable.
variables
Variables are symbols, usually letters, that represent unknown numbers in equations. Here, \(x\) stands for the pounds of oranges, and \(y\) for the pounds of apples.
Identifying variables is the first step in solving word problems. We defined our variables and then formulated equations based on those definitions. Using variables allows us to model real-world problems mathematically and find solutions systematically.
Understanding what each variable represents is crucial. It helps us set up correct equations and interpret the solutions properly. In our problem, replacing undefined terms ('apples' and 'oranges') with variables \(x\) and \(y\) made it easier to use algebraic methods to find the amounts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A fuel is \(20 \%\) No. 1 Diesel. Find the amount of this fuel and the amount of pure No. 1 Diesel needed to make 8000 gallons that is \(40 \%\) No. 1 Diesel.

(a) Write five inequalities that represent the constraints. (b) Graph the inequalities that represent the constraints. Label the feasible region. Independent students in their first year of college can receive up to $$\$ 9500$$ in Stafford loans. Of this amount, a maximum of $$\$ 3500$$ can be federally subsidized Stafford loans, and a maximum of $$\$ 6000$$ can be unsubsidized Stafford loans. Let \(x=\) amount in federally subsidized Stafford loans, and let \(y=\) amount in unsubsidized Stafford loans.

The size of cylindrical cans is described by using two three-digit numbers. The first number describes the diameter, and the second number describes the height. The first digit in each number is the number of whole inches, and the second two digits are the number of sixteenths of an inch. For example, a 303 by 407 can has a diameter of \(3 \frac{3}{16} \mathrm{in}\). and is \(4 \frac{7}{16} \mathrm{in}\). high. The formula for the volume \(V\) of a cylinder is \(V=\pi r^{2} h\), where \(r\) is the radius and \(h\) is the height. Find the volume of a 200 by 503 beverage can. Round to the nearest whole number.

The perimeter of a rectangle is \(60 \mathrm{in}\). The length is 14 in. longer than the width. Find the length and the width.

A prep cook at a restaurant in a national park gets off work at 8 a.m. At \(8: 30\) a.m., she starts hiking on a trail at a speed of \(2.5 \mathrm{mi}\) per hour. A server gets off work at 10 a.m. At 10:30 a.m., she starts hiking on the same trail at a speed of \(4.5 \mathrm{mi}\) per hour. Find the time in minutes when the server will catch up with the cook. Find the distance traveled by each person.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.