Chapter 5: Problem 7
Let \(a_{1}, a_{2}, a_{3}, \ldots\) be the sequence defined by \(a_{1}=\frac{3}{2}\) and \(a_{n}=5 a_{n-1}-1\) for \(n \geq 2 .\) Write down the first six terms of this sequence. Guess a formula for \(a_{n}\) and prove that your guess is correct.
Short Answer
Expert verified
The sequence terms are \(\frac{3}{2}, \frac{13}{2}, \frac{63}{2}, \frac{313}{2}, \frac{1563}{2}, \frac{7813}{2}\). The formula is \(a_n = \frac{5^n - 1}{2}\).
Step by step solution
01
Calculate the First Term
We're given that the first term of the sequence is \(a_1 = \frac{3}{2}\). This is our starting point.
02
Calculate the Second Term
Use the recurrence relation \(a_n = 5a_{n-1} - 1\) to find the second term.\[a_2 = 5a_1 - 1 = 5 \times \frac{3}{2} - 1 = \frac{15}{2} - \frac{2}{2} = \frac{13}{2}\]
03
Calculate the Third Term
Again, apply the recurrence relation to find the third term.\[a_3 = 5a_2 - 1 = 5 \times \frac{13}{2} - 1 = \frac{65}{2} - \frac{2}{2} = \frac{63}{2}\]
04
Calculate the Fourth Term
Use the recurrence relation once more to find the fourth term.\[a_4 = 5a_3 - 1 = 5 \times \frac{63}{2} - 1 = \frac{315}{2} - \frac{2}{2} = \frac{313}{2}\]
05
Calculate the Fifth Term
Apply the recurrence relation to find the fifth term.\[a_5 = 5a_4 - 1 = 5 \times \frac{313}{2} - 1 = \frac{1565}{2} - \frac{2}{2} = \frac{1563}{2}\]
06
Calculate the Sixth Term
Finally, use the recurrence to find the sixth term.\[a_6 = 5a_5 - 1 = 5 \times \frac{1563}{2} - 1 = \frac{7815}{2} - \frac{2}{2} = \frac{7813}{2}\]
07
Identify the Pattern
Looking at the terms calculated: \(\frac{3}{2}, \frac{13}{2}, \frac{63}{2}, \frac{313}{2}, \frac{1563}{2}, \frac{7813}{2}\), observe that they resemble \(\frac{5^n-1}{2}\).
08
Prove the Formula by Induction
Assume \(a_k = \frac{5^k - 1}{2}\) holds true. For the base case \(n = 1\), \(a_1 = \frac{3}{2}\) matches. For the inductive step, if \(a_k = \frac{5^k - 1}{2}\), then \[a_{k+1} = 5a_k - 1 = 5\left(\frac{5^k - 1}{2}\right) - 1 = \frac{5^{k+1} - 5}{2} - \frac{2}{2} = \frac{5^{k+1} - 1}{2}\] This confirms the formula for all \(n\) by mathematical induction.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sequence Formula
To understand a sequence formula in the context of recurrence relations, one must first grasp how each term in a sequence is defined. This involves using a base term and a recurrence relation. In this problem, we start with the first term, \( a_1 = \frac{3}{2} \), and use the recurrence relationship \( a_n = 5a_{n-1} - 1 \) to generate further terms. By systematically applying this formula, we calculated the sequence's first six terms:
- \( a_1 = \frac{3}{2} \)
- \( a_2 = \frac{13}{2} \)
- \( a_3 = \frac{63}{2} \)
- \( a_4 = \frac{313}{2} \)
- \( a_5 = \frac{1563}{2} \)
- \( a_6 = \frac{7813}{2} \)
Mathematical Induction
Mathematical induction is a technique used to prove hypotheses about formulas or sequences. It is structured as a two-step logic process: the base case, and the inductive step. Here, it's used to verify the guessed sequence formula, \( a_n = \frac{5^n - 1}{2} \), accurately represents any term in the sequence.**Base Case:**
Start with the first term: we observe that \( a_1 = \frac{3}{2} \), aligning perfectly with our formula since \( \frac{5^1 - 1}{2} = \frac{3}{2} \). **Inductive Step:**
Assume it holds for \( n = k \), that is, \( a_k = \frac{5^k - 1}{2} \). For \( n = k+1 \), test the relation:
Start with the first term: we observe that \( a_1 = \frac{3}{2} \), aligning perfectly with our formula since \( \frac{5^1 - 1}{2} = \frac{3}{2} \). **Inductive Step:**
Assume it holds for \( n = k \), that is, \( a_k = \frac{5^k - 1}{2} \). For \( n = k+1 \), test the relation:
- Apply the recurrence relation \( a_{k+1} = 5a_k - 1 \)
- Substitute the formula for \( a_k \): \( 5 \left( \frac{5^k - 1}{2} \right) - 1 \)
- Transform this expression to match our conjecture: \( \frac{5^{k+1} - 1}{2} \)
Recursive Sequences
Recursive sequences rely on defining each term based on prior terms in the sequence, typically through a recurrence relation. They provide an approach to define complex patterns incrementally. In this specific example, the relation \( a_n = 5a_{n-1} - 1 \) shows how each element emerges from its predecessor by multiplying it by 5 and then subtracting 1.**Properties of Recursive Sequences:**
- **Initial Condition:** Establishes the starting point, which is essential for generating any further terms.
- **Recurrence Relation:** Guides the transformation from one term to the next.
- **Predictability:** Once understood, the sequence can be generated completely from the initial condition and the relation applied successively.
- **Application:** Useful in solving a vast array of problems, from computer algorithms to economic forecasting.