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(a) solve by elimination. (b) if there is one solution, check. $$ \begin{aligned} 2 x+y &=7 \\ 4 x-3 y &=-16 \end{aligned} $$

Short Answer

Expert verified
The solution is \(x = \frac{1}{2}\) and \(y = 6\). After verification, the solution is correct.

Step by step solution

01

Align both equations

Align the given equations to prepare for the elimination method: (1) \(2x + y = 7\) (2) \(4x - 3y = -16\)
02

Eliminate one variable

We aim to eliminate the variable \(y\). To do this, multiply Equation (1) by 3 to align the coefficients of \(y\): \(3(2x + y) = 3(7)\) This gives us: (3) \(6x + 3y = 21\)
03

Add or subtract equations

Now add Equation (2) and Equation (3): \((6x + 3y) + (4x - 3y) = 21 + (-16)\) This simplifies to: \(10x = 5\)
04

Solve for \(x\)

Divide both sides of the equation by 10 to solve for \(x\): \(x = \frac{1}{2}\)
05

Substitute \(x\) back into one equation

Substitute \(x = \frac{1}{2}\) into Equation (1) to find \(y\): \(2(\frac{1}{2}) + y = 7\) This simplifies to: \(1 + y = 7\) Therefore: \(y = 6\)
06

Check the solution

Verify the solution by substituting \(x = \frac{1}{2}\) and \(y = 6\) back into the second equation: \(4(\frac{1}{2}) - 3(6) = -16\) This simplifies to: \(2 - 18 = -16\) Since both sides of the equation are equal, the solution is verified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Systems of Equations
A system of equations consists of two or more equations that share common variables. When solving such systems, we aim to find values for the variables that satisfy all equations simultaneously. In our example, the system includes the variables \(x\) and \(y\) in the equations:
  • \(2x + y = 7\)
  • \(4x - 3y = -16\)
Solving Equations
The elimination method is a systematic technique for solving systems of equations. The goal is to eliminate one variable so we can easily solve for the other.
Here’s a step-by-step explanation:1. **Align both equations:** Start by writing both equations one below the other. \text{Step 1:} \begin{aligned} 2x + y &= 7 \ 4x - 3y &= -16 2. **Eliminate a variable:** Choose a variable to eliminate by making the coefficients (numbers in front of the variable) in both equations equal but opposite. In this case, we will eliminate \(y\). To achieve this, multiply the first equation by 3: \text{Step 2:} \begin{aligned} 3 \times (2x + y) &= 3 \times 7 \ 6x + 3y &= 21 3. **Add the equations:** Add the modified first equation to the second equation to eliminate \(y\). \text{Step 3:} \begin{aligned} (6x + 3y) + (4x - 3y) &= 21 + (-16) \ 10x &= 5 4. **Solve for \(x\):** Divide both sides of the resulting equation by 10: \text{Step 4:} \begin{aligned} x &= \frac{5}{10} \ x &= \frac{1}{2}
Verification of Solutions
Once we have a solution, it's crucial to verify it by substituting the values back into the original equations. This ensures accuracy and confirms that the solution works for all equations.
1. Substitute \(x = \frac{1}{2}\) back into one of the original equations to find \(y\): \text{Step 5:} \begin{aligned} 2(\frac{1}{2}) + y &= 7 \ y &= 7 - 1 \ y &= 6 2. Verify by checking both values (\(x = \frac{1}{2}\) and \(y = 6\)) in the second equation: \text{Step 6:} \begin{aligned} 4(\frac{1}{2}) - 3(6) &= -16 \ 2 - 18 &= -16
Algebraic Manipulation
Algebraic manipulation involves using arithmetic operations (addition, subtraction, multiplication, division) to rearrange equations and solve for unknown variables. Learning these skills is essential for solving systems of equations efficiently.
Key steps involved in manipulation for the elimination method are:
  • **Multiplication to match coefficients**: Adjust equations so that one variable has the same coefficient in both equations.
    \text{Example: multiplying \(2x + y = 7\) by 3 to get \(6x + 3y = 21\)}.
  • **Addition/Subtraction to eliminate a variable**: Combine equations to cancel out one variable.
    \text{Example: \(6x + 3y + 4x - 3y = 21 - 16\) results in \(10x = 5\)}.
  • **Solving for the remaining variable**: Use basic algebra to solve for the single variable left in the equation.
    \text{Example: \(10x = 5\) leads to \(x = \frac{1}{2}\)}.

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