Chapter 11: Problem 13
Construct a transition table for each FSM.
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Chapter 11: Problem 13
Construct a transition table for each FSM.
These are the key concepts you need to understand to accurately answer the question.
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Find the language generated by each grammar \(G=(N, T, P, \sigma)\) where: $$\begin{array}{l} N=\\{\sigma, \mathrm{A}, \mathrm{B}\\}, T=\\{\mathrm{a}, \mathrm{b}\\}, P=\\{\sigma \rightarrow \mathrm{a} \mathrm{Aa}, \mathrm{A} \rightarrow \mathrm{bBb}, \sigma \rightarrow \lambda, \mathrm{A} \rightarrow \mathrm{a}, \\ \mathrm{B} \rightarrow \mathrm{a}, \mathrm{B} \rightarrow \mathrm{b}\\} \end{array}$$
Define the language \(L\) of all binary representations of non-negative integers recursively.
A number in ALGOL (excluding the exponential form) is defined as follows: $$\langle\text { number }\rangle :=\langle\text { decimal number }\rangle :\langle\text { sign }\rangle\langle\text { decimal number }\rangle$$ \(\langle\text { decimal number }\rangle : :=\langle\text { unsigned integer }\rangle \langle\text { unsigned integer }\rangle |\) $$\langle\text {unsigned integer}\rangle. \langle\text {unsigned integer}\rangle$$ $$\langle\text { unsigned integer }\rangle : :=\langle\text { digit }\rangle :\langle\text { unsigned integer }\rangle\langle\text { digit }\rangle$$ $$\langle\text { digit }\rangle : := 0|1| 2|3| 4|5| 6|7| 8 | 9$$ $$\langle\operatorname{sign}\rangle : :=+|-$$ Use this grammar to answer Exercises \(60-67\). Determine if each is a valid ALGOL number. $$234$$
Use the grammar \(G=(N, T, P, \sigma),\) where \(N=\\{A, \sigma\\}, T=\\{a, b\\},\) and \(P=\\{\sigma \rightarrow a \sigma, \sigma \rightarrow a A, A \rightarrow b\\},\) to answer Exercises \(15-23\) . Draw a derivation tree for each word in \(L(G)\) . $$\mathrm{a}^{4} \mathrm{b}$$
Construct a NDFSA that accepts the language generated by the regular grammar \(G=(N, T, P, \sigma),\) where: $$\begin{aligned} &N=\\{\sigma, \mathrm{A}, \mathrm{B}, \mathrm{C}\\}, T=\\{\mathrm{a}, \mathrm{b}\\}, \text { and } P=\\{\sigma \rightarrow \mathrm{b} \sigma, \sigma \rightarrow \mathrm{a} \mathrm{A}, \mathrm{A} \rightarrow \mathrm{a} \mathrm{A}\\\ &\mathrm{A} \rightarrow \mathrm{bB}, \mathrm{B} \rightarrow \mathrm{aA}, \mathrm{B} \rightarrow \mathrm{bC}, \mathrm{C} \rightarrow \mathrm{aA}, \mathrm{C} \rightarrow \mathrm{b} \sigma, \mathrm{B} \rightarrow \mathrm{b}\\} \end{aligned}$$
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