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What is the decryption function for an affine cipher if the encryption function is \(c=(15 p+13) \bmod 26 ?\)

Short Answer

Expert verified
The decryption function is \(p = (7c + 13) \mod 26\).

Step by step solution

01

- Understand the Affine Cipher

An affine cipher is defined by the encryption function: \[c = (ap + b) \mod m\]where \(a\) and \(b\) are constants, \(p\) is the plaintext, \(c\) is the ciphertext, and \(m\) is the size of the alphabet. For this problem, \(m = 26\) (the number of letters in the English alphabet).
02

- Identify Constants

From the given encryption function \(c = (15p + 13) \mod 26\), identify the constants:\(a = 15\), \(b = 13\).
03

- Find the Modular Inverse of a

The decryption function requires the modular inverse of \(a\) modulo \(m\). We need to find \(a^{-1}\) such that \[15a^{-1} \equiv 1 \mod 26\].Using the Extended Euclidean Algorithm, we get: \(x = 7\), so \(15^{-1} \equiv 7 \mod 26\).
04

- Construct the Decryption Function

The decryption function of an affine cipher is given by: \[p = a^{-1}(c - b) \mod m\].Substituting \(a^{-1} = 7\), \(b = 13\), and \(m = 26\), the decryption function is: \[p = 7(c - 13) \mod 26\].
05

- Simplify the Decryption Function

Simplify the function by expanding and taking the modulo:\[p = 7c - 91 \mod 26\].Since \(-91 \mod 26 \equiv 13\) (because \(-91 = -4 \cdot 26 + 13\)), the final decryption function is:\[p = (7c + 13) \mod 26\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Affine Cipher
The Affine Cipher is a type of substitution cipher where each letter in the plaintext is transformed to its corresponding letter in the ciphertext using a mathematical formula. The general form of the encryption function for the Affine Cipher is: \(c = (ap + b) \mod m\), where \(a\) and \(b\) are constants, \(p\) is the plaintext letter, \(c\) is the ciphertext letter, and \(m\) is the size of the alphabet. For example, if we are using the English alphabet, then \(m = 26\).
This transformation ensures that each letter of the plaintext maps to a distinct letter in the ciphertext, making it a simple yet effective encryption method. To decrypt the ciphertext back into the plaintext, specific steps involving modular arithmetic and inverse calculations are required.
It's important to note that for the cipher to work, \(a\) must be chosen such that it has a multiplicative inverse modulo \(m\), meaning \(a\) and \(m\) are coprime (i.e., they have no common divisors other than 1). This ensures that the transformation can be reversed efficiently.
Modular Arithmetic
Modular arithmetic is a system of arithmetic for integers, where numbers 'wrap around' upon reaching a certain value—the modulus. In the context of the Affine Cipher, modular arithmetic is critical because it helps to keep letter indices within the range of the alphabet.
When performing operations like addition, subtraction, multiplication, and finding the modular inverse, the results are taken modulo \(m\). For instance, in our example, we use modulo 26 because there are 26 letters in the English alphabet.
Key operations include:
  • Addition: \((a + b) \mod m\)
  • Subtraction: \((a - b) \mod m\)
  • Multiplication: \((a \cdot b) \mod m\)
  • Inverse: Finding a number \(a^{-1}\) such that \((a \cdot a^{-1}) \equiv 1 \mod m\)
This wrapping around behavior ensures that our results always stay within the bounds of our alphabet, simplifying calculations.
Extended Euclidean Algorithm
The Extended Euclidean Algorithm is an extension of the Euclidean Algorithm that not only finds the greatest common divisor (GCD) of two numbers but also finds coefficients that express the GCD as a linear combination of the two numbers.
This is particularly useful for finding the modular inverse, a critical step in the decryption process of the Affine Cipher. In our problem, we need to find \(15^{-1} \mod 26\). This involves solving the equation:
  • \((15a^{-1}) \equiv 1 \mod 26\)
By using the Extended Euclidean Algorithm, we determine that \(15^{-1} \equiv 7 \mod 26\). This means 7 is the modular inverse of 15 modulo 26.
The steps involved typically include using the Euclidean Algorithm to express the GCD as a combination of the two numbers and working backward to find the coefficients needed to reach the desired inverse.
Cryptanalysis
Cryptanalysis is the study of analyzing information systems to understand the hidden aspects of the systems. It is usually used to break the encryption and decrypt the information without knowing the encryption key. For the Affine Cipher, one common cryptanalysis attack is the brute-force attack, where all possible keys are tried. Given the need for \(a\) and \(m\) to be coprime, fewer valid keys are possible compared to other types of ciphers.
Cryptanalysts might also look for patterns or frequencies in the ciphertext. Since the Affine Cipher preserves the frequency of letters, analyzing the frequency of each letter in the ciphertext can provide clues.
In practical scenarios, Affine Ciphers are considered relatively weak due to the small key space and vulnerability to frequency analysis. Modern cryptography often employs more complex and secure methods.

