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Chapter 1: Problem 110
\(\left(25-5^{2}\right) \div 10\)
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The intensity of \(\mathrm{X}\)-ray radiation depends on the distance from the source of radiation. If the distance from the source of radiation changes from \(D_{1}\) to \(D_{2}\), the intensity changes from intensity \(I_{1}\) to \(I_{2}\). The formula for finding the new intensity is \(I_{2}=\frac{I_{1} \cdot\left(D_{1}\right)^{2}}{\left(D_{2}\right)^{2}}\). When \(D_{1}\) is \(25 \mathrm{~m}\), the intensity \(I_{1}\) is 620 roentgen per hour. Find the intensity of radiation \(I_{2}\) if \(D_{2}\) is \(5 \mathrm{~m}\).
Problem: Find the volume of a cylinder with a diameter of 14 in. and a height of \(2 \mathrm{ft}\). Write the answer in cubic inches. Use \(\pi \approx 3.14\). Incorrect Answer: \(V=\pi r^{2} h\) $$ \begin{aligned} &V=(3.14)(7 \text { in. })^{2}(2 \mathrm{ft}) \\ &V=(3.14)\left(49 \text { in. }^{2}\right)(2 \mathrm{ft}) \\ &V=307.72 \text { in. }^{3} \end{aligned} $$
\(5^{2}\)
The shape of a building lot is a trapezoid with bases that measure \(150 \mathrm{ft}\) and \(400 \mathrm{ft}\). The height is \(220 \mathrm{ft}\). Find the area of the lot.
Find the volume of a sphere with a diameter of \(15 \mathrm{in}\).
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