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Prove that if \(n\) and \(b\) are positive integers with \(b \geq 2\) the base \(b\) representation of \(n\) has \(\left\lfloor\log _{b} n\right\rfloor+ 1\) digits.

Short Answer

Expert verified
The base \(\b\) representation of \(\) has \(\floor{\log_{b} n} + 1\) digits.

Step by step solution

01

- Understand the Logarithm in Base b

Recall that for a number n, the logarithm base b, \(\ \log_{b} n\ \), tells us the power to which the base b must be raised to get n.
02

- Express n in terms of b

We can express n as \( = b^k\) where k is the logarithm base b of n. To find the number of digits, we need to find k such that \(\) is between \(\b^k\) and \(\b^{k+1}\).
03

- Define the Digits in Base b

A number with \(\) digits in base \(\b\) can be written as \( = b^{d-1}\) to \( = b^d - 1\), where \(\b^{d-1} \leq < b^d\).
04

- Apply the Floor Function

The floor function \(\floor{\log_{b} } \) gives us the highest integer less than or equal to \(\log_{b} n\). Since \( = b^d - 1\), its logarithm lies between \(\floor{\log_{b} }\) and \(\floor{\log_{b} (b^d)}\).
05

- Calculate the Digit Length

The number of digits d in base \(\b\) of \(\) will be \(\floor{\log_{b} n} + 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Logarithms
A logarithm is a powerful mathematical tool. It tells us what exponent (power) to raise a base number (b) to, in order to get another number (n). For example, \(\text{if } b = 2 \text{ and } n = 8 \)\text{then } \(\text{ log}_{2} 8 = 3 \) \text{ because } \(\text{2}^3 = 8\). Logarithms essentially help us transform multiplication into addition, and exponentiation into multiplication, making calculations easier. They are especially useful in computer science, biology, and finance. A key part of many problems involving logarithms is understanding their base. \( \text{In this context, the base } b \text{ is important because we are dealing with base b representation of a number} \).

The expression \(\text{ log}_{b} n \) tells us the exponent to which \(\text{ b } \) must be raised to obtain \( n.\) Mathematically speaking, \( \text{ log}_{b} n = k \) implies that \( b^k = n \). This understanding is crucial when we start talking about how many digits a number \( n \) will have in a different base \( (b). \)
The Floor Function
The floor function, denoted as \(\text{ \lfloor x \rfloor \)}, is used to round down a real number \(x \) to the nearest integer less than or equal to \(x \). In simpler terms,\ it chops off the decimal part of the number, leaving only the integer part. For example, \( \text{ \lfloor 3.7 \rfloor } = 3 \) and \( \text{ \lfloor 5.0 \rfloor } = 5 \). This function is very useful when dealing with logarithms because logarithms often result in non-integer values.

Using the floor function in the context of the problem, allows us to find the highest integer less than or equal to \(\text{ log}_{b} n \).
This is important when we want to define the number of digits of a number in a specific base since the exact number may not always be an integer. By using the floor function, you precisely determine the maximum integer which does not exceed your logarithmic result.

For example, if \(\text{ log}_{2} 10 = 3.321928 \), then \(\text{ \lfloor \log}_{2} 10 \rfloor = 3 \), because \(3.321928 \) gets rounded down to \(3. \).
Number of Digits in Base b Representation
To find out how many digits a number \(n \) will have in a different base \(b \), we can use logarithms and the floor function together. First, understand that a number \( n \) written in base \( b \) can be expressed as:
  • If \(n \) is exactly equal to some power of \( b, \) i.e., \( b^d, \) then it has \( d+1 \) digits.
  • If \(n \) falls between two powers of \( b, \) such as \( b^{d-1} \) and \( b^d, \) then the number of digits is \( d. \)

So, to generalize it, we use the following steps:
  • Calculate \( \text{ log}_{b} n \), which gives us \( k \).
  • Apply the floor function, \( \text{ \lfloor \log}_{b} n \rfloor,\) to get the highest integer \(d \).

The number of digits \(d \), is thus \( \text{ \lfloor \log}_{b} n \rfloor + 1.\) For instance, if you want to know how many digits the number \( 1000 \) has in base \( 10, \) you need to do the following:

Calculate \( \text{ log}_{10} 1000 = 3 \)--because \( 10^3 = 1000.\)

By applying the floor function, \( \text{ \lfloor 3 \rfloor = 3.\)

So, \(\text{ 1000 in base 10 has } 3 + 1 = 4 \text{ digits. } \)
This approach can be applied to any number in any base to find out the number of digits in that base.\

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Most popular questions from this chapter

In Exercises \(31-32\) suppose that Alice and Bob have these public keys and corresponding private keys: \(\left(n_{\text { Alice }}, e_{\text { Alice }}\right)=\) \((2867,7)=(61 \cdot 47,7), \quad d_{\text { Alice }}=1183\) and \(\left(n_{\text { Bob }}, e_{\text { Bob }}\right)=\) \((3127,21)=(59 \cdot 53,21), d_{\text { Bob }}=1149 .\) First express your answers without carrying out the calculations. Then, using a computational aid, if available, perform the calculation to get the numerical answers. Alice wants to send to Bob the message "BUY NOW" so that he knows that she sent it and so that only Bob can read it. What should she send to Bob, assuming she signs the message and then encrypts it using Bob's public key?

The first nine digits of the ISBN-10 of the European version of the fifth edition of this book are 0-07-119881. What is the check digit for that book?

Write out a table of discrete logarithms modulo 17 with respect to the primitive root \(3 .\)

Which positive integers less than 30 are relatively prime to 30\(?\)

Prove that the set of positive rational numbers is countable by showing that the function \(K\) is a one-to- one correspondence between the set of positive rational numbers and the set of positive integers if \(K(m / n)=p_{1}^{2 a_{1}} p_{2}^{2 a_{2}} \cdots \cdots p_{s}^{2 a_{s}} q_{1}^{2 b_{1}-1} q_{2}^{2 b_{2}-1} \ldots \cdots q_{t}^{2 b_{t}-1}\) where gcd \((m, n)=1\) and the prime-power factorizations of \(m\) and \(n\) are \(m=p_{1}^{a_{1}} p_{2}^{a_{2}} \cdots \cdot p_{s}^{a_{s}}\) and \(n=q_{1}^{b_{1}} q_{2}^{b_{2}} \cdots q_{t}^{b_{t}}\)

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