Chapter 2: Problem 58
Solve \(V=\frac{L W T}{144}\) for \(W\).
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Chapter 2: Problem 58
Solve \(V=\frac{L W T}{144}\) for \(W\).
These are the key concepts you need to understand to accurately answer the question.
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For exercises 93-96, the completed problem has one mistake. (a) Describe the mistake in words, or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: Solve: \(-2 x+12>36\) Incorrect Answer: \(-2 x+12>36\) $$ \begin{aligned} -12 &-12 \\ \hline-2 x+0 &>24 \\ \frac{-2 x}{-2} &>\frac{24}{-2} \\ x &>-12 \end{aligned} $$
a. Solve \(A=\frac{h\left(b_{1}+b_{2}\right)}{2}\) for \(b_{1}\). b. One of the bases \(b_{1}\) of a trapezoid is \(10 \mathrm{in}\)., the height is 4 in., and the area is 70 in. \({ }^{2}\). Find the other base \(b_{2}\).
For exercises 37-52, (a) solve. (b) use a number line graph to represent the solution. (c) check the direction of the inequality sign. $$ \frac{1}{12}>\frac{x}{96} $$
For problems \(89-92\), do the arithmetic with a calculator. The volume \(V\) of a beaker of turpentine is \(325 \mathrm{~mL}\), and the mass \(M\) of the turpentine is \(283.16 \mathrm{~g}\). Use the formula \(D=\frac{M}{V}\) to find the density of the turpentine. Round to the nearest thousandth.
For exercises 53-62, (a) clear the fractions or decimals and solve. (b) check the direction of the inequality sign. $$ -0.98 p+4 \geq-0.18 p+8 $$
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