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91Ó°ÊÓ

Prove that McCarthy's 91 function equals 91 for all positive integers less than or equal to 101 .

Short Answer

Expert verified
We proved through induction that McCarthy's 91 function equals 91 for all positive integers less than or equal to 101. We started with the base case of n = 1 and showed that it resulted in 91. Next, we assumed the claim is true for an arbitrary value n = k, and used this to derive the claim for n = k+1. Finally, we demonstrated that the claim holds for all values in the specified range between 1 and 100. Thus, we have established that the McCarthy's 91 function indeed gives 91 for all positive integers within this range.

Step by step solution

01

Base Case

First, we will prove the base case for when n = 1. \(M(1)=M(M(1+11))=M(M(12))\) Since 12 > 100, we apply the definition of the function: \(M(12)=12-10=2\) Now we substitute this value back into the original function: \(M(1)=M(2)\)
02

Inductive Hypothesis

Assume that for an arbitrary \(n=k\), the function results in 91: \(M(k) = M(M(k+11)) = 91\)
03

Inductive Step

Now we need to prove the inductive step for n = k + 1: \(M(k+1) = M(M((k+1)+11)) = M(M(k+12))\) Since \(k+12 > 100\), we can apply the definition of the function: \(M(k+12)=(k+12)-10=k+2\) Now we substitute this value back into the original function: \(M(k+1)=M(k+2)\)
04

Analyzing M(k+2)

Since \(M(k) = 91\), and the function is defined to decrease by 10 for values above 100, we know that \(M(k+9)=101\). So, when n reaches the next value, i.e., k+10, the function will return 91 again: \(M(k+10)=M(k+9)-10 = 91\) Therefore, we know that \(M(k+11)=91\). We can now use this information to analyze \(M(k+2)\), with the assumption that \(M(k+11)=91\): \(M(k+2) = M(M((k+2)+11)) = M(M(k+13))\) Since \(M(k+11)=91\), we have \(M(k+13)>100\). Applying the definition of the function, we get: \(M(k+13)=(k+13)-10=k+3\) Substituting this back into the original function, we get: \(M(k+2)=M(k+3)\)
05

Conclusion

Since we have shown that the function results in 91 for an arbitrary value of n (in this case, through the inductive step), and we know that the function will return 91 for every value of n between 1 and 101, we have proven that McCarthy's 91 function equals 91 for all positive integers less than or equal to 101.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mathematical Induction
Mathematical induction is a powerful proof technique used in discrete mathematics, which is particularly effective for proving properties of functions, sequences, and sets that are defined recursively. It involves two critical steps: establishing the base case and proving the inductive step.

For the base case, one needs to show that a statement holds for the first element in the sequence. In the case of McCarthy's 91 function, the base case shows that when the input is the smallest possible value, the function indeed yields the desired result, which is 91. The student is typically advised to be very clear when determining the correct base case, as it is foundational to the rest of the proof.

The inductive step involves assuming the statement holds for an arbitrary case of the sequence (commonly denoted as 'n=k') and then proving it holds for the next case ('n=k+1'). In the exercise, once we have established that the McCarthy function holds for an arbitrary k, we must show it also holds for k+1. If these two steps are achieved, the proposition is then proven to hold for all elements of the sequence.
Recursive Functions
Recursive functions are a fundamental concept in both mathematics and computer science. A function is said to be recursive if it is defined in terms of itself. To avoid infinite loops or definitions, each recursive function must have a base case that stops the recursion.

In the McCarthy's 91 function, we observe recursion when the function uses its own previous values to calculate the new ones. For example, for any positive integer n, the function calls itself when n is less than or equal to 101. It's crucial for students to recognize the base case here, because it halts further recursion and thus provides a definitive result. If the argument exceeds 100, the recursion is halted and the computation proceeds directly.

Understanding recursion often involves tracking the function's behavior through its recursive calls. This might seem daunting, but breaking down the function calls as in the step by step solution provided, and thoroughly understanding the base case, can greatly simplify the concept.
Discrete Mathematics
Discrete mathematics forms the backbone of computer science and includes the study of discrete and quantized structures, unlike continuous mathematics. It encompasses a wide array of topics such as logic, set theory, graph theory, and combinatorics, in addition to mathematical induction and recursive functions.

In the context of McCarthy's 91 function, discrete mathematics principles are at play. Being defined for positive integers, the function is inherently discrete because it operates on individual numbers rather than an unbroken range. In educational contexts, the exploration of discrete functions like McCarthy's 91 function offers a valuable exercise in logical reasoning and understanding computational procedures without resorting to continuous methods or calculus.

When guiding students through exercises in discrete mathematics, it is pivotal to encourage them to approach problems methodically, often starting with small cases or examples to detect patterns before generalizing their findings through formal proof methods such as mathematical induction.

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Most popular questions from this chapter

Note that a product \(x_{1} x_{2} x_{3}\) may be parenthesized in two different ways: \(\left(x_{1} x_{2}\right) x_{3}\) and \(x_{1}\left(x_{2} x_{3}\right)\). Similarly, there are several different ways to parenthesize \(x_{1} x_{2} x_{3} x_{4}\). Two such ways are \(\left(x_{1} x_{2}\right)\left(x_{3} x_{4}\right)\) and \(x_{1}\left(\left(x_{2} x_{3}\right) x_{4}\right) .\) Let \(P_{n}\) be the number of different ways to parenthesize the product \(x_{1} x_{2} \cdots x_{n}\). Show that if \(P_{1}=1\), then $$ P_{n}=\sum_{k=1}^{n-1} P_{k} P_{n-k} \text { for all integers } n \geq 2 \text {. } $$ (It turns out that the sequence \(P_{1}, P_{2}, P_{3}, \ldots\) is the same as the sequence of Catalan numbers.)

Show that the sequence \(2,3,4,5, \ldots, 2+n, \ldots\), defined for \(n \geq 0\), satisfies the recurrence relation $$ t_{k}=2 t_{k-1}-t_{k-2} \text { for all integers } k \geq 2 \text {. } $$

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