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Find the expansion of \((x+y+z)^{4}\)

Short Answer

Expert verified
(x+y+z)^4 = x^4 + y^4 + z^4 + 4x^3y + 4x^3z + 4y^3x + 4y^3z + 4z^3x + 4z^3y + 6x^2y^2 + 6x^2z^2 + 6y^2z^2 + 12x^2yz + 12xy^2z + 12xyz^2.

Step by step solution

01

Identify the Binomial Theorem for multinomials

To expand \( (x+y+z)^4 \) we use the multinomial theorem. The formula is given by: \[ (a_1 + a_2 + \cdots + a_m)^n = \sum_{k_1+k_2+\cdots+k_m=n} \frac{n!}{k_1! k_2! \cdots k_m!} a_1^{k_1} a_2^{k_2} \cdots a_m^{k_m} \] where \( k_1 + k_2 + \cdots + k_m = n \). Each term corresponds to the coefficients multiplied by the variables raised to the respective powers.
02

Determine the coefficients

For each term in the expansion of \( (x+y+z)^4 \), the power of each variable must sum to 4. We use the multinomial coefficient \( \frac{4!}{k_1! k_2! k_3!} \).
03

Compute the terms

We list all combinations where \( k_1 + k_2 + k_3 = 4 \). Compute the coefficients for each term as follows: \( \frac{4!}{k_1! k_2! k_3!} x^{k_1} y^{k_2} z^{k_3} \). Include all terms. For example, \( x^4, 4x^3y, 6x^2y^2, \cdots, z^4 \).
04

Write down all terms

Write each term by systematically plugging each combination into the multinomial coefficient formula: \[ (x+y+z)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4 + 4x^3z + 12x^2yz + 12xy^2z + 4y^3z + 6x^2z^2 + 12xyz^2 + 6y^2z^2 + 4xz^3 + 4yz^3 + z^4 \]. This includes all terms where the exponents of x, y, and z sum to 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial expansion
The binomial expansion is a way to express the power of a binomial expression, such as \((x+y)^n\), as a sum of terms involving the binomial coefficients. Each term in the expansion has the form \((\text{coefficient}) \, x^a \, y^b)\). The general formula for binomial expansion is: \[ (x + y)^n = \sum_{k=0}^{n} {n \choose k} \, x^{n-k} \, y^k \] where \({n \choose k}\) are the binomial coefficients. These coefficients can be found using Pascal's triangle or directly computed using: \[ {n \choose k} = \frac{n!}{k! (n-k)!} \]. This concept simplifies the process of expanding binomials and helps in finding coefficients and terms systematically.
Multinomial coefficients
Multinomial coefficients extend the idea of binomial coefficients to polynomials with more than two terms. In the expansion of an expression like \( (x + y + z)^n \, multinomial coefficients play a critical role. The general form is given as follows: \[ (a_1 + a_2 + \cdots + a_m)^n = \sum_{k_1+k_2+\cdots+k_m=n} \frac{n!}{k_1! \, k_2! \, \cdots \, k_m!} \, a_1^{k_1} \, a_2^{k_2} \, \cdots \, a_m^{k_m} \]. Each coefficient \frac{n!}{k_1! k_2! \- \cdots \! k_m!}\) represents the number of ways to distribute \(n \) items into \(m \) groups. This understanding is crucial when expanding polynomials with multiple terms, as it helps determine the coefficient for each term in the expansion.
Combinatorics
Combinatorics is the branch of mathematics dealing with combinations and permutations of objects. It is fundamental to understanding binomial and multinomial expansions. Key concepts include:
  • Permutations: Arrangements of objects in a specific order.
  • Combinations: Selections of objects without regard to order.
  • Factorials: Denoted as \(n!\), representing the product of all positive integers up to \(n\).
In the context of multinomial expansion, combinatorics helps in determining the different ways terms can be formed, ensuring all terms where the sum of the exponents equals \(n\) are included. This systematic approach is essential to correctly expand polynomial expressions involving multiple variables.
Polynomial expansion
Polynomial expansion refers to expressing a polynomial raised to a certain power as a sum of terms. For instance, to expand \( (x + y + z)^4\), follow these steps:
  • Apply the multinomial theorem: \[ (a_1 + a_2 + \cdots + a_m)^n = \sum_{k_1+k_2+\cdots+k_m=n} \frac{n!}{k_1! \, k_2! \cdots \! k_m!} \, a_1^{k_1} \, a_2^{k_2} \cdots a_m^{k_m} \]
  • Identify all combinations where the sum of the exponents equals the power (\(n\)). For \( (x + y + z)^4\), these need to sum up to 4.
  • Use multinomial coefficients to find the coefficients of each term.
  • Write down all terms: \[ (x + y + z)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4 + 4x^3z + 12x^2yz + 12xy^2z + 4y^3z + 6x^2z^2 + 12xyz^2 + 6y^2z^2 + 4xz^3 + 4yz^3 + z^4 \].
This approach ensures all parts of the polynomial are accounted for and expanded correctly.

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Most popular questions from this chapter

A professor packs her collection of 40 issues of a mathematics journal in four boxes with 10 issues per box. How many ways can she distribute the journals if a) each box is numbered, so that they are distinguishable? b) the boxes are identical, so that they cannot be distinguished?

In how many ways can a dozen books be placed on four distinguishable shelves a) if the books are indistinguishable copies of the same title? b) if no two books are the same, and the positions of the books on the shelves matter? [Hint: Break this into 12 tasks, placing each book separately. Start with the sequence \(1,2,3,4\) to represent the shelves. Represent the books by \(b_{i}, i=1,2, \ldots, 12 .\) Place \(b_{1}\) to the right of one of the terms in \(1,2,3,4 .\) Then successively place \(b_{2}, b_{3}, \ldots,\) and \(b_{12} . ]\)

Use the binomial theorem to expand \(\left(3 x^{4}-2 y^{3}\right)^{5}\) into a sum of terms of the form \(c x^{a} y^{b},\) where \(c\) is a real number and \(a\) and \(b\) are nonnegative integers.

Show that if \(n\) and \(k\) are integers with \(1 \leq k \leq n,\) then \(\left(\begin{array}{l}{n} \\ {k}\end{array}\right) \leq n^{k} / 2^{k-1}\)

A croissant shop has plain croissants, cherry croissants, chocolate croissants, almond croissants, apple croissants, and broccoli croissants. How many ways are there to choose a) a dozen croissants? b) three dozen croissants? c) two dozen croissants with at least two of each kind? d) two dozen croissants with no more than two broccoli croissants? e) two dozen croissants with at least five chocolate croissants and at least three almond croissants? f ) two dozen croissants with at least one plain croissant, at least two cherry croissants, at least three chocolate croissants, at least one almond croissant, at least two apple croissants, and no more than three broccoli croissants?

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