/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 In 1-4, use the fact that in bas... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In 1-4, use the fact that in baseball's World Series, the first team to win four games wins the series. How many ways can a World Series be played if team \(A\) wins four games in a row?

Short Answer

Expert verified
There are 4 ways a World Series can be played if team \(A\) wins four games in a row, which include team \(A\) winning games 1, 2, 3, and 4; games 2, 3, 4, and 5; games 3, 4, 5, and 6; or games 4, 5, 6, and 7.

Step by step solution

01

Calculate the total number of games

In a World Series, the first team to win four games wins the series. Since there are only two teams, this means that there can be a maximum of 7 games played (team A wins 4 games and team B wins 3 games).
02

Enumerate the possible outcomes

Team \(A\) needs to win four games in a row, so there are the following possibilities for team \(A\) to win the series: - Team \(A\) wins games 1, 2, 3, and 4 - Team \(A\) wins games 2, 3, 4, and 5 - Team \(A\) wins games 3, 4, 5, and 6 - Team \(A\) wins games 4, 5, 6, and 7
03

Count the number of ways

Since there are 4 possible scenarios where team \(A\) can win four games in a row, there are 4 ways that a World Series can be played if team \(A\) wins four games in a row.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Counting Principles
At the core of solving combinatorial problems in sports is an understanding of counting principles. These principles provide the foundation to calculate how many different outcomes or arrangements are possible within a given set of conditions. Two of the most fundamental counting principles are the 'rule of product' and the 'rule of sum.' The 'rule of product', also known as the multiplication principle, states that if one event can occur in 'm' ways and a second independent event can occur in 'n' ways, then the two events can occur in 'm * n' ways when combined. Conversely, the 'rule of sum' applies when considering alternative possibilities: if one event can take place in 'm' ways and another mutually exclusive event in 'n' ways, then there are 'm + n' ways for either event to happen.

In the scenario of the World Series, we're observing a sequence of victories, and the counting principle in use is remarkably simple. Since the series ends as soon as team A wins four games, we don't require complex permutations; instead, we find that there are 4 straightforward sequences that lead to this outcome, demonstrating how counting principles underpin even the simplest combinatorial settings in sports.
Enumeration of Outcomes
Enumeration is methodical counting, and in sporting events like the World Series, it involves listing all possible outcomes that adhere to the rules of the game. This is crucial because it helps us not to overcount or undercount the possibilities. It’s a practical application of the counting principles discussed earlier.

For instance, when team A must win four consecutive games to claim victory in the World Series, we enumerate the series starting points for team A's winning streak: it can start at game 1, game 2, game 3, or game 4. This ensures every winning combination is considered without duplication. The art of enumeration often involves illustrating scenarios or using a systematic approach to ensure completeness and accuracy—a critical step for problem-solvers and strategists alike.
Combinatorial Problems
Combinatorial problems are puzzles where we calculate the number of ways certain events can occur. They are pervasive in sports analytics, strategic game planning, and even in predicting outcomes. These problems require a blend of logic and mathematical tools like permutations, combinations, and variations depending on the restrictions of the problem.

In this World Series example, the combinatorial problem is simple: how many ways can team A win four games in a row? The answer involves recognizing the limited sequences where team A's victory is uninterrupted by a loss. Complex combinatorial problems might require more sophisticated techniques, but this example is a stepping stone towards understanding how choices and arrangements intersect within a structured framework like a sports tournament. These problems ultimately shape our understanding of probability, and how likely certain sporting outcomes are to occur, hence their significance in predictive models.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

a. A bit string is a finite sequence of 0 's and 1 's. How many bit strings have length 8 ? b. How many bit strings of length 8 begin with three 0 's? c. How many bit strings of length 8 begin and end with a 1 ? d. In Section \(1.5\) we showed how integers can be represented by strings of 0 's and 1 's inside a digital computer. In fact, through various coding schemes, strings of 0 's and l's can be used to represent all kinds of symbols. One commonly used code is the Extended Binary-Coded Decimal Interchange Code (EBCDIC) in which each symbol has an 8-bit representation. How many distinct symbols can be represented by this code?

Complete the row of Pascal's triangle that corresponds io \(n=7\).

A group of eight people are attending the movies together. a. Two of the eight insist on sitting side-by-side. In how many ways can the eight be seated together in a row? b. Two of the people do not like each other and do not want to sit side-by- side. Now how many ways can the eight be seated together in a row?

Assume that birthdays are equally likely to occur in any one of the 12 months of the year. a. Given a group of four people, \(A, B, C\), and \(D\). What is the total number of ways in which birth months could be associated with \(A, B, C\), and \(D ?\) (For instance, \(A\) and \(B\) might have been born in May, \(C\) in September, and \(D\) in February, As another example, \(A\) might have been born in January, \(B\) in June, \(C\) in March, and \(D\) in October.) b. How many ways could birth months be associated with \(A, B, C\), and \(D\) so that no two people would share the same birth month? c. How many ways could birth months be associated with \(A, B, C\), and \(D\) so that at least two people would share the same birth month? d. What is the probability that at least two people out of \(A, B, C\), and \(D\) share the same birth month? e. How large must \(n\) be so that in any group of \(n\) people, the probability that two or more share the same birth month is at least \(50 \mathrm{~g}\) ?

Use mathematical induction to prove the general inclusion/exclusion rule: If \(A_{1}, A_{2}, \ldots, A_{n}\) are finite sets, then $$ \begin{aligned} N\left(A_{1} \cup A_{2} \cup \ldots \cup A_{n}\right) & \sum_{1 \leq i \leq n} N\left(A_{i}\right)-\sum_{1 \leq i=j \leq n} N\left(A_{i} \cap A_{j}\right) \\\ &+\sum_{1 \leq j

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.