/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Find a counterexample, if possib... [FREE SOLUTION] | 91影视

91影视

Find a counterexample, if possible, to these universally quantified statements, where the domain for all variables consists of all integers. a) \(\forall x \forall y\left(x^{2}=y^{2} \rightarrow x=y\right)\) b) \(\forall x \exists y\left(y^{2}=x\right)\) c) \(\forall x \forall y(x y \geq x)\)

Short Answer

Expert verified
Counterexample for (a): \(x = 2\), \(y = -2\). Counterexample for (b): \(x = -1\). Counterexample for (c): \(x = 2\), \(y = 0\).

Step by step solution

01

Understanding the Statement in Part (a)

The statement is \(\forall x \forall y \(x^{2}=y^{2} \rightarrow x=y\)\). It claims that for all integers \(x\) and \(y\), if \(x^2 = y^2\), then \(x = y\). Let's find a counterexample to this.
02

Finding Counterexample for Part (a)

Consider \(x = 2\) and \(y = -2\). Clearly, \(2^2 = (-2)^2 \) but \(2 eq -2\). Hence, \(x^2 = y^2 \rightarrow x = y\) is not always true.
03

Understanding the Statement in Part (b)

The statement is \(\forall x \exists y\(y^{2}=x\)\). It claims that for every integer \(x\), there exists an integer \(y\) such that \(y^2 = x\). Let's find a counterexample.
04

Finding Counterexample for Part (b)

Consider \(x = -1\). There is no integer \(y\) such that \(y^2 = -1\). Therefore, this statement is false.
05

Understanding the Statement in Part (c)

The statement is \(\forall x \forall y (xy \geq x)\). It claims that for all integers \(x\) and \(y\), the product \(xy\) is greater than or equal to \(x\). Let's find a counterexample.
06

Finding Counterexample for Part (c)

Consider \(x = 2\) and \(y = 0\). The product \(2 \times 0 = 0 \), but \(0 < 2\). Therefore, this statement is false.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

counterexample
A counterexample is a particular case that refutes a universally quantified statement. In simple terms, it is an example that disproves a statement by showing that the statement does not hold true in that specific case. Consider the statement, \(\forall x \forall y \(x^2 = y^2 \rightarrow x = y\)\). To disprove this, we only need to find one pair of integers \((x, y)\) such that \((x^2 = y^2)\) but \((x eq y)\).

As seen in the solution, choosing \(x = 2\) and \(y = -2\), we find that \(2^2 = (-2)^2\) but \(2 eq -2\). Thus, this serves as a counterexample, showing the statement is not always true. Counterexamples are quite powerful in proving the non-universality of a statement and can help deepen understanding by highlighting exceptions.
integer domain
The integer domain refers to the set of all integers, which includes positive numbers, negative numbers, and zero \((..., -3, -2, -1, 0, 1, 2, 3, ...)\).

When working with universally quantified statements over the integer domain, every integer must satisfy the given condition for the statement to be true. For instance, in \(\forall x \forall y \(xy \geq x\)\), this requires that the product of any two integers \(x\) and \(y\) must be greater than or equal to \(x\).

However, as shown in the solution, there are integers within the domain that violate this condition, such as \(x = 2\) and \(y = 0\), leading to \(2 \times 0 = 0 < 2\). This counterexample shows that the statement is false over the integer domain.
logical statements
Logical statements are assertions that can either be true or false. They are formed using logical connectives such as \(\rightarrow\) (implies), \(\forall\) (for all), and \(\exists\) (there exists).

In the context of our exercise, the logical statement \(\forall x \forall y \(x^2 = y^2 \rightarrow x = y\)\) uses the \(\forall\) quantifier to imply that for every pair of integers \(x\) and \(y\), if \(x^2 = y^2\), then \(x\) must equal \(y\).

Like mathematical equations, logical statements are precise, and any generalized proof must hold true for all cases specified. Conversely, providing a single counterexample can disprove such a statement by demonstrating a scenario where the logical condition fails.
quantifiers
Quantifiers are symbols in logic that specify the quantity of specimens in the domain of discourse that satisfy an open formula. The two main types of quantifiers are: \(\forall\) (universal quantifier) and \(\exists\) (existential quantifier).

The universal quantifier \(\forall\) means 'for all' or 'for every.' For example, \(\forall x \forall y \(xy \geq x\)\) asserts that the inequality must hold for all possible integer values of \(x\) and \(y\).

The existential quantifier \(\exists\) means 'there exists.' For instance, \(\forall x \exists y \(y^2 = x\)\) claims that for every integer \(x\), there exists an integer \(y\) such that \(y^2 = x\).

However, as illustrated, considering \(x = -1\), there is no integer \(y\) such that \(y^2 = -1\), revealing the statement to be false. Understanding the role of these quantifiers is crucial in forming precise and meaningful logical statements.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For each of these arguments, explain which rules of inference are used for each step. a) 鈥淟inda, a student in this class, owns a red convertible. Everyone who owns a red convertible has gotten at least one speeding ticket. Therefore, someone in this class has gotten a speeding ticket.鈥 b) 鈥淓ach of five roommates, Melissa, Aaron, Ralph, Veneesha, and Keeshawn, has taken a course in discrete mathematics. Every student who has taken a course in discrete mathematics can take a course in algorithms. Therefore, all five roommates can take a course in algorithms next year.鈥 c) 鈥淎ll movies produced by John Sayles are wonder-ful. John Sayles produced a movie about coal miners. Therefore, there is a wonderful movie about coal miners.鈥 d) 鈥淭here is someone in this class who has been to France. Everyone who goes to France visits the Louvre. Therefore, someone in this class has visited the Louvre.鈥

Translate in two ways each of these statements into logical expressions using predicates, quantifiers, and logical connectives. First, let the domain consist of the students in your class and second, let it consist of all people. a) Someone in your class can speak Hindi. b) Everyone in your class is friendly. c) There is a person in your class who was not born in California. d) A student in your class has been in a movie. e) No student in your class has taken a course in logic programming.

Determine whether each of these arguments is valid. If an argument is correct, what rule of inference is being used? If it is not, what logical error occurs? a) If \(n\) is a real number such that \(n>1,\) then \(n^{2}>1\) Suppose that \(n^{2}>1 .\) Then \(n>1\) b) If \(n\) is a real number with \(n>3,\) then \(n^{2}>9\) . Suppose that \(n^{2} \leq 9 .\) Then \(n \leq 3\) . c) If \(n\) is a real number with \(n>2,\) then \(n^{2}>4\) . Suppose that \(n \leq 2 .\) Then \(n^{2} \leq 4 .\)

Determine whether \(\forall x(P(x) \leftrightarrow Q(x))\) and \(\forall x P(x) \leftrightarrow\) \(\forall x Q(x)\) are logically equivalent. Justify your answer.

Express the negation of each of these statements in terms of quantifiers without using the negation symbol. a) \(\forall x(x>1)\) b) \(\forall x(x \leq 2)\) \(\begin{array}{ll}\text { c) } & \exists x(x \geq 4)\end{array}\) d) \(\exists x(x<0)\) e) \(\forall x((x<-1) \vee(x>2))\) f) \(\exists x((x<4) \vee(x>7))\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.