/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Assume that \(m\) and \(n\) are ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Assume that \(m\) and \(n\) are both integers and that \(n \neq 0\). Explain why \((5 m+12 n) /(4 n)\) must be a rational number.

Short Answer

Expert verified
Given that \(m\) and \(n\) are integers and \(n \neq 0\), we can rewrite the expression \((5m + 12n) / (4n)\) as the sum of two ratios: \(\dfrac{5m}{4n} + 3\). Since both \(5m\) and \(4n\) are integers, \(\dfrac{5m}{4n}\) is a ratio of two integers, making it a rational number. Adding an integer (3) to a rational number results in another rational number. Therefore, \((5m + 12n) / (4n)\) is a rational number.

Step by step solution

01

Identify the numerator and denominator

In the given expression, \((5m + 12n) / (4n)\), the numerator is \(5m + 12n\), and the denominator is \(4n\).
02

Rewrite the numerator

We can rewrite the numerator as a sum of two terms: \(5m + 12n = 5m + 4(3n)\)
03

Factor out common terms

Now, we can factor out the common term of \(m\) and \(4n\) in the numerator: \(5m + 4(3n) = 5(m) + 4(3)n\)
04

Rewrite the expression as a ratio of integers

As \(m\) and \(n\) are both integers, the terms \(5m\) and \(12n\) are also integers (product of two integers is an integer). Now we can rewrite the expression as a sum of two ratios: \(\dfrac{5m + 12n}{4n} = \dfrac{5(m) + 4(3)n}{4n}\) Split the fraction into two parts: \(\dfrac{5(m) + 4(3)n}{4n} = \dfrac{5m}{4n} + \dfrac{12n}{4n}\)
05

Simplify the sum of the two ratios

We can now simplify the sum of the two ratios: \(\dfrac{5m}{4n} + \dfrac{12n}{4n} = \dfrac{5m}{4n} + 3\) Since both \(5m\) and \(4n\) are integers and \(n \neq 0\), \(\dfrac{5m}{4n}\) is a ratio of two integers, which makes it a rational number. Adding an integer (3) to a rational number results in another rational number. Hence, \((5m + 12n) / (4n)\) is a rational number.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Number Definition
A rational number is a number that can be expressed as the ratio of two integers, where the numerator is an integer and the denominator is a non-zero integer. This is represented as \frac{a}{b}, where \( a \) and \( b \) are integers and \( b eq 0 \). Rational numbers include natural numbers, whole numbers, and integers because they can all be expressed as a ratio where the denominator is 1. For example, the number 5 is a rational number because it can be written as \( \frac{5}{1} \). In the context of our original exercise, we looked at the expression \( (5m + 12n) /(4n) \) where both \( m \) and \( n \) are integers and \( n eq 0 \), ensuring that the number we're working with fits within the rational number definition.In everyday terms, when you have a slice of pie, the size of your slice compared to the whole pie can be described with a rational number. Just like you can cut a pie into a certain number of slices, numbers can be divided up into parts that can be described with integers, hence becoming rational numbers.
Integer Properties
Integers are the set of whole numbers and their opposites, including zero. The properties of integers are fundamental to understanding mathematical concepts like rational numbers. Here are a few critical properties to keep in mind:
  • Commutative Property: The order in which we add or multiply integers does not change the result (e.g., \( a + b = b + a \) and \( ab = ba \)).
  • Associative Property: When adding or multiplying integers, the way in which they are grouped does not affect the sum or product (e.g., \( (a + b) + c = a + (b + c) \)).
  • Distributive Property: Multiplying a number by a group of numbers added together is the same as doing each multiplication separately (e.g., \( a(b + c) = ab + ac \)).
  • Closure Property: The sum or product of any two integers is an integer, keeping us within the set of integers. This is central for rational numbers, as it guarantees a ratio of integers.
By understanding these properties, students recognize that operations on integers produce more integers, reinforcing the idea that rational numbers are ratios of integers. For example, in our exercise, the numerator \(5m + 12n\) is a sum of products of integers, which is also an integer, due to these integer properties, particularly the closure property.
Expression Simplification
Expression simplification refers to the process of making an algebraic expression as simple as possible. This typically involves combining like terms, factoring, expanding expressions, and canceling out terms where possible. Simplifying expressions helps us to more easily solve equations and understand the underlying structure of mathematical problems.For instance, in our exercise, we simplify the expression \( (5m + 12n) /(4n) \) by first expressing it as a sum of two ratios. Then we break it down further by simplifying these into \( \frac{5m}{4n} \) and \( \frac{12n}{4n} \), which can be reduced to \( \frac{5m}{4n} + 3 \), making the rational number more identifiable. This is a clear application of the distributive property, showing expression simplification in action. Simplifying expressions in this way leads us to a better understanding of what kind of number we are dealing with—confirming that our result is, indeed, a rational number.
Fraction Representation
Fraction representation is another way to describe the division of two numbers, where the numerator (top number) is divided by the denominator (bottom number). Every fraction is a rational number, provided that the denominator is not zero. It's essential to understand that fractions are not unique; for example, \( \frac{2}{4} \) and \( \frac{1}{2} \) represent the same rational number.When working with fractions, it's crucial to be able to simplify them and recognize equivalent fractions. This skill is helpful not just in pure mathematics, but in real life whenever you're dividing up something into parts, like cutting a cake into equal slices or measuring ingredients in cooking. In our exercise, after simplifying the numerator and splitting the fraction into two parts, we represent the expression as \( \frac{5m}{4n} + 3 \), effectively showing that a complex expression can be broken down into a simpler, more understandable fraction form. Recognizing fractions helps us to see that the numbers we work with every day, like \( \frac{3}{4} \) of a cup of flour or \( \frac{1}{2} \) of an hour for a meeting, are all examples of rational numbers.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The quotient-remainder theorem says not only that there exist quotients and remainders but also that the quotient and remainder of a division are unique. Prove the uniqueness. That is, prove that if \(a\) and \(d\) are integers with \(d>0\) and if \(q_{1}, r_{1}, q_{2}\), and \(r_{2}\) are integers such that $$ a=d q_{1}+r_{1} \quad \text { where } 0 \leq r_{1}

