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a. How many integers from 1 through 1,000 are multiples of 2 or multiples of 9 ? b. Suppose an integer from I through 1,000 is chosen at random. Use the result of part (a) to find the probability that the integer is a multiple of 2 or a multiple of \(9 .\) c. How many integers from 1 through 1,000 are neither multiples of 2 nor multiples of 9 ?

Short Answer

Expert verified
a. There are 556 integers between 1 and 1000 that are multiples of 2 or 9. b. The probability of choosing an integer between 1 and 1000 that is a multiple of 2 or 9 is \(0.556\). c. There are 444 integers between 1 and 1000 that are neither multiples of 2 nor 9.

Step by step solution

01

Counting multiples of 2

We need to determine how many integers between 1 and 1000 are multiples of 2. To do this, divide 1000 by 2, and round the result down to the nearest integer: \[ \lfloor \frac{1000}{2} \rfloor = 500 \] So, there are 500 multiples of 2 between 1 and 1000.
02

Counting multiples of 9

Next, we need to determine how many integers between 1 and 1000 are multiples of 9. Divide 1000 by 9 and round the result down to the nearest integer: \[ \lfloor \frac{1000}{9} \rfloor = 111 \] So, there are 111 multiples of 9 between 1 and 1000.
03

Counting multiples of 18

There are also integers that are multiples of both 2 and 9. We need to count them only once. To do this, we'll count how many integers between 1 and 1000 are multiples of 18 (their least common multiple). Divide 1000 by 18 and round the result down to the nearest integer: \[ \lfloor \frac{1000}{18} \rfloor = 55 \] So, there are 55 multiples of 18 between 1 and 1000.
04

Counting integers that are multiples of 2 or 9

Using the principle of inclusion-exclusion, we can now calculate the total number of multiples of 2 or 9 by adding the counts from steps 1 and 2, then subtracting the count from step 3: \[ 500 + 111 - 55 = 556 \] So, there are 556 integers between 1 and 1000 that are multiples of 2 or 9.
05

Calculating probability

Now, we will use the result from step 4 to find the probability of choosing an integer between 1 and 1000 that is a multiple of 2 or 9. Divide the number of multiples of 2 or 9 (556) by the total number of integers between 1 and 1000 (1000): \[ P(\text{multiple of 2 or 9}) = \frac{556}{1000} = 0.556 \] So, the probability of choosing an integer that is a multiple of 2 or 9 is 0.556.
06

Counting integers that are neither multiples of 2 nor 9

Lastly, we need to find the total number of integers between 1 and 1000 that are neither multiples of 2 nor 9. To do this, subtract the count of multiples of 2 or 9 (556) from the total number of integers between 1 and 1000 (1000): \[ 1000 - 556 = 444 \] So, there are 444 integers between 1 and 1000 that are neither multiples of 2 nor 9.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inclusion-Exclusion Principle
Understanding the inclusion-exclusion principle is key to solving many problems in discrete mathematics, especially those involving counting and probability. The principle provides a way to count the overall number of entities that are part of at least one of several categories without double-counting those that fit into multiple categories.

For example, when counting the integers from 1 to 1,000 that are multiples of either 2 or 9, we initially add the number of multiples for each integer. However, this count will include some numbers twice – those that are multiples of both 2 and 9, so we must subtract the count of these shared multiples to get the accurate total. The shared multiples are identified by their least common multiple (LCM), which in this case is 18. The principle succinctly keeps the balance in our calculations and helps us find precise counts.
Multiples of Integers
Multiples of an integer refer to the set of numbers that can be expressed as that integer multiplied by the integers (1, 2, 3, ... and so on). For instance, the multiples of 2 are all the even numbers, as each can be expressed as 2 times some other integer. Similarly, the multiples of 9 are those numbers that are obtainable by multiplying 9 by any integer.

Multiples hold an integral place in various branches of mathematics and, in particular, are crucial for topics such as least common multiples, divisibility, and number theory. In our textbook exercise, we leverage the straightforward way to find the count of multiples within a range by dividing the upper bound (in this case, 1,000) by the integer we are interested in.
Probability Calculation
Probability in discrete mathematics is about the likelihood of occurrence of a particular event within a set of possible outcomes. We express this likelihood as a number between 0 and 1, where 0 indicates impossibility and 1 represents certainty. The formula to calculate the probability of an event is the ratio of the number of favorable outcomes to the total number of possible outcomes.

In our exercise, the event of interest is picking a number that is a multiple of 2 or 9. After utilizing the inclusion-exclusion principle to avoid double counting, the number of favorable outcomes (multiples of 2 or 9) can be placed over the total count of outcomes, which is all numbers between 1 and 1,000.
Least Common Multiple
The least common multiple (LCM) of two integers is the smallest positive integer that is a multiple of both. It plays a significant role in solving problems that involve finding commonalities between different sets of multiples. For instance, in problems where two processes with different periodic cycles must sync up, the LCM gives the point at which this synchrony occurs.

In the context of our textbook problem, the LCM of 2 and 9 is 18. This LCM shows the intervals at which the multiples of both numbers coincide. Knowing the LCM helps in utilizing the inclusion-exclusion principle accurately, as it identifies the overlap that we need to account for to avoid double counting.

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Most popular questions from this chapter

Three officers-a president, a treasurer, and a secretaryare to be chosen from among four people: Ann, Bob, Cyd, and Dan. Suppose that Bob is not qualified to be treasurer and Cyd's other commitments make it impossible for her to be secretary. How many ways can the officers be chosen? Can the multiplication rule be used to solve this problem?

a. How many even integers are in the set $$ \\{1,2,3, \ldots, 100\\} ? $$ b. How many odd integers are in the set $$ \\{1,2,3, \ldots, 100\\} ? $$ c. How many ways can two integers be selected from the set \(\\{1,2,3, \ldots, 100\\}\) so that their sum is even? d. How many ways can two integers be selected from the set \(\\{1,2,3, \ldots, 100\\}\) so that their sum is odd?

On an \(8 \times 8\) chessboard, a rook is allowed to move any number of squares either horizontally or vertically. How many different paths can a rook follow from the bottom-left square of the board to the top-right square of the board if all moves are to the right or upward?

Redo exercise 10 assumuing that the first um contains 4 blue balls and 16 white balls and the second urn contains 10 blue balls and 9 white balls.

Modify Example \(6.2 .4\) by supposing that a PIN must not begin with any of the letters \(\mathrm{A}-\mathrm{M}\) and must end with a digit. Continue to assume that no symbol may be used more than once and that the total number of PINs is to be determined. a. Find the error in the following "solution." "Constructing a PIN is a four-step process. Step 1: Choose the left-most symbol. Step 2: Choose the second symbol from the left. Step 3: Choose the third symbol from the left. Step 4: Choose the right-most symbol. Because none of the thirteen letters from A through M may be chosen in step 1 , there are \(36-13=23\) ways to perform step 1. There are 35 ways to perform step 2 and 34 ways to perform step 3 because previously used symbols may not be used. Since the symbol chosen in step 4 must be a previously unused digit, there are \(10-3=7\) ways to perform step 4 . Thus there are \(23 \cdot 35 \cdot 34 \cdot 7=191,590\) different PINs that satisfy the given conditions." b. Reorder steps 1-4 in part (a) as follows: Step 1: Choose the right-most symbol. Step 2: Choose the left-most symbol. Step 3: Choose the second symbol from the left. Step 4: Choose the third symbol from the left. Use the multiplication rule to find the number of PINs that satisfy the given conditions.

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