/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 (a) solve by elimination. (b) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) solve by elimination. (b) if there is one solution, check. $$ \begin{array}{r} 10 c-16 n=3 \\ -5 c+8 n=9 \end{array} $$

Short Answer

Expert verified
No solution. The equations result in a contradiction (0 = 21).

Step by step solution

01

Align the equations

Write both equations as they are given. Equation 1: \[10c - 16n = 3\] Equation 2: \[-5c + 8n = 9\]
02

Adjust the coefficients

We notice that multiplying Equation 2 by 2 will make the coefficients of the corresponding terms align for easy elimination. Modified Equation 2: \[-10c + 16n = 18\]
03

Add the equations to eliminate one variable

Add Equation 1 and the modified Equation 2 to eliminate variable \( c \):\[(10c - 16n) + (-10c + 16n) = 3 + 18\]This simplifies to:\[0 = 21\]
04

Analyze the result

The result \[0 = 21\] is a contradiction, indicating that there is no solution to the given system of equations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

elimination method
The elimination method is a powerful technique for solving systems of linear equations. It involves adding or subtracting equations to eliminate one of the variables, making it simpler to solve for the remaining variable. Here, we start with two equations in the variables \( c \) and \( n \):

\[ 10c - 16n = 3 \]\[-5c + 8n = 9 \]

We notice that if we multiply the second equation by 2, the coefficients of \( c \) become equal but with opposite signs:

\[-10c + 16n = 18 \]

By adding this to the first equation, the \( c \) terms cancel out:

(10c - 16n) + (-10c + 16n) = 3 + 18

This simplifies to 0 = 21, highlighting the power of the elimination method in signaling inconsistencies when no solutions exist.
contradiction in equations
A contradiction in equations occurs when we end up with a statement that is always false, like 0 = 21. Let's look at our system again:

\[10c - 16n = 3 \]\[-10c + 16n = 18 \]

When we added these equations, the term for variable \( c \) canceled out:

0 + 0 = 21 or

0 = 21

This result is clearly false and indicates that no combination of \( c \) and \( n \) will satisfy both equations at the same time. Thus, we have encountered a contradiction, meaning there is no solution to the given system of equations.
no solution
When dealing with systems of equations, it’s possible to find that there is no solution. This happens if the equations represent parallel lines, which never intersect. In our example, the contradiction 0 = 21 signals that:
  • Neither equation can be satisfied by the same \( c \) and \( n \).
  • Graphically, if plotted, these lines would be parallel and never meet.
Thus, this system is inconsistent, producing no solution under any circumstance. When using the elimination method, such contradictions immediately indicate no common solution exists.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A karat describes the percent gold in an alloy (a mixture of metals). $$ \begin{array}{|c|c|} \hline \text { Name of alloy } & \text { Percent gold } \\ \hline \text { 10-karat gold } & 41.7 \% \\ \text { 14-karat gold } & 58.3 \% \\ \text { 18-karat gold } & 75 \% \\ \text { 20-karat gold } & 83.3 \% \\ \text { 24-karat gold } & 100 \% \\ \hline \end{array} $$ If 9 oz of 14-karat gold jewelry is melted down, find the amount of 20 -karat gold to add to the melted jewelry to create a new alloy that is \(18-k\) arat gold. Find the amount of the new alloy. Round to the nearest tenth.

The cost to make a product is $$\$ 21.50$$. The fixed overhead costs per month to make the product are $$\$ 21,450$$. The price of each product is $$\$ 29.75$$. Find the break-even point for this product.

A timber bolt with a diameter of \(\frac{5}{8}\) in. weighs \(1.2 \mathrm{lb}\) and costs $$\$ 3.65$$. A hex bolt with a diameter of 1 in. weighs \(3 \mathrm{lb}\) and costs $$\$ 7.82$$. The total weight of 20 bolts is \(51 \mathrm{lb}\). Find the number of timber bolts and the number of hex bolts.

A karat describes the percent gold in an alloy (a mixture of metals). $$ \begin{array}{|c|c|} \hline \text { Name of alloy } & \text { Percent gold } \\ \hline \text { 10-karat gold } & 41.7 \% \\ \text { 14-karat gold } & 58.3 \% \\ \text { 18-karat gold } & 75 \% \\ \text { 20-karat gold } & 83.3 \% \\ \text { 24-karat gold } & 100 \% \\ \hline \end{array} $$ Find the amount of 24-karat gold and the amount of silver to mix to make 8 oz of 10 -karat gold. Round to the nearest hundredth.

A new hotel will have 520 rooms. There must be seven times as many rooms that are designated as nonsmoking as rooms that are designated as smoking. Find the number of nonsmoking rooms. Find the number of smoking rooms.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.