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In 8 and 9 a finite-state automaton is given by an annotated nextstate table. For each automaton: a. Find its states. b. Find its input symbols, c. Find its initial state. d. Find its accepting states. e. Draw its transition diagram. Next-State Table State \(\quad\)\begin{tabular}{l|ll} \(s_{1}\) & \(s_{1}\) & \(s_{2}\) \\ \(s_{2}\) & \(s_{2}\) & \(s_{3}\) \\ \(s_{3}\) & \(s_{3}\) & \(s_{0}\) \end{tabular}

Short Answer

Expert verified
The given finite-state automaton has 3 states: \(s_{1}\), \(s_{2}\), and \(s_{3}\); and 2 input symbols, \(a\) and \(b\). The initial state is \(s_{1}\), and the accepting state is \(s_{0}\). The transition diagram is as follows: ``` a +-----+ | | v | .-->s1---+->(s0) | | ^ b | v | | s2--+ | | | b | | v | (s0)<-+ ```

Step by step solution

01

Find the states

To find the states of the automaton, we should look at the table's rows. Each row in the table represents one state. So, we have 3 states in this automaton: \(s_{1}\), \(s_{2}\), and \(s_{3}\).
02

Find the input symbols

To find the input symbols, we should look at the table's columns. There are two columns in the table, which means the automaton has two input symbols. We can represent them with the letters \(a\) and \(b\).
03

Find the initial state

In most finite-state automaton problems, the initial state is the first state listed in the table, which in our case is \(s_{1}\). So, the initial state of the automaton is \(s_{1}\).
04

Find the accepting states

The accepting states are not provided in the table, but since there is a state \(s_{0}\) mentioned, which doesn't appear in the row headers, it is likely that this state is an accepting state. So, the accepting state of the automaton is \(s_{0}\).
05

Draw the transition diagram

Now that we have all the necessary information, we can draw the transition diagram for the given automaton. To do this, we will represent each state as a circle, labeled with the state name. We will then link the states with directed arcs following the transitions listed in the table. The initial state will have an incoming arrow without a source, and the accepting state will be represented by a double circle. The resulting transition diagram for the automaton is: ``` a +-----+ | | v | .-->s1---+->(s0) | | ^ b | v | | s2--+ | | | b | | v | (s0)<-+ ``` Where "s1" is the initial state, and "(s0)" is the accepting state.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

States in Automata
In a finite-state automaton, states are fundamental elements that represent different configurations or steps of the system. Think of states as positions in a board game. Each row in a next-state table corresponds to one specific state. For the given exercise, the states that were identified are \(s_{1}\), \(s_{2}\), and \(s_{3}\). These serve as the critical junctures that determine how the automaton processes input and transitions between different phases.

Each state can be imagined as a distinct situation where the automaton waits for an input to decide which state to move to next. It's essential to note that these states are not isolated; they interact with each other through transitions based on input symbols, helping the automaton to function dynamically.
Input Symbols in Automata
Input symbols in automata act like commands that tell the automaton where to go or what to do next. These are typically labeled using letters or numbers. In our context, the input symbols are identified based on the table's columns. According to the exercise, the automaton has two input symbols, which we can call \(a\) and \(b\).

This is akin to choosing between different paths in a decision tree; at each step (or state), the automaton examines the input symbol and decides the next state by looking at the designated column in the next-state table. This directed path is fundamental in determining the automaton's movement from one state to another.
Transition Diagrams
Transition diagrams, also known as state diagrams, visually illustrate how an automaton transitions from one state to another based on inputs. Each state is represented as a circle, with arrows showing possible transitions. The initial step is to draw the states (e.g., \(s_{1}\), \(s_{2}\), and \(s_{3}\)) as circles. Then, using information from the next-state table, you connect these states with directed arcs labeled with input symbols \((a, b)\).

For instance, in the given exercise, the diagram captures transitions like moving from \(s_{1}\) to \(s_{2}\) upon receiving input \(b\), or looping back to \(s_{1}\) with input \(a\). This graphical representation facilitates an easier understanding of how the automaton behaves with different inputs, acting as a roadmap for its operational flow.
Initial and Accepting States
The initial state is where the automaton begins its journey. It is the starting point and is usually represented in diagrams by an arrow with no originating source. In the exercise, the initial state was identified as \(s_{1}\) because it is the first listed in the next-state table.

Accepting states, on the other hand, are the configurations where the automaton successfully completes its operation under given conditions. These states are depicted as double circles in transition diagrams, indicating successful termination. The exercise inferred \(s_{0}\) as an accepting state based on its appearance in transitions but absence as a main header in the table.

Understanding these states is crucial as they define both the start and successful completion points of the automaton's process, shaping how inputs can lead to desired outcomes.

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Most popular questions from this chapter

Input alphabet \(=\\{0,1\\}\); Accepts the set of all strings that end in 10 .

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a. Let \(A\) be a finite-state automaton with input alphabet \(\Sigma\), and suppose \(L(A)\) is the language accepted by \(A\). The complement of \(L(A)\) is the set of all strings over \(\Sigma\) that are not in \(L(A)\). Show that the complement of a regular language is regular by proving the following: If \(L(A)\) is the language accepted by a finite-state automaton \(A\), then there is a finite-state automaton \(A^{\prime}\) that accepts the complement of \(L(A)\). b. Show that the intersection of any two regular languages is regular as follows: First prove that if \(L\left(A_{1}\right)\) and \(L\left(A_{2}\right)\) are languages accepted by automata \(A_{1}\) and \(A_{2}\), respectively, then there is an automaton \(A\) that accepts \(\left(L\left(A_{1}\right)\right)^{c} \cup\left(L\left(A_{2}\right)\right)^{c}\). Then use one of De Morgan's laws for sets, the double complement law for sets, and the result of part (a) to prove that there is an automaton that accepts \(L\left(A_{1}\right) \cap L\left(A_{2}\right)\).

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