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a) What is the generating function for \(\left\\{a_{k}\right\\},\) where \(a_{k}\) is the number of solutions of \(x_{1}+x_{2}+x_{3}=k\) when \(x_{1}, x_{2},\) and \(x_{3}\) are integers with \(x_{1} \geq 2,0 \leq x_{2} \leq 3,\) and \(2 \leq x_{3} \leq 5 ?\) b) Use your answer to part (a) to find \(a_{6}\)

Short Answer

Expert verified
The generating function for \(a_k\) is \( \frac{x^2}{1 - x} (1 + x + x^2 + x^3) (x^2 + x^3 + x^4 + x^5)\). To find \(a_6\), solve for the coefficient of \(x^6\).

Step by step solution

01

Find the generating function for each variable

First, let's identify the constraints for each variable and convert them into generating functions: For variable \(x_1\) with \(x_1 \geq 2\), the generating function is obtained by shifting \(x_1\) down by 2 units. This implies the generating function is \[x^2 + x^3 + x^4 + \cdots = x^2(1 + x + x^2 + \cdots) = \frac{x^2}{1 - x}\].
02

Find the generating function for x_2

For variable \(x_2\) with \(0 \leq x_2 \leq 3\), the generating function is limited to coefficients that go from \(0\) to \(3\). Therefore, the generating function is \[1 + x + x^2 + x^3.\]
03

Find the generating function for x_3

For variable \(x_3\) with \(2 \leq x_3 \leq 5\), the generating function is limited to coefficients from 2 to 5. Thus, \[x^2 + x^3 + x^4 + x^5.\]
04

Combine generating functions

Now combine the generating functions by multiplying them together: \[\frac{x^2}{1 - x} \times (1 + x + x^2 + x^3) \times (x^2 + x^3 + x^4 + x^5).\]
05

Simplify the combined function

To simplify, multiply the functions: \[\frac{x^2}{1 - x} (1 + x + x^2 + x^3) (x^2 + x^3 + x^4 + x^5).\]Combine and simplify further if needed.
06

Find coefficients assuming k = 6

To find the coefficient of \(x^6\) in the overall generating function, simplify and find the coefficient matching \(x^6\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Mathematics
Discrete mathematics is a branch of mathematics dealing with countable, distinct elements. Unlike continuous mathematics, where elements can vary smoothly, discrete mathematics focuses on individual elements that have a separate, distinct value.
Discrete mathematics includes topics like:
  • Logic
  • Set Theory
  • Combinatorics
  • Graph Theory
  • Algorithm Theory
Understanding these topics is vital when working with generating functions and combinatorial problems, as they allow us to break down complex issues into smaller, countable steps.
Integer Solutions
Solving for integer solutions involves finding all possible solutions that satisfy given equations or conditions where the solutions are integers. In the problem, we aim to solve the equation
\(x_1 + x_2 + x_3 = k\) where the integer variables \(x_1\), \(x_2\), and \(x_3\) adhere to defined constraints.
To tackle integer solutions efficiently:
  • Identify constraints for each variable
  • Convert these constraints into generating functions
  • Combine these generated functions to trace possible solutions that meet the criteria
These steps simplify the problem by turning it from an equation with numerous potential solutions into a manageable form.
Combinatorial Analysis
Combinatorial analysis refers to the study of counting, arrangement, and combination of objects. In this problem:
We use generating functions, which are an essential tool in combinatorial analysis. Generating functions transform sequences into power series, where coefficients represent elements of the original sequence.
To solve combinatorial problems:
  • Find the generating functions that represent each part of the problem
  • Combine these functions appropriately through multiplication or addition
  • Simplify the combined generating function to deduce coefficients representing the number of solutions
Using these principles helps in solving complex counting problems by breaking them down into more straightforward tasks.
Generating Function Simplification
Generating function simplification involves reducing the product of generating functions to a simpler form. Let's go through the problem's solution in detail:
For \(x_1\) with \(x_1 \geq 2\):
The generating function is \(\frac{x^2}{1 - x}\)
For \(x_2\) with \(0 \leq x_2 \leq 3\):
The generating function is \(1 + x + x^2 + x^3\)
For \(x_3\) with \(2 \leq x_3 \leq 5\):
The generating function is \(x^2 + x^3 + x^4 + x^5\)
Combining these functions, we get:
\(\frac{x^2}{1 - x} \times (1 + x + x^2 + x^3) \times (x^2 + x^3 + x^4 + x^5)\)
To simplify:
1. Multiply \(\frac{x^2}{1 - x}\) by \((1 + x + x^2 + x^3)\)
2. Multiply the result by \((x^2 + x^3 + x^4 + x^5)\)
The process reveals the coefficient of \(x^6\), answering the problem. Simplifying generating functions involves straightforward multiplication and collecting terms based on their degrees.

