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a. How many ways can three of the letters of the word \(A L G O R I T H M\) be selected and written in a row? b. How many ways can six of the letters of the word ALGORITHM be selected and written in a row? c. How many ways can six of the letters of the word ALGORITHM be selected and written in a row if the first letter must be \(A\) ? d. How many ways can six of the letters of the word ALGORITHM be selected and written in a row if the first two letters must be \(O R\) ?

Short Answer

Expert verified
The short answers for each part of the question are: a. There are \(504\) ways to select and arrange 3 letters of the word ALGORITHM. b. There are \(60,480\) ways to select and arrange 6 letters of the word ALGORITHM. c. There are \(13,440\) ways to select and arrange 6 letters of the word ALGORITHM when the first letter is A. d. There are \(840\) ways to select and arrange 6 letters of the word ALGORITHM when the first two letters are O and R.

Step by step solution

01

Count the number of letters

The word ALGORITHM has 9 letters.
02

Calculate permutations for 3 letters

Since we want to select 3 letters, we are looking for the number of permutations of 3 objects taken from 9. This can be calculated as P(9, 3) = 9! / (9-3)!
03

Calculate the result

Now, compute P(9, 3) = 9! / 6! = 9 × 8 × 7 = \(504\) So, there are 504 ways to select and arrange 3 letters of the word ALGORITHM. b.
04

Calculate permutations for 6 letters

Now, we want to select 6 letters from the word ALGORITHM. So, we need to find P(9, 6) = 9! / (9-6)!
05

Calculate the result

Compute P(9, 6) = 9! / 3! = 9 × 8 × 7 × 6 × 5 × 4 = \(60,480\) So, there are 60,480 ways to select and arrange 6 letters of the word ALGORITHM. c.
06

Apply the constraint

In this case, we have to choose 6 letters from ALGORITHM, but the first letter must be A. We now have to choose 5 letters from the remaining 8 (with A already selected), so we will compute P(8, 5).
07

Calculate the result

Compute P(8, 5) = 8! / (8-5)! = 8 × 7 × 6 × 5 × 4 = \(13,440\) So, there are 13,440 ways to select and arrange 6 letters of the word ALGORITHM when the first letter is A. d.
08

Apply the constraint

In this case, we need to select 6 letters from the ALGORITHM with the first two letters being O and R. We now have to choose 4 letters from the remaining 7 (with O and R already selected), so we will compute P(7, 4).
09

Calculate the result

Compute P(7, 4) = 7! / (7-4)! = 7 × 6 × 5 × 4 = \(840\) So, there are 840 ways to select and arrange 6 letters of the word ALGORITHM when the first two letters are O and R.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Mathematics
Discrete mathematics is an area of study that deals with mathematical structures that are fundamentally discrete rather than continuous. In essence, it involves countable, distinct elements that do not require the notion of 'in between' values. This field encompasses a wide range of topics such as logic, set theory, graph theory, and combinatorics, which specifically deals with counting and arrangement problems.

Within discrete mathematics, permutations are a fundamental concept, particularly when it comes to arranging objects in specific orders. A permutation is an arrangement of all or part of a set of objects, with regard to the order of the arrangement. For example, when looking at the different ways to arrange letters from a word like 'ALGORITHM', each unique sequence that can be made with the letters constitutes a different permutation. Understanding permutations is crucial in discrete mathematics as they are applied in various areas such as computer science algorithms, cryptographic systems, and even in organizing data structures.
Factorial Notation
Factorial notation is integral to combinatorics and permutations. The factorial of a non-negative integer, denoted by the exclamation mark (!), is the product of all positive integers less than or equal to that number. For instance, the factorial of 4, which is written as 4!, would be calculated as 4 × 3 × 2 × 1 = 24.

Factorials are particularly useful when determining the number of ways we can arrange a set number of objects. In the context of our problem with the word 'ALGORITHM', factorials help us calculate how many permutations exist depending on the number of letters we select. By using factorial notation, the complex process of counting each possible arrangement manually is eliminated, and we are provided with a powerful mathematical shortcut that simplifies computation significantly.
Combinatorics
Combinatorics is a branch of mathematics focused on counting, both as a means and an end in obtaining results, and certain properties of finite structures. It is closely related to many other areas of mathematics, such as algebra, probability, and number theory, and has applications in diverse fields including computer science, statistics, and biology.

Counting the number of possible arrangements or selections is a primary concern in combinatorics. The problems in the exercise with the word 'ALGORITHM' demonstrate different combinatorial situations. From selecting and arranging a subset of letters without any constraints to doing so with specific positions being predetermined, we see the richness of counting techniques available. By applying the principles of combinatorics, we are able to swiftly navigate through complex scenarios, quantifying the possibilities with clear, logical steps and mathematical expressions.

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Most popular questions from this chapter

Assume that birthdays are equally likely to occur in any one of the 12 months of the year. a. Given a group of four people, \(A, B, C\), and \(D\). What is the total number of ways in which birth months could be associated with \(A, B, C\), and \(D ?\) (For instance, \(A\) and \(B\) might have been born in May, \(C\) in September, and \(D\) in February, As another example, \(A\) might have been born in January, \(B\) in June, \(C\) in March, and \(D\) in October.) b. How many ways could birth months be associated with \(A, B, C\), and \(D\) so that no two people would share the same birth month? c. How many ways could birth months be associated with \(A, B, C\), and \(D\) so that at least two people would share the same birth month? d. What is the probability that at least two people out of \(A, B, C\), and \(D\) share the same birth month? e. How large must \(n\) be so that in any group of \(n\) people, the probability that two or more share the same birth month is at least \(50 \mathrm{~g}\) ?

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a. Prove that if \(A\) and \(B\) are any events in a sample space \(S\), with \(P(B) \neq 0\), then \(P\left(A^{c} \mid B\right)=1-P(A \mid B)\). b. Explain how this result justifies the following statements: (1) If the probability of a false negative on a test for a condition is \(4 \%\), then there is a \(96 \%\) probability that a person who does not have the condition will have a negative test result. (2) If the probability of a false positive on a test for a condition is \(1 \%\), then there is a 995 probability that a person who does have the condition will test positive for it.

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