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From a group of 13 men, 6 women, 2 boys, and 4 girls, (a) In how many ways can a man, a woman, a boy, and a girl be selected? (b) In how many ways can a man or a girl be selected? (c) In how many ways can one person be selected?

Short Answer

Expert verified
(a) 624 ways, (b) 17 ways, (c) 25 ways.

Step by step solution

01

Identify Groups for Part A

To find how many ways we can select one person from each subgroup (man, woman, boy, and girl), we first identify the total number in each group. There are 13 men, 6 women, 2 boys, and 4 girls.
02

Calculate Selections for Part A

For each group, select one person: select a man in 13 ways, a woman in 6 ways, a boy in 2 ways, and a girl in 4 ways. Multiply these together to get the total number of ways to select one person from each group: \[13 \times 6 \times 2 \times 4 = 624.\]
03

Identify Groups for Part B

For selecting either a man or a girl, we identify the number of people in each group. There are 13 men and 4 girls.
04

Calculate Selections for Part B

Since we can choose a man or a girl, we simply add the number of men and the number of girls: \[13 + 4 = 17.\]
05

Identify Total Population for Part C

To find how many ways we can select one person from the entire group, we first determine the total population. There are 13 men, 6 women, 2 boys, and 4 girls.
06

Calculate Total Selections for Part C

Add up the number of people in all groups to find the total number of people: \[13 + 6 + 2 + 4 = 25.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Counting Principle
The Counting Principle is a fundamental concept in combinatorics that allows us to determine the total number of ways to perform a series of operations. This principle is particularly useful when you have a series of independent choices to make. The key idea is that if you have to make one choice in several different categories, you can find the total number of possible outcomes by multiplying the number of options in each category.

In the original exercise, when we needed to select a man, a woman, a boy, and a girl, the Counting Principle was applied. First, identify the number of options available in each group: 13 men, 6 women, 2 boys, and 4 girls. The total number of ways to make one selection from each group is the product of the number of options in each group:
  • Select a man: 13 ways
  • Select a woman: 6 ways
  • Select a boy: 2 ways
  • Select a girl: 4 ways
Therefore, the total number of ways to select a person from each group is calculated as: \[13 \times 6 \times 2 \times 4 = 624.\]

This approach reveals how systematically breaking down a problem using the Counting Principle can simplify complex selections into manageable calculations.
Combinations
Combinations refer to the different ways of selecting items from a larger set where the order of selection does not matter. In the context of combinatorics, it is useful when creating groups or choosing representatives without regard to order.

In the exercise provided, while the problem is simpler, the concept underlying Part B aligns with combinations since we're effectively grouping and considering options separately and then together. When determining how many ways a man or girl can be selected, we look at each group independently, then unite their counts:
  • There are 13 men.
  • There are 4 girls.
The number of ways to select a man or a girl is the total of these two independent groups: \[13 + 4 = 17.\]

Though this specific operation of adding does not depend on order, it introduces the basic conceptual layout of treating separate choices as combinations, where each element can belong to a set that contributes to a larger group selection.
Selections
Selections are a broad concept encompassing a variety of choosing methods, including those described by the Counting Principle and combinations. It refers to the act of choosing a subset from a given set of items. This operation is fundamental in problems of combinatorics where the building of subsets or the choice of representatives is concerned.

For Part C of the exercise, one needs to understand that the selection process involves considering the entire group as one. By recognizing each member of the group as a possible selection, the total number of selections is simply the sum of all individual elements.

Start with determining the entire population:
  • 13 men
  • 6 women
  • 2 boys
  • 4 girls
Putting it all together, the total selections from the entire group is calculated as:\[13 + 6 + 2 + 4 = 25.\]This method underscores that for selection problems, especially simple ones like choosing one out of many, adding all available choices gives the count directly.

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Most popular questions from this chapter

(a) [BB] Show that in any group of ten people, there is either a set of three mutual strangers or a set of four mutual friends. (b) Show that in any group of 20 people, there is cither a set of four mutual strangers or a set of four mutual friends.

Let \(A, B\) and \(C\) be sets. Prove that (a) \([\mathrm{BB}]|(A \oplus B) \cap C|=|A \cap C|+|B \cap C|\) \(-2|A \cap B \cap C|\) (b) \(|A \oplus B \oplus C|=|A|+|B|+|C|-2|A \cap B|-2 \mid A \cap\) \(|C|-2|B \cap C|+4|A \cap B \cap C|\)

(a) How many five-digit numbers can be formed using the digits \(0-9\) inclusive if repetitions are allowed? (Leading 0 's are not allowed: 07392 , for example, should not be considered a five-digit number.) (b) How many five-digit numbers can be formed if repetition is not allowed? (c) How many five-digit numbers have one or more repeated digits?

In Mark Salas, the 1991 Detroit Tigers had probably the only palindromic player in major league baseball (certainly, the only palindromic catcher). A palindrome is a word that reads the same forward and backward, like SALAS. (a) How many five-letter palindromes (not necessarily real words) can be made from the letters of the English alphabet? (b) How many eight-letter palindromes are possible? (c) How many "words" not exceeding eight letters in length are palindromes? (d) One of the most famous palindromes of all time is one which might have been uttered by Napoleon (had his native tongue been English): ABLE WAS | ERE I SAW ELBA. How many palindromes (not necessarily of real words) are this of this length?

(a) Let \(A\) be a set of seven (distinct) natural numbers none of which exceeds 21 . Prove that the sums of the elements in all the nonempty subsets of \(A\) are not distinct. (b) Improve the result of (a) by showing that the result holds under the assumption that the integers of \(A\) do not exceed 23 . (c) Assume none of the elements of \(A\) exceeds \(12 .\) At least how many subsets of \(A\) must have the same sum?

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