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Show that if \(A\) and \(B\) are sets with the same cardinality, then \(|A| \leq|B|\) and \(|B| \leq|A|\)

Short Answer

Expert verified
\[ |A| \leq |B| \text{ and } |B| \leq |A| \].

Step by step solution

01

Define Cardinality

Start by understanding that sets have cardinalities, which are measures of the 'number of elements' in the set. If sets \(A\) and \(B\) have the same cardinality, denoted \(|A| = |B|\), it means there is a bijective function (one-to-one and onto) between \(A\) and \(B\).
02

Prove \(|A| \leq |B|\)

To show \[|A| \leq |B|\], assume there exists a bijective function \[f \colon A \rightarrow B\]. If \[f\] is bijective, every element of \[A\] maps to a unique element of \[B\]. This implies \[|A| \leq |B|\].
03

Prove \(|B| \leq |A|\)

Similarly, to show \[|B| \leq |A|\], consider the inverse function \[/\f^{-1} \colon B \rightarrow A\] which exists because \[f\] is bijective. This shows that every element of \[B\] maps to a unique element of \[A\], and thus \[|B| \leq |A|\].
04

Conclude the Proof

Since we've shown both \[|A| \leq |B|\] and \[|B| \leq |A|\], it follows that the sets \[A\] and \[B\] have equal cardinalities, hence proving our initial claim.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bijective Functions
Understanding bijective functions is crucial to grasping the concept of set cardinality. A bijective function is a function that is both injective (one-to-one) and surjective (onto).

In simpler terms:
  • Injective means every element of set A maps to a unique element of set B (no duplicates in the mapping).
  • Surjective means every element of set B is covered by the mapping (every element in B is matched with an element in A).

When a function is bijective, it establishes a perfect 'pairing' between the elements of two sets. This one-to-one and onto relationship indicates that both sets have the same number of elements, or the same cardinality.
Cardinality Proof
Proving the cardinality between two sets often involves showing that there is a bijective function between them. Let’s break down this proof step-by-step:

1. Define Cardinality: Clearly understand what cardinality means. If \(\|A\| = \|B\|\), it means sets A and B have the same number of elements because there exists a bijective function between them.

2. Proving \(\|A\| \leq \|B\|\): Assume there is a bijective function \(f: A \to B\). This assumption implies every element in A maps to a unique element in B. Hence, \(\|A\| \leq \|B\|\).

3. Proving \(\|B\| \leq \|A\|\): Consider the inverse function \(f^{-1}: B \to A\), which exists because our original function \(f\) is bijective. This shows that every element in B maps to a unique element in A. Thus, \(\|B\| \leq \|A\|\).

By proving both \(\|A\| \leq \|B\|\) and \(\|B\| \leq \|A\|\), we conclude that the sets A and B have equal cardinalities.
Inverse Functions
An inverse function is a function that reverses the operations of the original function. If you have a function \(f: A \to B\), the inverse function \(f^{-1}: B \to A\) will map each element of B back to its corresponding element in A.

For the function \(f\) to have an inverse, it must be bijective:
  • If \(f\) is injective, each element in A maps to a unique element in B, meaning no element in B is 'left out'.
  • If \(f\) is surjective, every element in B is 'hit' by the mapping from A. This ensures that there are no unmapped elements in B.

When both these conditions are satisfied, and \(f\) is bijective, the inverse function \(f^{-1}\) can be defined. This property plays a key role in cardinality proofs since it allows us to construct a clear mapping in both directions between sets A and B.

Understanding inverse functions is fundamental for proving that two sets have the same cardinality, as it conclusively shows the one-to-one and onto relationships between the elements of the sets.

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Most popular questions from this chapter

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