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Decrypt these messages encrypted using the shift cipher \(f(p)=(p+10) \bmod 26 .\) a) CEBBOXNOB XYG b) LO WIPBSOXN c) DSWO PYB PEX

Short Answer

Expert verified
a) SURROUND NOW b) BE MY FRIEND c) TIME FOR FUN

Step by step solution

01

Understand the Shift Cipher

In this problem, the shift cipher is defined by the function \( f(p) = (p + 10) \bmod 26 \). To decrypt a message, calculate the inverse shift: \( f^{-1}(c) = (c - 10) \bmod 26 \), where \( c \) is the encrypted character and \( p \) is the original character.
02

Create the Decryption Function

Since the encryption function is a Caesar cipher with a shift of 10 to the right, decryption will shift each letter 10 positions to the left in the alphabet. If the result is negative, add 26 to get back into the alphabet range.
03

Decrypt Each Character in Message a

Take each letter in 'CEBBOXNOB XYG' and shift it left by 10 positions: C (shifted by 10) = SE (shifted by 10) = UB (shifted by 10) = RB (shifted by 10) = RO (shifted by 10) = EX (shifted by 10) = NN (shifted by 10) = DO (shifted by 10) = EB (shifted by 10) = RFor the space, leave it as is.X (shifted by 10) = NY (shifted by 10) = OG (shifted by 10) = WResulting in: 'SURROUND NO W'.
04

Decrypt Each Character in Message b

Take each letter in 'LO WIPBSOXN' and shift it left by 10 positions: L (shifted by 10) = BO (shifted by 10) = E For the space, leave it as is.W (shifted by 10) = MI (shifted by 10) = YP (shifted by 10) = FB (shifted by 10) = RS (shifted by 10) = IO (shifted by 10) = EX (shifted by 10) = NN (shifted by 10) = DResulting in: 'BE MY FRIEND'.
05

Decrypt Each Character in Message c

Take each letter in 'DSWO PYB PEX' and shift it left by 10 positions: D (shifted by 10) = TS (shifted by 10) = IW (shifted by 10) = MO (shifted by 10) = EFor the space, leave it as is.P (shifted by 10) = FY (shifted by 10) = OB (shifted by 10) = RFor the space, leave it as is.P (shifted by 10) = FE (shifted by 10) = UX (shifted by 10) = NResulting in: 'TIME FOR FUN'.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Caesar Cipher
The Caesar cipher is a well-known cryptographic technique named after Julius Caesar, who reportedly used it in his private correspondence. This cipher is a type of substitution cipher where each letter in the plaintext is shifted a certain number of places down or up the alphabet. For example, with a shift of 1, A becomes B, B becomes C, and so on, wrapping around to the start of the alphabet if necessary.
In the given exercise, the shift is 10, meaning each letter in the plaintext is replaced by the letter 10 positions ahead. Decrypting such a message involves shifting each letter back by 10 positions.
Caesar ciphers are simplistic, making them easy to break with modern computational techniques, but they serve as an excellent introduction to the world of cryptography and encryption.
Modular Arithmetic
Modular arithmetic is a system of arithmetic for integers, where numbers 'wrap around' upon reaching a certain value—the modulus. Think of it like the numbers on a clock: after 12 comes 1 again.
For the Caesar cipher, modular arithmetic is used to ensure that shifting letters wraps around at 'Z' to 'A'. The modulus here is 26, the number of letters in the alphabet.
If shifting a letter left by 10 moves it out of the alphabet range (like 'A' shifting to a non-existent '-9'), modular arithmetic ensures it wraps around correctly. Mathematically, it's represented as \( (p + k) \bmod 26 \) for encryption and \( (c - k) \bmod 26 \) for decryption, where \( p \) and \( c \) are plaintext and ciphertext letters, respectively, and \( k \) is the shift.
This wrapping effect is key to the cipher's functionality and ensures all results stay within the bounds of the alphabet.
Cryptography
Cryptography is the practice and study of techniques for secure communication. Originating from Greek words meaning 'hidden writing', cryptography has evolved significantly from simple techniques like the Caesar cipher to complex algorithms used in digital security today.
Modern cryptography involves various fields, including mathematics, computer science, and electrical engineering. It secures data from unauthorized access and ensures privacy and integrity.
The Caesar cipher is an example of classical cryptography, providing a foundational understanding of encryption and decryption processes. Classical ciphers like these illustrate the basic principles of shifting and substitution, crucial for grasping more advanced cryptographic methods.
Today's cryptographic techniques build on these basic principles but incorporate complex algorithms to secure data in a digital age, protecting everything from personal messages to financial transactions and critical infrastructure.

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Most popular questions from this chapter

The Vigenère cipher is a block cipher, with a key that is a string of letters with numerical equivalents \(k_{1} k_{2} \ldots k_{m},\) where \(k_{i} \in \mathbf{Z}_{26}\) for \(i=1,2, \ldots, m .\) Suppose that the numerical equivalents of the letters of a plaintext block are \(p_{1} p_{2} \ldots p_{m} .\) The corresponding numerical ciphertext block is \(\left(p_{1}+k_{1}\right)\) mod 26 \(\left(p_{2}+k_{2}\right) \bmod 26 \ldots\left(p_{m}+k_{m}\right)\) mod \(26 .\) Finally, we translate back to letters. For example, suppose that the key string is RED, with numerical equivalents \(1743 .\) Then, the plaintext ORANGE, with numerical equivalents \(141700130604,\) is encrypted by first splitting it into two blocks 141700 and 13 \(0604 .\) Then, in each block we shift the first letter by 17 , the second by \(4,\) and the third by \(3 .\) We obtain 52103 and 0410 \(07 .\) The cipherext is FVDEKH. Express the Vigenère cipher as a cryptosystem.

Prove that the set of positive rational numbers is countable by showing that the function \(K\) is a one-to- one correspondence between the set of positive rational numbers and the set of positive integers if \(K(m / n)=p_{1}^{2 a_{1}} p_{2}^{2 a_{2}} \cdots \cdots p_{s}^{2 a_{s}} q_{1}^{2 b_{1}-1} q_{2}^{2 b_{2}-1} \ldots \cdots q_{t}^{2 b_{t}-1}\) where gcd \((m, n)=1\) and the prime-power factorizations of \(m\) and \(n\) are \(m=p_{1}^{a_{1}} p_{2}^{a_{2}} \cdots \cdot p_{s}^{a_{s}}\) and \(n=q_{1}^{b_{1}} q_{2}^{b_{2}} \cdots q_{t}^{b_{t}}\)

Find each of these values. a) \((-133 \bmod 23+261 \bmod 23) \bmod 23\) b) \((457 \bmod 23 \cdot 182 \bmod 23) \bmod 23\)

Find an inverse of \(a\) modulo \(m\) for each of these pairs of relatively prime integers using the method followed in Example \(2 .\) a) \(a=4, m=9\) b) \(a=19, m=141\) c) \(a=55, m=89\) d) \(a=89, m=232\)

\(\begin{array}{ll}{\text { Find the Cantor expansions of }} \\ {\text { a) } 2 .} & {\text { b) } 7} \\ {\text { c) } 19 .} & {\text { d) } 87} \\ {\text { e) } 1000 .} & {\text { f) } 1,000,000}\end{array}\)

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