/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Each of the statements in \(20-2... [FREE SOLUTION] | 91Ó°ÊÓ

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Each of the statements in \(20-23\) is true. For each, (a) rewrite the statement using a variable or variables and the form \(V\) if ___ then ___ and (b) write the first sentence of a proof (the "starting point") and the last sentence of a proof (the "conclusion to be shown"). Note that you do not need to understand the statements in order to be able to do these exercises. 20\. For all integers \(m\), if \(m>1\) then \(0<\frac{1}{m}<1\).

Short Answer

Expert verified
(a) Rewrite the statement as: For all integers \(m\), if \(m > 1\), then \(0 < \frac{1}{m} < 1\). (b) Starting point: Let \(m\) be an integer such that \(m > 1\). Conclusion: Thus, we have shown that for the given integer \(m\), the inequality \(0 < \frac{1}{m} < 1\) holds true.

Step by step solution

01

Rewrite the given statement

Rewrite the statement as: For all integers \(m\), if \(m > 1\), then \(0 < \frac{1}{m} < 1\).
02

Write the starting point of the proof

Let \(m\) be an integer such that \(m > 1\).
03

Write the conclusion of the proof

Thus, we have shown that for the given integer \(m\), the inequality \(0 < \frac{1}{m} < 1\) holds true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mathematical Proof Structure
Understanding the structure of a mathematical proof is crucial for anyone navigating through discrete mathematics. A proof is a logical argument that demonstrates the truth of a statement, and it usually follows a standard format. First, it begins with the assertion, stating what you aim to prove. The next segment is the hypothesis, which outlines the conditions under which the assertion holds true.

Then comes the proof itself, which is the body of the argument where logical deductions are made based on the hypothesis and known principles. Finally, the conclusion reaffirms the assertion, ensuring that what was set out to be proven has indeed been established. Using our rewriting and representation skills, we express all these elements clearly.

For instance, in the exercise provided, we start by restating the original condition with variables, creating a clear hypothesis. The proof then logically demonstrates why the hypothesis leads to the assertion, ending with a conclusion that restates the proof's achievement in showing the initial claim to be true.
Variable Representation in Mathematics
The use of variables is the cornerstone of representing mathematical concepts succinctly and universally. Variables, typically denoted by letters, stand in for unknown values or values that can change. In mathematics, clear representation is paramount as it prevents ambiguity and promotes understanding.

In the context of our exercise, the variable \(m\) is used to represent an arbitrary integer in the statement. This abstraction to variables allows mathematicians to write proofs that are generally applicable rather than being limited to specific cases. It is essential to define your variables clearly and state their constraints; for example, specifying that \(m\) is an integer greater than 1 sets the stage for the ensuing logical deductions.
Inequalities in Integers
Inequalities are relations between two expressions that may not be equal, shown by symbols such as \(>\), \(<\), \(geq\), or \(leq\). In the realm of integers, these inequalities define the ordering of numbers. Recognizing and proving inequalities involve understanding properties of numbers, such as the fact that the reciprocal of a positive integer is always between zero and one.

In the provided exercise, we encounter an example of such an inequality: \(0 < \frac{1}{m} < 1\) for any integer \(m > 1\). When approaching inequalities with integers, ensure to draw on known properties such as divisibility, the behavior of negatives, and the reciprocal relationships. This foundational knowledge supports constructing convincing arguments concerning the relative size of integer-related expressions.

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Most popular questions from this chapter

Assume that \(k\) is a particular integer. a. Is \(-17\) an odd integer? b. Is 0 an even integer? c. Is \(2 k-1\) odd?

When expressions of the form \((x-r)(x-s)\) are multiplied out, a quadratic polynomial is obtained. For instance, \((x-2)(x-(-7))=(x-2)(x+7)=x^{2}+5 x-14 .\) \(H\) a. What can be said about the coefficients of the polynomial obtained by multiplying out \((x-r)(x-s)\) when both \(r\) and \(s\) are odd integers? when both \(r\) and \(s\) are even integers? when one of \(r\) and \(s\) is even and the other is odd? b. It follows from part (a) that \(x^{3}-1253 x+255\) cannot be written as a product of two polynomials with integer coefficients. Explain why this is so.

Observe that $$ \begin{aligned} 7524 &=7 \cdot 1000+5 \cdot 100+2 \cdot 10+4 \\ &=7(999+1)+5(99+1)+2(9+1)+4 \\ &=(7 \cdot 999+7)+(5 \cdot 99+5)+(2 \cdot 9+2)+4 \\ &=(7 \cdot 999+5 \cdot 99+2 \cdot 9)+(7+5+2+4) \\ &=(7 \cdot 111 \cdot 9+5 \cdot 11 \cdot 9+2 \cdot 9)+(7+5+2+4) \\ &=(7 \cdot 111+5 \cdot 11+2) \cdot 9+(7+5+2+4) \\ &=(\text { an integer divisible by } 9) \end{aligned} $$ \(\begin{aligned} 7524 &=7 \cdot 1000+5 \cdot 100+2 \cdot 10+4 \\\ &=7(999+1)+5(99+1)+2(9+1)+4 \\ &=(7.999+7)+(5 \cdot 99+5)+(2 \cdot 9+2)+4 \\\ &=(7 \cdot 999+5 \cdot 99+2 \cdot 9)+(7+5+2+4) \\ &=(7 \cdot 111 \cdot 9+5 \cdot 11 \cdot 9+2 \cdot 9)+(7+5+2+4) \\ &=(7 \cdot 111+5 \cdot 11+2) \cdot 9+(7+5+2+4) \\ &=(\text { an integer divisible by } 9) \\ &+(\text { the sum of the digits of } 7524) \end{aligned}\) Since the sum of the digits of 7524 is divisible by 9,7524 can be written as a sum of two integers each of which is divisible by 9 . It follows from exercise 15 that 7524 is divisible by \(9 .\) Generalize the argument given in this example to any nonnegative integer \(n\). In other words, prove that for any nonnegative integer \(n\), if the sum of the digits of \(n\) is divisible by 9 , then \(n\) is divisible by 9 ,

If \(m\) and \(n\) are perfect squares, then \(m+n+2 \sqrt{m n}\) is also a perfect square. Why?

Prove that for all positive integers \(a\) and \(b, a \mid b\) if, and only if, \(\operatorname{gcd}(a, b)=a\). (Note that to prove " \(A\) if, and only if, \(B, "\) you need to prove "if \(A\) then \(B\) " and "if \(B\) then \(A . "\) ")

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