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A country uses as currency coins with values of 1 peso, 2 pesos, 5 pesos, and 10 pesos and bills with values of 5 pesos, 10 pesos, 20 pesos, 50 pesos, and 100 pesos. Find a recurrence relation for the number of ways to pay a bill of \(n\) pesos if the order in which the coins and bills are paid matters.

Short Answer

Expert verified
A(n) = A(n-1) + A(n-2) + A(n-5) + A(n-10) + A(n-20) + A(n-50) + A(n-100)

Step by step solution

01

- Define the problem

The task is to find the number of ways to pay a bill of n pesos using a specific set of coins and bills, where the order in which they are paid matters.
02

- Identify the variables

Let A(n) represent the number of ways to pay a bill of n pesos.
03

- Consider the base case

The base case occurs when n = 0. There is only one way to pay a bill of 0 pesos, which is by paying nothing. Thus, A(0) = 1.
04

- Choose one currency unit to pay first

To build a recurrence relation, start by choosing one of the currency units to pay first. There are coins of values 1, 2, 5, and 10 pesos, and bills of values 5, 10, 20, 50, and 100 pesos.
05

- Express A(n) in terms of smaller subproblems

For each unit, subtract the value of the unit from n and find A(n - unit). Sum these values to obtain A(n): \[ A(n) = A(n-1) + A(n-2) + A(n-5) + A(n-10) + A(n-20) + A(n-50) + A(n-100) \]
06

- Form the final recurrence relation

Combine all possibilities into one final recurrence relation: \[ A(n) = A(n-1) + A(n-2) + A(n-5) + A(n-10) + A(n-20) + A(n-50) + A(n-100) \] for n ≥ 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Mathematics
Discrete mathematics is the study of mathematical structures that are fundamentally discrete rather than continuous. This means no smooth transitions or infinitesimals. In the context of our problem, we deal with discrete units of currency: coins and bills.

Key points about discrete mathematics in our problem:
  • Deals with countable elements
  • The problem involves distinct denominations of coins and bills
  • We use recurrence relations to break the problem into simpler, discrete subproblems
Using discrete mathematics helps in performing operations over a set of distinct denominations to determine how many ways we can sum up to a given value. By treating the currency units as discrete items, we can use tools like recurrence relations to systematically compute the number of ways to make up the value.
This makes discrete mathematics an excellent tool for problems like these, where we want to count specific arrangements or combinations.
Understanding these basic principles makes it easier to grasp the concepts necessary to solve problems involving separated, distinct items like coins and bills.
Dynamic Programming
Dynamic programming is a powerful technique for solving problems by breaking them down into simpler subproblems and solving each subproblem only once.
In our exercise:

  • We define A(n) as the number of ways to pay a bill of n pesos
  • Each value of A(n) is built using the values of smaller terms (like A(n-1), A(n-2), etc.)
This saves computation time by storing results of subproblems to avoid redundant calculations.
Consider the recurrence relation established:


This means to calculate A(n), we use previously computed values:
Example: To pay a bill of 5 pesos, we consider the following possibilities:
  • Using 1 peso: A(4)
  • Using 2 pesos: A(3)
  • Using 5 pesos: A(0)
  • Each subproblem feeds into the next, allowing us to accumulate the total number of ways efficiently.

    In dynamic programming, this principle is essential:
    • Break problems into simpler subproblems
    • Compute solutions incrementally
    • Store intermediate results
    By adopting this strategy, we can solve complex problems like counting ways to make change much more efficiently than by brute force.
    Combinatorial Counting
    Combinatorial counting involves finding the number of ways to arrange or combine various elements according to certain rules.
    In our exercise, the task boils down to combinatorial counting since we want to find distinct ways to sum up to a certain value using various denominations.
    • Each unique arrangement of coins and bills is a 'way' to make up the total
    • Order matters in each arrangement
    • We systematically count these using recurrence relations
    To better grasp this, consider an example:
    Finding ways to pay 3 pesos:

    • Using coins: A(3) = A(2+1) + A(1+2) + A(1+1+1)
    • Using a combination of bill and coins: Not possible for 3 pesos with given bills
    Each combination counts as a different way, so we combine them to find the total number of arrangements.
    This approach ensures:
    • All possible combinations are considered
    • We don't miss any unique arrangement
    Combinatorial counting is fundamental in problems where the arrangement, selection, or combination of items is crucial. By systematically counting each possibility, we can efficiently solve complex counting problems like the one given.

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    Most popular questions from this chapter

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