a. Use proof by contradiction to show that for any integer \(n\), it is impossible for \(n\) to equal both \(3 q_{1}+r_{1}\) and \(3 q_{2}+r_{2}\), where \(q_{1}, q_{2}, r_{1}\), and \(r_{2}\), are integers, \(0 \leq r_{1}<\) \(3,0 \leq r_{2}<3\), and \(r_{1} \neq r_{2}\). b. Use proof by contradiction, the quotient-remainder theorem, division into cases, and the result of part (a) to prove that for all integers \(n\), if \(n^{2}\) is divisible by 3 then \(n\) is divisible by 3 . c. Prove that \(\sqrt{3}\) is irrational.

a. Rewrite the following theorem in the form \(\forall \longrightarrow\) if then b. Fill in the blanks in the proof, Theorem: The sum of any even integer and any odd integer is odd. Proof: Suppose \(m\) is any even integer and \(n\) is (a) By definition of even, \(m=2 r\) for some \((b)\), and by definition of odd, \(n=2 s+1\) for some integer \(s\). By substitution and algebra, \(m+n=\underline{(c)}=2(r+s)+1 .\) Since \(r\) and \(s\) are both integers, so is their sum \(r+s\). Hence \(m+n\) has the form 2 . (some integer) \(+1\), and \(s o\) (d) by definition of odd.

Prove each of the statements in 23-29. For all real numbers \(x\), if \(x-\lfloor x\rfloor<1 / 2\) then \(\lfloor 2 x\rfloor=2\lfloor x\rfloor\).

Let \(p_{1}, p_{2}, p_{3}, \ldots\) be a list of all prime numbers in ascending order. Here is a table of the first six:$$ \begin{array}{|c|c|c|c|c|c|} \hline p_{1} & p_{2} & p_{3} & p_{4} & p_{5} & p_{6} \\ \hline 2 & 3 & 5 & 7 & 11 & 13 \\ \hline \end{array} $$a. For each \(i=1,2,3,4,5,6\), let \(N_{i}=p_{1} p_{2} \cdots p_{i}+1\). Calculate \(N_{1}, N_{2}, N_{3}, N_{4}, N_{5}\), and \(N_{6}\). b. For each \(i=1,2,3,4,5,6\), find the smallest prime number \(q_{i}\) such that \(q_{i}\) divides \(N_{i}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.