/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 The lights in a classroom are co... [FREE SOLUTION] | 91Ó°ÊÓ

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The lights in a classroom are controlled by two switches: one at the back and one at the front of the room. Moving either switch to the opposite position turns the lights off if they are on and on if they are off. Assume the lights have been installed so that when both switches are in the down position, the lights are off. Design a circuit to control the switches.

Short Answer

Expert verified
Design a circuit using a 2-input XOR gate to control the lights in the classroom. Connect the inputs of the XOR gate to the two switches and the output to the lights. The XOR gate's output will be 1 (on) when the number of up switch positions is odd and 0 (off) when it's even, fulfilling the requirements of the problem.

Step by step solution

01

Circuit design using XOR gate

Design a circuit using an XOR gate to control the switches. To do this, use the following steps: 1. Represent the initial down position of the switches as 0 (off) and the up position as 1 (on). 2. Use a 2-input XOR gate. Connect the inputs of the XOR gate to the two switches. 3. Connect the output of the XOR gate to the lights. 4. Verify that the XOR gate's output fulfills the requirements of the problem. For example, if both switches are in the down position (0, 0), the XOR gate output is 0, and the lights are off. When one switch changes position (1, 0) or (0, 1), the XOR gate output is 1, and the lights turn on. When both switches change positions (1, 1), the XOR gate output returns to 0, and the lights turn off again. This circuit design using an XOR gate will ensure that the lights in the classroom can be controlled by the two switches according to the given conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Digital Logic Gates
Digital logic gates are the building blocks of digital circuits, similar to how bricks are to a building. They perform logical operations on one or more binary inputs to produce a single binary output. These gates are implemented in various devices such as computers, calculators, and other electronics where logical decision making is required. Among the most basic types of logic gates are AND, OR, NOT, NAND, NOR, XOR, and XNOR.

Each type of logic gate has its own truth table, which outlines the output for each possible combination of inputs. For instance, the XOR (exclusive OR) gate, which is central to the textbook exercise, produces an output of '1' only when the inputs are different. If both inputs are '0' or both are '1', the output is '0'. This unique property makes the XOR gate extremely useful in circuits that require a toggle functionality, such as the switch circuit described in the classroom lights exercise.
Circuit Analysis
Circuit analysis is the process of determining the voltages across, and the currents through, every component in an electrical network. In the context of digital circuits, analysis often involves understanding how digital logic gates are interconnected and how they influence each other to produce the desired output. It's important to note that in digital electronics, voltages and currents are translated into logical levels, typically represented by '0' (low) and '1' (high).

In analyzing the classroom light circuit, the role of the XOR gate is pivotal. By systematically evaluating the truth table of an XOR gate, we can confirm that the designed circuit will meet the conditions of the problem. For example, when one switch is up (1) and the other is down (0), the output of the gate and hence the light status, will indeed switch. Analysis of such circuits is crucial for predicting their behavior before actual implementation.
Boolean Algebra
Boolean algebra is a branch of mathematics that deals with variables that have two distinct values: true or false, often denoted as '1' or '0'. In the realm of digital electronics, Boolean algebra is applied to express and simplify the logic of digital circuits. Each logic gate corresponds to a particular Boolean operation.

In the exercise provided, the XOR gate represents the Boolean operation of exclusive disjunction. The algebraic expression for an XOR operation with two variables, A and B, is typically written as \( A \oplus B \). This can be expanded into a more detailed expression using AND, OR, and NOT operations as \( (A \cdot \overline{B}) + (\overline{A} \cdot B) \), which conveys the same logic. For instance, using Boolean algebra, we can derive simplified expressions to predict the outcome of complex circuits, or in the provided exercise, to understand why the XOR gate’s behavior matches the desired switching action for the classroom lights.

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Most popular questions from this chapter

Write the statements in 6-9 in symbolic form using the symbols \(\sim, \vee\), and \(\wedge\) and the indicated letters to represent component statements. Either Olga will go out for tennis or she will go out for track but not both. ( \(n=\) "Olga will go out for tennis," \(k=\) "Olga will go out for track")

In 38-41 (a) use the logical equivalences \(p \rightarrow q \equiv \sim p \vee q\) and \(p \leftrightarrow q \equiv(\sim p \vee q) \wedge(\sim q \vee p)\) to rewrite the given statement forms without using the symbol \(\rightarrow\) or \(\leftrightarrow\), and (b) use the logical equivalence \(p \vee q \equiv \sim(\sim p \wedge \sim q)\) to rewrite each statement form using only \(\wedge\) and \(\sim\). $$ (p \rightarrow(q \rightarrow r)) \leftrightarrow((p \wedge q) \rightarrow r) $$

Design a circuit to take input signals \(P, Q\), and \(R\) and output a 1 if, and only if, all three of \(P, Q\), and \(R\) have the same value.

If statement forms \(P\) and \(Q\) are logically equivalent, then \(P \leftrightarrow Q\) is a tautology. Conversely, if \(P \leftrightarrow Q\) is a tautology, then \(P\) and \(Q\) are logically equivalent. Use \(\leftrightarrow\) to convert each of the logical equivalences in 29-31 to a tautology. Then use a truth table to verify each tautology. $$ p \wedge(q \vee r) \equiv(p \wedge q) \vee(p \wedge r) $$

Use truth tables to show that the following forms of argument are invalid. a. \(\begin{array}{rlrl} & p \rightarrow q & \text { b. } & p & p \rightarrow q \\\ q & & & \sim p \\ & \therefore p & \therefore & \sim q \\ \text { (converse error) } & & \text { (inverse error) }\end{array}\)

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