/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Prove the (first form of the) Pi... [FREE SOLUTION] | 91Ó°ÊÓ

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Prove the (first form of the) Pigeon-Hole Principle by mathematicai induction on \(m\), the number of boxes.

Short Answer

Expert verified
The Pigeon-Hole Principle is proved by induction for all \(m \geq 1\).

Step by step solution

01

Understand the Pigeon-Hole Principle

The Pigeon-Hole Principle states that if you have more pigeons than pigeon holes, then at least one pigeon hole must contain more than one pigeon. In formal terms, if you distribute more than \(m\) objects into \(m\) containers, at least one container will contain more than one object.
02

Base Case for Induction

To begin proving by induction, we need a base case. For \(m = 1\), if you have more than 1 object and only 1 container, all objects must go into that single container, thus satisfying the principle (since at least one container will have more than one object).
03

Induction Hypothesis

Assume that the Pigeon-Hole Principle holds for some arbitrary \(m = k\). This means that if you have \(k+1\) or more objects and only \(k\) containers, at least one container must hold more than one object.
04

Inductive Step

We need to show that the principle also holds for \(m = k + 1\). Consider having \(k + 2\) objects and \(k + 1\) containers. By the induction hypothesis, if you can fill \(k\) containers with \(k + 1\) objects such that at least one container has more than one object, adding just one more object increases both the number of objects to \(k + 2\) and containers to \(k + 1\), ensuring by contradiction that at least one container contains more than one object.
05

Conclusion of Inductive Proof

We've shown that if the principle holds for \(m = k\), it holds for \(m = k + 1\). Since the principle is true for the base case of \(m = 1\), by the principle of mathematical induction, it holds for all \(m \geq 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mathematical Induction
Mathematical induction is a fundamental proof technique used in mathematics to demonstrate that a given statement is true for all natural numbers. It is like a chain reaction, where proving one link in the chain unlocks the next. Here’s a simple breakdown:
  • Start with a base case. Prove that the statement holds for the initial value.
  • Use induction hypothesis. Assume that the statement holds for some arbitrary case.
  • Prove the inductive step. Show that if the statement is true for an arbitrary case, it must also be true for the next case.
Many mathematical theories leverage this powerful technique to build broader, universal truths from simple, foundational starting points.
Base Case
The base case is the first step in the process of mathematical induction. It's like testing the waters before diving in further. In our example of proving the Pigeonhole Principle, the base case involves checking whether the principle holds when there is just one box. For instance, if you have more than one object and only a single box to place them, clearly, all those objects must end up in that box.
This satisfies the principle because at least one box (in this case, the only box!) contains more than one object. Establishing this base case assures us of a solid foundation from which we can build more complex logical statements.
Inductive Step
The inductive step is where the magic of mathematical induction truly shines. Here, we assume that our statement holds for an arbitrary case, say for 'm = k'. This assumption is known as the induction hypothesis. The aim now is to show that if our statement holds for 'k', then it must hold for 'k + 1'.
In our Pigeonhole Principle example, we assume if you put one more object into 'k' boxes, at least one box ends up with more than one object. Now, adding another object and box (making it plus 1) should also lead to the same outcome. If our inductive logic holds true, the induction hypothesis proves the next case! It's like stepping stones leading us safely across a river.
Proof by Contradiction
A proof by contradiction involves assuming the opposite of what you want to prove and then showing that this assumption leads to a logical contradiction. It's akin to a Sherlock Holmes approach: eliminating the impossible leaves you with the truth.
In proving the Pigeonhole Principle, suppose contrary to our statement, each of the 'k' boxes contains at most one object. If we have more objects than boxes, this assumption results in a scenario where additional objects have no box to fit into without sharing, contradicting our initial contradictory assumption. Therefore, proving via contradiction helps to reaffirm the statement, showing logically impossible scenarios help solidify the heart of the principle.

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