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Most popular questions from this chapter

The Vigenère cipher is a block cipher, with a key that is a string of letters with numerical equivalents \(k_{1} k_{2} \ldots k_{m},\) where \(k_{i} \in \mathbf{Z}_{26}\) for \(i=1,2, \ldots, m .\) Suppose that the numerical equivalents of the letters of a plaintext block are \(p_{1} p_{2} \ldots p_{m} .\) The corresponding numerical ciphertext block is \(\left(p_{1}+k_{1}\right)\) mod 26 \(\left(p_{2}+k_{2}\right) \bmod 26 \ldots\left(p_{m}+k_{m}\right)\) mod \(26 .\) Finally, we translate back to letters. For example, suppose that the key string is RED, with numerical equivalents \(1743 .\) Then, the plaintext ORANGE, with numerical equivalents \(141700130604,\) is encrypted by first splitting it into two blocks 141700 and 13 \(0604 .\) Then, in each block we shift the first letter by 17 , the second by \(4,\) and the third by \(3 .\) We obtain 52103 and 0410 \(07 .\) The cipherext is FVDEKH. Express the Vigenère cipher as a cryptosystem.

Write an algorithm in pseudocode for generating a sequence of pseudorandom numbers using a linear congruential generator. The middle-square method for generating pseudorandom numbers begins with an \(n\) -digit integer. This number is squared, initial zeros are appended to ensure that the result has 2\(n\) digits, and its middle \(n\) digits are used to form the next number in the sequence. This process is repeated to generate additional terms.

Which memory locations are assigned by the hashing function \(h(k)=k \bmod 97\) to the records of insurance company customers with these Social Security numbers? $$ \begin{array}{ll}{\text { a) } 034567981} & {\text { b) } 183211232} \\\ {\text { c) } 220195744} & {\text { d) } 987255335}\end{array} $$

We describe a basic key exchange protocol using private key cryptography upon which more sophisticated protocols for key exchange are based. Encryption within the protocol is done using a private key cryptosystem (such as AES) that is considered secure. The protocol involves three parties, Alice and Bob, who wish to exchange a key, and a trusted third party Cathy. Assume that Alice has a secret key \(k\) alice that only she and Cathy know, and Bob has a secret key \(k_{\text { Bob }}\) which only he and Cathy know. The protocol has three steps: (i) Alice sends the trusted third party Cathy the message "request a shared key with Bob" encrypted using Alice's key \(k_{\text { Alice }}\) . (ii) Cathy sends back to Alice a key \(k_{\text { Alice Bob }},\) which she generates, encrypted using the key \(k_{\text { Alice }},\) followed by this same key \(k_{\text { Alice, Bob }},\) encrypted using Bob's key, \(k_{\text { Bob }}\) (iii) Alice sends to Bob the key \(k_{\text { Alice }, \mathrm{Bob}}\) encrypted using \(k_{\text { Bob }},\) known only to Bob and to Cathy. Explain why this protocol allows Alice and Bob to share the secret key \(k_{\text { Alice }, \text { Bob }},\) known only to them and to Cathy.

In Exercises \(24-27\) first express your answers without com- puting modular exponentiations. Then use a computational aid to complete these computations. What is the original message encrypted using the RSA system with \(n=43 \cdot 59\) and \(e=13\) if the encrypted message is 066719470671\(?\) (To decrypt, first find the decryption exponent \(d\) which is the inverse of \(e=13\) modulo \(42 \cdot 58 .\)

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