Chapter 3: Problem 54
(a) complete the table of solutions. (b) graph the equation. $$ \begin{aligned} &2 x+y=-8\\\ &\begin{array}{|l|l|} \hline x & y \\ \hline 0 & \\ \hline & 0 \\ \hline 3 & \\ \hline \end{array} \end{aligned} $$
Short Answer
Expert verified
Table: \(0, -8\); \(-4, 0\); \(3, -14\). Graph: A line through these points.
Step by step solution
01
- Understand the Equation
Given the equation: \(2x + y = -8\)This linear equation is in the form \(Ax + By = C\).
02
- Solve for \(y\) When \(x = 0\)
Substitute \(x = 0\) into the equation:\(2(0) + y = -8\)This simplifies to:\(y = -8\)So, when \(x = 0\), \(y = -8\).
03
- Solve for \(x\) When \(y = 0\)
Substitute \(y = 0\) into the equation:\(2x + 0 = -8\)This simplifies to:\(2x = -8\)Divide by 2:\(x = -4\)So, when \(y = 0\), \(x = -4\).
04
- Solve for \(y\) When \(x = 3\)
Substitute \(x = 3\) into the equation:\(2(3) + y = -8\)This simplifies to:\(6 + y = -8\)Subtract 6 from both sides:\(y = -14\)So, when \(x = 3\), \(y = -14\).
05
- Fill in the Table
Using the values calculated:\(x = 0, y = -8\)\(x = -4, y = 0\)\(x = 3, y = -14\)Complete the table as follows:\(\begin{array}{|l|l|}\hlinex & y \hline0 & -8 \hline-4 & 0 \hline3 & -14 \hline\end{array}\)
06
- Plot the Points and Graph the Equation
On a coordinate plane, plot the points \((0, -8)\), \((-4, 0)\), and \((3, -14)\). Draw a straight line through these points to represent the equation \(2x + y = -8\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
solving equations
A linear equation is an equation that forms a straight line when plotted on a graph. To solve a linear equation, you need to find the values of the variables that make the equation true. Let's consider the equation given: \(2x + y = -8\). This equation shows how the variables \(x\) and \(y\) relate to each other.
To solve for \(y\) when \(x = 0\), you substitute \(0\) for \(x\) in the equation: \(2(0) + y = -8\). This simplifies to \(y = -8\).
Next, to solve for \(x\) when \(y = 0\), substitute \(0\) for \(y\) in the equation: \(2x + 0 = -8\), which simplifies to \(2x = -8\). Dividing both sides by 2, we get \(x = -4\).
Lastly, to solve for \(y\) when \(x = 3\), substitute \(3\) for \(x\) in the equation: \(2(3) + y = -8\), which simplifies to \(6 + y = -8\). Subtracting 6 from both sides, we get \(y = -14\).
To solve for \(y\) when \(x = 0\), you substitute \(0\) for \(x\) in the equation: \(2(0) + y = -8\). This simplifies to \(y = -8\).
Next, to solve for \(x\) when \(y = 0\), substitute \(0\) for \(y\) in the equation: \(2x + 0 = -8\), which simplifies to \(2x = -8\). Dividing both sides by 2, we get \(x = -4\).
Lastly, to solve for \(y\) when \(x = 3\), substitute \(3\) for \(x\) in the equation: \(2(3) + y = -8\), which simplifies to \(6 + y = -8\). Subtracting 6 from both sides, we get \(y = -14\).
- When \(x = 0\), \(y = -8\)
- When \(y = 0\), \(x = -4\)
- When \(x = 3\), \(y = -14\)
graphing solutions
Graphing solutions of a linear equation involves plotting points on the coordinate plane that satisfy the equation and then drawing a line through these points.
For the given equation \(2x + y = -8\), we have identified three solutions: \( (0, -8) \), \( (-4, 0) \), and \( (3, -14) \). To graph these solutions:
After plotting these points, draw a straight line through them, representing the graph of the equation \(2x + y = -8 \). This line shows all possible solutions of the equation on the coordinate plane.
For the given equation \(2x + y = -8\), we have identified three solutions: \( (0, -8) \), \( (-4, 0) \), and \( (3, -14) \). To graph these solutions:
- First, place the point \( (0, -8) \) on the graph. This point is found where \( x = 0 \) and \( y = -8 \).
- Next, place the point \( (-4, 0) \) on the graph. This is where \( x = -4 \) and \( y = 0 \).
- Finally, place the point \( (3, -14) \) on the graph. This point corresponds to \( x = 3 \) and \( y = -14 \).
After plotting these points, draw a straight line through them, representing the graph of the equation \(2x + y = -8 \). This line shows all possible solutions of the equation on the coordinate plane.
coordinate plane plotting
The coordinate plane is a two-dimensional surface on which we can plot points, lines, and curves. It consists of two perpendicular lines: the horizontal axis (x-axis) and the vertical axis (y-axis). The point where these axes intersect is called the origin, labeled \( (0,0) \).
Each point on the coordinate plane is determined by an \(x\)-value and a \(y\)-value, written as an ordered pair \( (x, y) \). The x-value tells you how far to move left or right from the origin, while the y-value tells you how far to move up or down.
For example, the point \( (-4, 0) \) means you move 4 units to the left along the x-axis and stay on the y-axis since the y-value is 0.
In our equation \(2x + y = -8\), plotting points \( (0, -8) \), \( (-4, 0) \), and \( (3, -14) \) on the coordinate plane helps visualize the relationship between \(x\) and \(y\). Drawing straight lines through these points helps illustrate how the solutions form a linear path across the plane.
Each point on the coordinate plane is determined by an \(x\)-value and a \(y\)-value, written as an ordered pair \( (x, y) \). The x-value tells you how far to move left or right from the origin, while the y-value tells you how far to move up or down.
For example, the point \( (-4, 0) \) means you move 4 units to the left along the x-axis and stay on the y-axis since the y-value is 0.
In our equation \(2x + y = -8\), plotting points \( (0, -8) \), \( (-4, 0) \), and \( (3, -14) \) on the coordinate plane helps visualize the relationship between \(x\) and \(y\). Drawing straight lines through these points helps illustrate how the solutions form a linear path across the plane.