/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Show that the sum, over the set ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that the sum, over the set of people at a party, of the number of people a person has shaken hands with, is even. Assume that no one shakes his or her own hand.

Short Answer

Expert verified
The sum of degrees is even because it equals twice the number of edges.

Step by step solution

01

Define the problem

Let the number of people at the party be denoted by n. Each person at the party shakes hands with a certain number of other people, but no one shakes their own hand.
02

Represent handshakes with a graph

Think of this scenario as a graph where each person at the party is a vertex and each handshake is an edge connecting two vertices. In this context, the number of people a person has shaken hands with corresponds to the degree of the vertex.
03

Write the sum of degrees

The task requires showing that the sum of the degrees of all vertices in the graph is even. This can be denoted as: \[ \text{Sum of degrees} = \text{degree}(v_1) + \text{degree}(v_2) + ... + \text{degree}(v_n) \]
04

Use handshaking lemma

According to the handshaking lemma in graph theory, the sum of the degrees of all vertices in a graph equals twice the number of edges. Denote the number of edges by E. Hence, \[ \text{Sum of degrees} = 2E \]
05

Conclude the result

Since the number of edges E is an integer, multiplying it by 2 always yields an even number. Therefore, the sum of the degrees is always even.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

handshaking lemma
The handshaking lemma is a fundamental concept in graph theory. It states that the sum of the degrees of all vertices in an undirected graph is equal to twice the number of edges in the graph. This is expressed by the formula: \[\text{{Sum of degrees}} = 2E \] where E is the number of edges.

The lemma gets its name from a real-life analogy. Imagine a party where each handshake represents an edge connecting two people (vertices). The total number of handshakes can be calculated by adding up all the handshakes of each person (sum of degrees). Since every handshake involves two people, the total number of edges is half the sum of all handshakes. Hence, the sum of degrees is twice the number of edges.
degree of a vertex
The degree of a vertex in a graph is the number of edges connected to that vertex. In simpler terms, it represents how many direct connections (or edges) a particular node (or vertex) has within the graph.

For example, consider a scenario where a person at a party shakes hands with others. Each handshake is an edge, and the degree of a person's vertex is the number of handshakes they engage in.
If John shakes hands with three people, his vertex degree is 3. If Susan shakes hands with five people, her vertex has a degree of 5.

The importance of understanding vertex degrees lies in analyzing the connectivity and structure of graphs.
  • Find isolated nodes: A vertex with a degree of 0 is isolated, meaning it has no connections.
  • Identify highly connected nodes: High-degree vertices indicate highly connected or central nodes in the graph.
  • Determine graph properties: Vertex degrees help in understanding other properties of the graph, like the handshaking lemma.
sum of degrees
The sum of degrees of all vertices in a graph is the total count of all the edges multiplied by 2. This follows directly from the handshaking lemma, which states \[\text{{Sum of degrees}} = 2E\], where E is the number of edges.

For instance, if you consider a graph representing a social network at a party, where vertices are people and edges are handshakes, the sum of degrees tells you about the total social interaction taking place. Since shaking hands is a mutual activity involving two people, every handshake (edge) contributes a degree to both vertices (people involved).

Understanding the sum of degrees is crucial because:
  • It confirms that graphs with multiple vertices and edges have an even sum of degrees.
  • It helps in network analysis and understanding connectivity.
  • It ensures that in any network, interactions (edges) are symmetric and accounted for properly.
This concept is particularly useful in problems like the one our exercise explores, where verifying that the sum of handshakes (degrees) is even is necessary to draw correct conclusions about the network structure.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the number of nonisomorphic simple graphs with seven vertices in which each vertex has degree two.

How many subgraphs with at least one vertex does \(K_{2}\) have?

For each course at a university, there may be one or more other courses that are its prerequisites. How can a graph be used to model these courses and which courses are prerequisites for which courses? Should edges be directed or undirected? Looking at the graph model, how can we find courses that do not have any prerequisites and how can we find courses that are not the prerequisite for any other courses?

Suppose that a connected bipartite planar simple graph has \(e\) edges and \(v\) vertices. Show that \(e \leq 2 v-4\) if \(v \geq 3\) .

In an old puzzle attributed to Alcuin of York \((735-804),\) a farmer needs to carry a wolf, a goat, and a cabbage across a river. The farmer only has a small boat, which can carry the farmer and only one object (an animal or a vegetable). He can cross the river repeatedly. However, if the farmer is on the other shore, the wolf will eat the goat, and, similarly, the goat will eat the cabbage. We can describe each state by listing what is on each shore. For example, we can use the pair \((F G, W C)\) for the state where the farmer and goat are on the first shore and the wolf and cabbage are on the other shore. [The symbol \(\emptyset\) is used when nothing is on a shore, so that \((F W G C, \emptyset)\) is the initial state. \(]\) a) Find all allowable states of the puzzle, where neither the wolf and the goat nor the goat and the cabbage are left on the same shore without the farmer. b) Construct a graph such that each vertex of this graph represents an allowable state and the vertices representing two allowable states are connected by an edge if it is possible to move from one state to the other using one trip of the boat. c) Explain why finding a path from the vertex representing \((F W G C, \emptyset)\) to the vertex representing \((\emptyset, F W G C)\) solves the puzzle. d) Find two different solutions of the puzzle, each using seven crossings. e) Suppose that the farmer must pay a toll of one dollar whenever he crosses the river with an animal. Which solution of the puzzle should the farmer use to pay the least total toll?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.