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Use substitution to prove the following statement: if \(12 \mid n\) and \(n \mid 4 m,\) where \(n\) and \(m\) are integers, then \(3 \mid m\). ("Hint ")

Short Answer

Expert verified
3 \mid m

Step by step solution

01

Express the Divisibility Condition

First, understand and express the given divisibility conditions. If \(12 \mid n\), then \(n = 12k\) for some integer \(k\). Moreover, if \(n \mid 4m\), then \(4m = nq\) for some integer \(q\).
02

Substitute n

Substitute \(n = 12k\) into the second condition: \(4m = nq\). Thus, \(4m = 12kq\).
03

Simplify the Equation

Divide both sides of the equation \(4m = 12kq\) by 4: \(m = 3kq\).
04

Conclude the Divisibility

Since \(m\) can be written as \(m = 3kq\), it is clear that \(m\) is divisible by 3. Thus, \(3 \mid m\) is proven.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

substitution
Substitution is a powerful technique in algebra and number theory. To understand substitution, think of replacing a variable with another value or expression to simplify a problem. In our example, we used substitution to prove divisibility. Here's how:

First, we identified that if 12 divides n, then n can be written as a multiple of 12. So, we wrote n as 12k where k is an integer. This substitution helped simplify the problem.

Next, we knew that n divides 4m. By substituting n with 12k, we transformed the equation 4m = nq into 4m = 12kq. This substitution made the equation easier to work with, leading us to the next steps in proving divisibility.

Substitution helps break down complex problems into simpler parts by replacing variables with known values or expressions.
divisibility rules
Divisibility rules are guidelines that help us determine if one number is divisible by another without performing long division. In this problem, we focus on the rules for 12 and 3.

For 12 to divide a number, that number must be divisible by both 3 and 4. This is because 12 is the product of these two numbers. So, any number divisible by 12 is automatically divisible by 3 and 4.

In the problem, we found that 12 divides n, indicating that n is a multiple of 12. When simplifying the equation to m = 3kq, we observed that m is written as a product of 3, which means m is divisible by 3.

Understanding these rules simplifies checking for divisibility quickly, aiding in solving complex number problems in an efficient manner.
integer properties
Integer properties are essential in various areas of mathematics, especially in number theory and algebra. These properties include understanding integers' behavior under different operations such as addition, multiplication, and division.

In our exercise, we worked with the properties of integers that relate to divisibility. We started with two integers, n and m, and leveraged the fact that if an integer divides another, their relationship can be expressed through multiplication with another integer (e.g., n = 12k, where k is an integer).

Later, the equation 4m = nq was simplified using integer properties. By substituting n = 12k, we got 4m = 12kq. Dividing both sides by 4, we found m = 3kq. This showed that m is an integer multiple of 3, hence proving that 3 divides m.

Being familiar with these properties allows us to manipulate and simplify equations effectively, leading to clear and logical proofs.

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Most popular questions from this chapter

(a) Suppose that \(a, b, c\) are integers and \((a / b)^{2}=c .\) Suppose further that \(a\) and \(b\) have no common factors except 1: that is, any integer \(x>1\) which divides \(b\) doesn't divide \(a\). Prove by contradiction that \(b=1\). (b) Generalize part (a): Suppose that \(a, b, c\) are integers and \((a / b)^{n}=c,\) where \(n\) is a positive integer. If \(a\) and \(b\) have no common factors, prove by contradiction that \(b=1\). (c) Use part (b) to prove the following: Let \(a\) and \(n\) be integers, both greater than \(1 .\) Let \(x\) be a real nth root of \(a .\) If \(x\) is not an integer, then \(x\) is irrational.

(a) Write down the complex number with real part 0 and imaginary part \(7 .\) (b) Write down a complex number whose real part is the negative of its imaginary part. (c) Write down a complex number that is also a real number.

Do imaginary numbers "really" exist? Write two or three sentences to express your opinion. \(^{6}\)

(a) Suppose that: \- \(a\) is a negative number; \- \(n\) is a positive integer; \(\bullet\) the equation \(x^{n}=a\) has a real solution for the unknown \(x\). What can you conclude about \(n ?\) Make a clear statement and prove your statement. (*Hint*) (b) Replace the condition \({ }^{4} n\) is a positive integer" in part (a) with " \(n\) is a negative integer." Now what can you conclude about \(n\) ? Make a clear statement and prove your statement.

(a) Sketch the function \(f(x)=x^{2}+9 .\) Does the function have any real roots? Explain how you can use the graph to answer this question. (b) Prove that the function \(f(x)=x^{2}+9\) has no real roots. (You may prove by contradiction, as before). (c) Graph the function \(f(x)=x^{6}+7 x^{2}+5\) (you may use a graphing calculator). Determine whether \(f(x)\) has any real roots. Prove your answer (note: a picture is not a proof!).

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