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How many different ways are there to choose a dozen donuts from the 21 varieties at a donut shop?

Short Answer

Expert verified
The number of ways to choose 12 donuts from 21 varieties is \( C(32, 12) \).

Step by step solution

01

Introduction to the Problem

We need to determine how many ways we can choose 12 donuts from 21 available varieties.
02

Understanding the Combination Concept

This problem can be solved using the concept of combinations with repetition. We are choosing 12 items (donuts) from 21 categories (varieties), where order doesn't matter, and repetition is allowed.
03

Applying the Combinations Formula with Repetition

The formula for combinations with repetition is given by \[ C(n + r - 1, r) \] where \(n\) is the number of varieties, and \(r\) is the number of donuts to be chosen.
04

Substituting the Values

Here \(n = 21\) and \(r = 12\). Substitute these values into the formula: \[ C(21 + 12 - 1, 12) = C(32, 12) \]
05

Calculating the Combination

Calculate the value of \[ C(32, 12) \] using the binomial coefficient formula: \[ C(n, r) = \frac{n!}{r!(n-r)!} \]. This gives us: \[ C(32, 12) = \frac{32!}{12! (32-12)!} = \frac{32!}{12! 20!} \]
06

Simplifying the Result

Perform the calculations: \[ C(32, 12) = \frac{32 \times 31 \times 30 \times ... \times 21}{12 \times 11 \times ... \times 1} \]. The result is a numerical value which is the number of different ways to choose 12 donuts from 21 varieties.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Mathematics
Discrete Mathematics is a branch of mathematics dealing with objects that can assume only distinct, separated values. It contrasts with continuous mathematics, which deals with objects that can vary smoothly.

Discrete mathematics includes topics such as:
  • Graph theory
  • Combinatorics
  • Number theory
  • Logic

In this exercise, we focus on combinatorics, which is about counting, arranging, and finding patterns in sets. Since we are choosing donuts, we need to count the different ways to select them, a classic problem within this field. Combinations with repetition, which allows us to select the same item multiple times, is a key method used here.
Binomial Coefficient
The binomial coefficient is a fundamental concept in combinatorics. It is used to count the number of ways to choose a subset of a certain size from a larger set without regard for the order of the items. The binomial coefficient is denoted as \( C(n, r) \), where \( n\) represents the total number of items to choose from, and \( r\) is the number of items to choose.

The formula for the binomial coefficient is: \[ C(n, r) = \frac{n!}{r!(n-r)!} \]. Here, \( n! \) is the factorial of \( n \), which means the product of all positive integers up to \( n \).

For instance, in this problem we needed to calculate \( C(32, 12) \), which represents the number of ways to choose 12 donuts from 32 (21 varieties with repetition). This formula helps in solving the problem accurately by providing the exact number of combinations possible.
Combinatorial Analysis
Combinatorial Analysis deals with counting, arranging, and grouping items. It is especially useful when dealing with problems where the arrangement or selection of objects is crucial.

In the given exercise, combinatorial analysis is essential because we need to determine how many possible ways there are to choose 12 donuts from 21 varieties, allowing for repetition. This specific scenario is addressed by combinations with repetition.

The formula \[ C(n + r - 1, r) \] is pivotal for such calculation:
  • \( n \) is the types of items (21 varieties)
  • \( r \) is the items to choose (12 donuts)
Substituting the values, we get \[ C(21+12-1, 12) = C(32, 12) \].

Therefore, combinatorial analysis provides the structured approach to get a precise solution by breaking down a complex selection process into understandable and calculable steps.

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