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Determine whether these are valid arguments. a) If \(x\) is a positive real number, then \(x^{2}\) is a positive real number. Therefore, if \(a^{2}\) is positive, where \(a\) is a real number, then \(a\) is a positive real number. b) If \(x^{2} \neq 0,\) where \(x\) is a real number, then \(x \neq 0 .\) Let \(a\) be a real number with \(a^{2} \neq 0 ;\) then \(a \neq 0\)

Short Answer

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a) Invalid; b) Valid

Step by step solution

01

Analyze Argument (a)

Consider the given argument: If x is a positive real number, then x虏 is a positive real number. Therefore, if a虏 is positive and a is a real number, then a is a positive real number. To validate this argument, break it down into its logical components. The first statement is true because squaring any positive real number results in a positive real number. However, the conclusion is false. If a虏 is positive, a can be positive or negative. For example, both 2虏 = 4 and (-2)虏 = 4. Hence, the conclusion doesn't logically follow from the premises.
02

Analyze Argument (b)

Consider the argument: If x虏 鈮 0, where x is a real number, then x 鈮 0. Let a be a real number with a虏 鈮 0; then a 鈮 0. To validate this argument, break it down into its logical components. The premise states that the square of a real number is non-zero only if the number itself is non-zero, which is true. Therefore, if a虏 鈮 0, then a must be non-zero. This argument is logically valid as the conclusion follows directly from the premise.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Valid Arguments
When we discuss 'valid arguments' in logic, we refer to scenarios where the conclusion logically follows from the premises. In other words, if the premises are true, the conclusion must also be true.

Let's examine two logical arguments provided in the exercise:
  • Argument (a): If x is a positive real number, then x虏 is a positive real number. Therefore, if a虏 is positive and a is a real number, then a is a positive real number.
  • Argument (b): If x虏 鈮 0, where x is a real number, then x 鈮 0. Let a be a real number with a虏 鈮 0; then a 鈮 0.
For Argument (a), even though the first premise is true, the conclusion is false because a can be either positive or negative when a虏 is positive. Therefore, Argument (a) is invalid.

For Argument (b), the premises and the conclusion align flawlessly. If a虏 is non-zero, then 'a' must be non-zero too. Hence, Argument (b) is valid.
Logical Components
Logical arguments consist of different components such as premises and conclusions. The validity of an argument hinges on how these components interact.

Taking Argument (a) again, let's break it down: The premise is 'If x is a positive real number, then x虏 is a positive real number.' This is true since the square of any positive number remains positive. However, the conclusion 'if a虏 is positive, then a is positive' doesn't follow logically. Squaring a negative number also results in a positive number, thus the conclusion is false.

Breaking down Argument (b), the premise is 'if x虏 鈮 0, then x 鈮 0'. This holds as the square of zero is zero. If x虏 is not zero, then x itself can't be zero. The conclusion 'if a虏 鈮 0; then a 鈮 0' follows logically from the premises, making it a valid argument. Hence, understanding these logical components is key to determining the validity.
Real Numbers
Real numbers form the foundation of these logical arguments. Real numbers include all the numbers on the number line, including both positive and negative numbers, as well as zero.

In Argument (a), 'x' must be understood as a positive real number. Squaring a positive real number (x) results in another positive real number (x虏). However, saying that if 'a虏' is positive then 'a' must be positive is incorrect because 'a' can also be negative. For instance, 3 and -3 both squared give 9, a positive number, demonstrating that 'a虏' being positive doesn't confirm 'a' is positive.

In Argument (b), the premise relies on the property that squaring a real number results in either zero or a positive number. If 'a虏 鈮 0', 'a' must be non-zero as the square of zero is zero. This illustrates why understanding the nature of real numbers is critical for evaluating logical arguments effectively.

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Most popular questions from this chapter

Suppose that the domain of the propositional function \(P(x)\) consists of the integers \(1,2,3,4,\) and \(5 .\) Express these statements without using quantifiers, instead using only negations, disjunctions, and conjunctions. $$ \begin{array}{ll}{\text { a) } \quad \exists x P(x)} & {\text { b) } \forall x P(x)} \\ {\text { c) } \quad \neg \exists x P(x)} & {\text { d) } \neg \forall x P(x)}\end{array} $$ e) \(\quad \forall x((x \neq 3) \rightarrow P(x)) \vee \exists x \neg P(x)\)

Express each of these statements using quantifiers. Then form the negation of the statement so that no negation is to the left of a quantifier. Next, express the negation in simple English. (Do not simply use the phrase 鈥淚t is not the case that.鈥) a) Every student in this class has taken exactly two mathematics classes at this school. b) Someone has visited every country in the world except Libya. c) No one has climbed every mountain in the Himalayas. d) Every movie actor has either been in a movie with Kevin Bacon or has been in a movie with someone who has been in a movie with Kevin Bacon.

Let \(C(x)\) be the statement " \(x\) has a cat," let \(D(x)\) be the statement " \(x\) has a dog," and let \(F(x)\) be the statement "x has a ferret." Express each of these statements in terms of \(C(x), D(x), F(x),\) quantifiers, and logical connectives. Let the domain consist of all students in your class. a) A student in your class has a cat, a dog, and a ferret. b) All students in your class have a cat, a dog, or a ferret. c) Some student in your class has a cat and a ferret, but not a dog. d) No student in your class has a cat, a dog, and a ferret. e) For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.

Is this reasoning for finding the solutions of the equation \(\sqrt{2 x^{2}-1}=x\) correct? \((1) \sqrt{2 x^{2}-1}=x\) is given; (2) \(2 x^{2}-1=x^{2},\) obtained by squaring both sides of \((1)\) (3) \(x^{2}-1=0,\) obtained by subtracting \(x^{2}\) from both sides of \((2) ;(4)(x-1)(x+1)=0\) , obtained by factoring the left-hand side of \(x^{2}-1 ;\) (5) \(x=1\) or \(x=-1\) which follows because \(a b=0\) implies that \(a=0\) or \(b=0\)

Show that the equivalence \(p \wedge \neg p \equiv \mathbf{F}\) can be derived using resolution together with the fact that a conditional statement with a false hypothesis is true. [Hint: Let \(q=\) \(r=\mathbf{F}\) in resolution.

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