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Prove that if \(n\) is an integer and \(3 n+2\) is even, then \(n\) is even using a) a proof by contraposition. b) a proof by contradiction.

Short Answer

Expert verified
By contraposition, if \(n\) is odd, then \(3n + 2\) is odd. By contradiction, \(n\) being odd makes \(3n + 2\) odd, a contradiction. Therefore, if \(3n + 2\) is even, \(n\) is even.

Step by step solution

01

Understanding the Problem

We need to prove that if \(n\) is an integer and \(3n + 2\) is even, then \(n\) is even. We will do this using two methods: proof by contraposition and proof by contradiction.
02

Proof by Contraposition - Step 1: Write the Contrapositive

The contrapositive of 'If \(3n + 2\) is even, then \(n\) is even' is 'If \(n\) is odd, then \(3n + 2\) is odd.' This is what we need to prove.
03

Proof by Contraposition - Step 2: Assume \(n\) is odd

Assume \( n = 2k + 1 \) for some integer \(k\), meaning \(n\) is odd.
04

Proof by Contraposition - Step 3: Show \(3n + 2\) is odd

Substitute \(n = 2k + 1\) into \(3n + 2\): \[ 3(2k + 1) + 2 = 6k + 3 + 2 = 6k + 5 \]. Since \(6k + 5\) is of the form \(2m + 1\), it is odd.
05

Proof by Contraposition - Conclusion

Since the contrapositive 'If \(n\) is odd, then \(3n + 2\) is odd' is true, the original statement 'If \(3n + 2\) is even, then \(n\) is even' must also be true.
06

Proof by Contradiction - Step 1: Assume the negation

Assume \(3n + 2\) is even, but \(n\) is odd. We will reach a contradiction.
07

Proof by Contradiction - Step 2: Express \(n\) as an odd number

Since \(n\) is odd, let \( n = 2k + 1 \) for some integer \(k\).
08

Proof by Contradiction - Step 3: Substitute and simplify

Substitute \(n = 2k + 1\) into \(3n + 2\): \[ 3(2k + 1) + 2 = 6k + 3 + 2 = 6k + 5 \].
09

Proof by Contradiction - Step 4: Analyze the result

Notice that \(6k + 5\) is odd. This contradicts the assumption that \(3n + 2\) is even.
10

Proof by Contradiction - Conclusion

Since assuming the negation leads to a contradiction, the original statement 'If \(3n + 2\) is even, then \(n\) is even' must be true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proof by Contraposition
Proof by contraposition is a powerful tool in discrete mathematics. Instead of proving a statement directly, we prove its contrapositive. For example, instead of proving 'if P then Q,' we prove 'if not Q then not P.' These statements are logically equivalent.
In the given exercise, we needed to prove 'if 3n + 2 is even, then n is even.'
We did this by proving the contrapositive: 'if n is odd, then 3n + 2 is odd.'
By assuming n is odd ( = 2k + 1), we showed that 3n + 2 equals 6k + 5, which is clearly odd.
Successfully proving the contrapositive ensures the original statement's truth. This method is often easier than direct proof because the contrapositive might be simpler to work with.
Proof by Contradiction
Proof by contradiction involves assuming the negation of the statement you want to prove and showing that this assumption leads to a logical contradiction.
For the problem 'if 3n + 2 is even, then n is even,' we assume the opposite: 3n + 2 is even, but n is odd.
Substituting n as an odd number ( = 2k + 1), we again find that 3n + 2 equals 6k + 5, which is odd.
Since this contradicts our initial assumption that 3n + 2 is even, our original statement must be true. This logical contradiction confirms the correctness of the statement.
Proof by contradiction is useful when direct proof or contraposition is difficult, and reaching a contradiction can be more straightforward.
Parity of Integers
Understanding the parity of integers (whether a number is even or odd) is crucial in many proofs.
An integer n is even if it can be expressed as n = 2k, where k is an integer. It is odd if it can be written as n = 2k + 1.
In the given exercise, knowing the definitions of even and odd helped us frame our assumptions and substitutions. For instance, assuming n is odd allowed us to express it as n = 2k + 1.
This knowledge also helped us recognize that 6k + 5 is odd since any expression of the form 2m + 1 is odd.
Understanding these basic concepts of parity enables us to break down and solve more complex mathematical problems efficiently.
Logical Reasoning
Logical reasoning is the backbone of mathematical proofs. It involves making statements and drawing conclusions based on definitions, assumptions, and previously proven results.
In our exercise, we used logical reasoning to understand that proving the contrapositive of our statement was equivalent to proving the statement itself.
Similarly, in proof by contradiction, we used logical steps to show that assuming the negation leads to a contradiction, thus verifying the original statement.
Logical reasoning includes understanding if-then statements, contrapositives, and the nature of evenness and oddness for integers. Using these principles methodically allows us to construct and understand proofs effectively.

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