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(a) use roster notation to represent the domain. (b) use roster notation to represent the range. For an order of 4 to 11 cigarette waste cans, $$C(x)=\left(\frac{\$ 61.50}{1 \text { can }}\right) x$$ represents the relationship of the number of waste cans ordered, \(x\), and the cost of the order, \(C(x)\)

Short Answer

Expert verified
Domain: \( \{4, 5, 6, 7, 8, 9, 10, 11\} \) Range: \( \{246, 307.50, 369, 430.50, 492, 553.50, 615, 676.50\} \)

Step by step solution

01

Understand the Domain

The domain represents all the possible values of the independent variable, which is the number of waste cans ordered, represented by variable \(x\). Given that the number of waste cans ordered ranges from 4 to 11, the domain is all the integers from 4 to 11.
02

Represent the Domain using Roster Notation

In roster notation, the domain is written as a set containing all the possible values of \(x\). Thus, the domain is: \( \{4, 5, 6, 7, 8, 9, 10, 11\} \).
03

Understand the Range

The range represents all the possible values of the dependent variable, which is the cost of the order, represented by \(C(x)\). We need to calculate the cost for each value of \(x\) in the domain.
04

Calculate the Range Values

Use the formula \( C(x) = 61.50 \times x \) to calculate the cost for each value of \( x \) in the domain: For \( x = 4 \), \( C(4) = 61.50 \times 4 = 246 \) For \( x = 5 \), \( C(5) = 61.50 \times 5 = 307.50 \) For \( x = 6 \), \( C(6) = 61.50 \times 6 = 369 \) For \( x = 7 \), \( C(7) = 61.50 \times 7 = 430.50 \) For \( x = 8 \), \( C(8) = 61.50 \times 8 = 492 \) For \( x = 9 \), \( C(9) = 61.50 \times 9 = 553.50 \) For \( x = 10 \), \( C(10) = 61.50 \times 10 = 615 \) For \( x = 11 \), \( C(11) = 61.50 \times 11 = 676.50 \)
05

Represent the Range using Roster Notation

In roster notation, the range is the set of all calculated values of \(C(x)\). Thus, the range is: \(\{246, 307.50, 369, 430.50, 492, 553.50, 615, 676.50\}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Domain
The domain of a function includes all the possible input values for the independent variable. In our exercise, the independent variable is the number of cigarette waste cans ordered, represented by \( x \). Since the problem specifies that orders can range from 4 to 11 cans, the domain consists of the integers 4 through 11.
To express this using roster notation, we list all these values in a set: \(\text{Domain} = \{ 4, 5, 6, 7, 8, 9, 10, 11 \}\).
This means that only these specific values are allowed inputs for the function representing the number of cigarette waste cans ordered.
Calculating and Representing the Range
The range includes all possible output values of the dependent variable. In this exercise, the dependent variable is the cost of the order, represented by \( C(x) \).
We calculate the cost using the formula \( C(x) = 61.50 \times x \), for every value in the domain:
\(\begin{align*} C(4) &= 61.50 \times 4 = 246, \ C(5) &= 61.50 \times 5 = 307.50, \ C(6) &= 61.50 \times 6 = 369, \ C(7) &= 61.50 \times 7 = 430.50, \ C(8) &= 61.50 \times 8 = 492, \ C(9) &= 61.50 \times 9 = 553.50, \ C(10) &= 61.50 \times 10 = 615, \ C(11) &= 61.50 \times 11 = 676.50 \ \end{align*}\)
Expressing this in roster notation, we get: \(\text{Range} = \{246, 307.50, 369, 430.50, 492, 553.50, 615, 676.50\}\).
This shows all the possible values for the cost depending on the number of cans ordered.
Understanding the Cost Function
A cost function helps us understand the relationship between the number of items ordered and the total cost. In our problem, the cost function is given by \(C(x) = 61.50 \times x\), where \(C(x)\) is the total cost and \(x\) is the number of cigarette waste cans ordered.
Here are the key components in this function:
  • The coefficient 61.50 represents the cost per single can.
  • The variable \( x \) represents the quantity of waste cans ordered.

By using this function, you can easily calculate the total cost for any quantity of cans within the domain. For example, if five cans are ordered, the total cost would be \(C(5) = 61.50 \times 5 = 307.50\). This straightforward relationship helps in budgeting and planning for any number of cans you may need within the given range.

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