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In how many ways can a \(2 \times n\) rectangular checkerboard be tiled using \(1 \times 2\) and \(2 \times 2\) pieces?

Short Answer

Expert verified
The number of ways to tile a 2x(n) board is given by the recurrence relation \( T(n) = T(n-1) + T(n-2)\), with initial conditions \( T(1) = 1 \) and \( T(2) = 2 \).

Step by step solution

01

- Understanding the Tiles

Tiles available are: a 1x2 tile, which occupies two vertical or two horizontal adjacent cells, and a 2x2 tile, which occupies four cells forming a square.
02

- Base Cases

Let's determine the number of ways to tile smaller boards to establish a pattern.For a 2x1 board, the only way to place tiles is to use one 1x2 tile placed vertically:\[T(1) = 1\]For a 2x2 board, there are two ways: using two horizontal 1x2 tiles or one 2x2 tile:\[T(2) = 2\]
03

- Develop a Recurrence Relation

Consider a 2x(n+1) board. The last column of the board can be filled in two possible ways:1. One 1x2 tile placed vertically, which reduces the problem to finding the number of ways to tile a 2x(n) board.2. One 2x2 tile placed at the bottom right corner, reducing the problem to tiling a 2x(n-1) board.Hence, we get:\[T(n+1) = T(n) + T(n-1)\]
04

- Solve Using Recurrence

Starting with the initial conditions and using the recurrence relation, we can find the number of ways for larger boards:\[T(1) = 1\]\[T(2) = 2\]\[T(3) = T(2) + T(1) = 2 + 1 = 3\]\[T(4) = T(3) + T(2) = 3 + 2 = 5\]Thus, to find the number of ways to tile a 2xn board, one needs to compute up to \(T(n)\) using the established recurrence relation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recurrence Relation
To solve the checkerboard tiling problem, understanding recurrence relations is crucial. A recurrence relation expresses terms in a sequence based on previous terms. In our problem, the recurrence relation helps us find the number of ways to tile a 2 × n board using smaller boards.
In mathematical terms, a recurrence relation might look like this:
\(T(n+1) = T(n) + T(n-1)\). This means that the number of ways to tile a 2 × (n + 1) board depends on the number of ways to tile a 2 × n board and a 2 × (n - 1) board.
By solving the recurrence, we can progressively calculate solutions for larger values of n by knowing the values of smaller n. This step-by-step approach is fundamental in solving tiling problems and is the backbone of connecting smaller problems to form a solution for a larger problem.
Checkerboard Tiling
The specific checkerboard tiling problem involves covering a 2 × n rectangular board using 1 × 2 and 2 × 2 tiles. These tiles fit together in unique ways based on their shapes:
The 1 × 2 tile, which can cover two adjacent cells either vertically or horizontally.
The 2 × 2 tile, which covers a square area of four cells.
The complexity arises in how these tiles can fit together without leaving gaps. For example, a 2 × 1 board can only be covered horizontally with a single 1 × 2 tile, whereas a 2 × 2 board has two possibilities: either using two horizontal 1 × 2 tiles or one 2 × 2 tile.
Understanding these basic tiling possibilities provides the foundation to tackle larger boards by building up from these small cases.
Dynamic Programming
Dynamic programming (DP) is a powerful technique often used to solve recurrence relations efficiently. It works by breaking down a complex problem into simpler subproblems and storing the results to avoid redundant calculations.
In the context of our tiling problem, dynamic programming helps us determine the number of ways to tile a board by using previously computed results. We start with small base cases (like 2 × 1 and 2 × 2), store their computed number of ways, and build upon them:
  • First, we solve for smaller values like T(1) and T(2).
  • Then, we use these results to iteratively compute larger values up to T(n).
By storing intermediate results, DP reduces the computation time significantly, making it possible to solve problems that would otherwise be infeasible due to the sheer number of possibilities.
Combinatorics
Combinatorics is a branch of mathematics concerning the counting, arrangement, and combination of objects. In tiling problems, combinatorial concepts help us understand and enumerate the different ways to arrange tiles on a board.
For the 2 × n board, we can use principles of combinatorics to count distinct tiling arrangements. Each tiling arrangement can be seen as a combination of smaller tile placements, and these combinations follow patterns described by our recurrence relation.
For instance, when we say there are 3 ways to tile a 2 × 3 board (T(3)), combinatorics ensures we account for every possible configuration. Understanding combinatorics allows us not just to find solutions but to ensure all solutions are counted, providing a comprehensive framework for solving and verifying tiling problems.

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Most popular questions from this chapter

How many elements are in \(A_{1} \cup A_{2}\) if there are 12 elements in \(A_{1}, 18\) elements in \(A_{2},\) and $$ \begin{array}{ll}{\text { a) } A_{1} \cap A_{2}=\emptyset ?} & {\text { b) }\left|A_{1} \cap A_{2}\right|=1 ?} \\ {\text { c) }\left|A_{1} \cap A_{2}\right|=6 ?} & {\text { d) } A_{1} \subseteq A_{2} ?}\end{array} $$

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