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Most popular questions from this chapter

In Exercises \(29-33,\) assume that \(f\) is an increasing function satisfying the recurrence relation \(f(n)=a f(n / b)+c n^{d},\) where \(a \geq 1, b\) is an integer greater than \(1,\) and \(c\) and \(d\) are positive real numbers. These exercises supply a proof of Theorem \(2 .\) Show that if \(a=b^{d}\) and \(n\) is a power of \(b,\) then \(f(n)=\) \(f(1) n^{d}+c n^{d} \log _{b} n .\)

Find a closed form for the exponential generating function for the sequence \(\left\\{a_{n}\right\\},\) where \(\begin{array}{ll}{\text { a) } a_{n}=2 .} & {\text { b) } a_{n}=(-1)^{n}} \\\ {\text { c) } a_{n}=3^{n} .} & {\text { d) } a_{n}=n+1} \\ {\text { e) } a_{n}=1 /(n+1)}\end{array}\)

a) Find a recurrence relation for the number of ways to completely cover a \(2 \times n\) checkerboard with \(1 \times 2\) dominoes. [Hint: Consider separately the coverings where the position in the top right corner of the checkerboard is covered by a domino positioned horizontally and where it is covered by a domino positioned vertically.] b) What are the initial conditions for the recurrence relation in part (a)? c) How many ways are there to completely cover a \(2 \times\) 17 checkerboard with \(1 \times 2\) dominoes?

Exercises \(38-45\) involve the Reve's puzzle, the variation of the Tower of Hanoi puzzle with four pegs and \(n\) disks. Before presenting these exercises, we describe the Frame-Stewart algorithm for moving the disks from peg 1 to peg 4 so that no disk is ever on top of a smaller one. This algorithm, given the number of disks \(n\) as input, depends on a choice of an integer \(k\) with \(1 \leq k \leq n .\) When there is only one disk, move it from peg 1 to peg 4 and stop. For \(n>1\) , the algorithm proceeds recursively, using these three steps. Recursively move the stack of the \(n-k\) smallest disks from peg 1 to peg \(2,\) using all four pegs. Next move the stack of the \(k\) largest disks from peg 1 to peg \(4,\) using the three-peg algorithm from the Tower of Hanoi puzzle without using the peg holding the \(n-k\) smallest disks. Finally, recursively move the smallest \(n-k\) disks to peg \(4,\) using all four pegs. Frame and Stewart showed that to produce the fewest moves using their algorithm, \(k\) should be chosen to be the smallest integer such that \(n\) does not exceed \(t_{k}=k(k+1) / 2,\) the \(k\) th triangular number, that is, \(t_{k-1}

Find \(\nabla a_{n}\) for the sequence \(\left\\{a_{n}\right\\},\) where $$ \begin{array}{ll}{\text { a) } a_{n}=4 .} & {\text { b) } a_{n}=2 n} \\\ {\text { c) } a_{n}=n^{2}} & {\text { d) } a_{n}=2^{n}}\end{array} $$

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